Question Number 207249 by hardmath last updated on 10/May/24 $$\begin{cases}{\mathrm{x}^{\mathrm{2}} \:\:+\:\:\mathrm{2y}^{\mathrm{2}} \:\:+\:\:\mathrm{xy}\:\:=\:\:\mathrm{37}}\\{\mathrm{y}^{\mathrm{2}} \:\:+\:\:\mathrm{2x}^{\mathrm{2}} \:\:+\:\:\mathrm{2xy}\:\:=\:\:\mathrm{26}}\end{cases}\:\:\:\:\mathrm{find}:\:\:\mathrm{x}^{\mathrm{2}} \:+\:\mathrm{y}^{\mathrm{2}} \:=\:? \\ $$ Answered by A5T last updated on 10/May/24…
Question Number 207250 by hardmath last updated on 10/May/24 $$\mathrm{If}\:\:\:\mathrm{2}^{\boldsymbol{\mathrm{a}}} \:=\:\mathrm{5}\:\:,\:\:\mathrm{3}^{\boldsymbol{\mathrm{b}}} \:=\:\mathrm{9}\:\:\mathrm{and}\:\:\mathrm{25}^{\boldsymbol{\mathrm{c}}} \:=\:\mathrm{8} \\ $$$$\mathrm{Find}:\:\:\mathrm{a}\centerdot\mathrm{b}\centerdot\mathrm{c}\:=\:? \\ $$ Answered by A5T last updated on 10/May/24 $${a}={log}_{\mathrm{2}}…
Question Number 207247 by hardmath last updated on 10/May/24 $$\mathrm{8}\:\:+\:\:\frac{\mathrm{18}}{\mathrm{2}\:\:+\:\:\frac{\mathrm{7}}{\mathrm{5}\:\:+\:\:\frac{\mathrm{2}}{\boldsymbol{\mathrm{x}}}}}\:\:\:=\:\:\:\mathrm{14}\:\:\:\:\:\mathrm{find}:\:\:\:\boldsymbol{\mathrm{x}}\:=\:? \\ $$ Commented by Frix last updated on 10/May/24 $${x}=\mathrm{1} \\ $$ Answered by Rasheed.Sindhi…
Question Number 207243 by efronzo1 last updated on 10/May/24 Answered by mr W last updated on 10/May/24 $${s}={side}\:{length}\:{of}\:{square} \\ $$$$\left(\frac{{s}}{\mathrm{2}}\right)^{\mathrm{2}} ={s}×\mathrm{1} \\ $$$$\Rightarrow{s}=\mathrm{4} \\ $$$${square}'{s}\:{area}={s}^{\mathrm{2}}…
Question Number 207232 by MrGHK last updated on 10/May/24 $$ \\ $$$$\mathrm{Consider}\:\mathrm{the}\:\mathrm{relation}\:\mathrm{R}\:\mathrm{whose}\:\mathrm{graph}\:\mathrm{is}\:\mathrm{giveny} \\ $$$$\mathrm{b}\:\mathrm{R}\left(\right. \\ $$$$\left.\left(\mathrm{57}\right)\left(\mathrm{58}\right)\left(\mathrm{78}\right)\left(\mathrm{97}\right)\left(\mathrm{98}\right)\left(\mathrm{55}\right)\left(\mathrm{66}\right)\left(\mathrm{56}\right)\left(\mathrm{77}\right)\left(\mathrm{88}\right)\mathrm{99}\right)\mathrm{o} \\ $$$$\mathrm{n}\:\mathrm{the}\:\mathrm{set}\:\mathrm{S}\:\:\mathrm{56789}\:\mathrm{Find}\:\:\:\:\:\mathrm{1}.\:\mathrm{the}\:\mathrm{set}\:\mathrm{of}\:\mathrm{alla} \\ $$$$\mathrm{first}\left(\mathrm{lest}\right)\:\mathrm{elements}\:\mathrm{of}\:\left(\mathrm{SR}\right)\:\:\:\:\:\:\:\:\:\:\:\mathrm{2}.\:\mathrm{the}\:\mathrm{set}\:\mathrm{of}\:\mathrm{alla} \\ $$$$\mathrm{lst}\:\mathrm{element}\:\mathrm{of}\:\left(\mathrm{SR}\right)\:\:\:\:\:\:\:\:\:\:\:\mathrm{3}.\:\mathrm{the}\:\mathrm{set}\:\mathrm{of}\:\mathrm{all}\: \\ $$$$\mathrm{minimalelements}\:\mathrm{of}\:\left(\mathrm{SR}\right)\:\:\:\:\:\:\:\:\:\:\mathrm{4}.\:\mathrm{the}\:\mathrm{set}\:\mathrm{of}\:\mathrm{alla} \\…
Question Number 207233 by hardmath last updated on 10/May/24 $$\mathrm{1}.\:\:\:\underset{\boldsymbol{\mathrm{n}}\rightarrow\infty} {\mathrm{lim}}\:\left(\:\frac{\mathrm{n}\:−\:\mathrm{1}}{\mathrm{n}\:+\:\mathrm{2}}\:\right)^{\boldsymbol{\mathrm{n}}\:+\:\mathrm{3}} \:=\:\:? \\ $$$$ \\ $$$$\mathrm{2}.\:\:\:\underset{\boldsymbol{\mathrm{x}}\rightarrow\infty} {\mathrm{lim}}\:\left(\:\frac{\mathrm{5x}\:+\:\mathrm{6}}{\mathrm{2x}\:−\:\mathrm{9}}\:\right)^{\boldsymbol{\mathrm{x}}^{\mathrm{2}} } \:=\:\:? \\ $$$$ \\ $$$$\mathrm{3}.\:\:\:\underset{\boldsymbol{\mathrm{n}}\rightarrow\infty} {\mathrm{lim}}\:\left(\:\frac{\mathrm{n}\:+\:\mathrm{3}}{\mathrm{n}\:+\:\mathrm{1}}\:\right)^{\boldsymbol{\mathrm{n}}} \:=\:\:?…
Question Number 207212 by hardmath last updated on 09/May/24 $$\mathrm{arcsin}\:\left(\mathrm{sin}\:\mathrm{6}\right)\:=\:? \\ $$ Commented by A5T last updated on 09/May/24 $${sin}^{−\mathrm{1}} \left({sin}\mathrm{6}\right)=\mathrm{6} \\ $$ Answered by…
Question Number 207196 by lmcp1203 last updated on 09/May/24 $${if}\:\mathrm{2}\left({a}^{\mathrm{2}} −{b}^{\mathrm{2}} \right)^{\mathrm{5}\:} {it}\:{is}\:{a}\:{term}\:{of}\:{notable}\:{quotient}\:{of}\:\:\left(\left({a}+{b}\right)^{{n}} −\left({a}−{b}\right)^{{n}} \right)/\left({ab}+{b}^{\mathrm{2}} \right)\:\:{find}\:\:{n}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 207197 by hardmath last updated on 09/May/24 $$\mathrm{If}\:\:\:\mathrm{xy}\:=\:\frac{\mathrm{1}}{\mathrm{3}}\:\:\:,\:\:\:\mathrm{xz}\:=\:\frac{\mathrm{3}}{\mathrm{8}}\:\:\:\mathrm{and}\:\:\:\mathrm{yz}\:=\:\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\mathrm{For}\:\:\:\mathrm{x}\:,\:\mathrm{y}\:\mathrm{and}\:\mathrm{z}\:\:\:\mathrm{compare}. \\ $$ Answered by A5T last updated on 09/May/24 $${x}=\frac{\mathrm{1}}{\mathrm{3}{y}};{z}=\frac{\mathrm{1}}{\mathrm{2}{y}} \\ $$$${xz}=\frac{\mathrm{3}}{\mathrm{8}}\Rightarrow\frac{\mathrm{1}}{\mathrm{6}{y}^{\mathrm{2}} }=\frac{\mathrm{3}}{\mathrm{8}}\Rightarrow{y}^{\mathrm{2}}…
Question Number 207194 by sniper237 last updated on 09/May/24 $${Let}\:\:{x}\:=\:{cos}\frac{\pi}{\mathrm{9}}\: \\ $$$${Show}\:{that}\:\mathrm{8}{x}^{\mathrm{3}} −\mathrm{6}{x}−\mathrm{1}=\mathrm{0} \\ $$$${Deduce}\:{x}\:{is}\:{not}\:\:{rational}\: \\ $$ Answered by Berbere last updated on 09/May/24 $${cos}\left(\mathrm{3}.\frac{\pi}{\mathrm{9}}\right)={cos}\left(\frac{\pi}{\mathrm{3}}\right)=\frac{\mathrm{1}}{\mathrm{2}}…