Question Number 203704 by mnjuly1970 last updated on 26/Jan/24 $$ \\ $$$$\:\:\:\:\:{Q}:\:{In}\:{A}\overset{\Delta} {{B}C}\::\:\:\left(\:{AB}={AC}={b}\:\right)\:{and}\:\:\left(\:{BC}={a}\:\right).\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:{If}\:\:,\:\:{cos}\:\left({A}\:\right)=\:\frac{{a}^{\mathrm{2}} }{{b}^{\mathrm{2}} }\:,\:\:\:\:{then}\:{find}\:{the}\:{value}\:{of}\::\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\sqrt{\frac{{b}}{{a}}\:}\:=? \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\: \\ $$ Answered by…
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Question Number 203705 by SANOGO last updated on 26/Jan/24 $$\underset{{n}=\mathrm{0}} {\overset{+{oo}} {\sum}}\frac{\left(−\mathrm{1}\right)^{{n}} }{\left(\mathrm{2}{n}^{\mathrm{2}} −\mathrm{1}\right)^{\mathrm{2}} } \\ $$ Answered by witcher3 last updated on 26/Jan/24 $$\mathrm{decomposition}…
Question Number 203701 by Noorzai last updated on 26/Jan/24 Answered by mr W last updated on 26/Jan/24 $$\mathrm{0}<\frac{\mathrm{2}^{{x}} }{{x}!}=\frac{\mathrm{2}×\mathrm{2}×\mathrm{2}×\mathrm{2}×….×\mathrm{2}}{\mathrm{1}×\mathrm{2}×\mathrm{3}×\mathrm{4}×…×{x}}<\left(\frac{\mathrm{2}}{\mathrm{3}}\right)^{{x}} \\ $$$$\mathrm{0}<\underset{{x}\rightarrow\infty} {\mathrm{lim}}\frac{\mathrm{2}^{{x}} }{{x}!}<\underset{{x}\rightarrow\infty} {\mathrm{lim}}\left(\frac{\mathrm{2}}{\mathrm{3}}\right)^{{x}} =\mathrm{0}…
Question Number 203693 by Numsey last updated on 26/Jan/24 Answered by MM42 last updated on 26/Jan/24 $${I}=\int\sqrt{\mathrm{2}}{cos}\frac{{x}}{\mathrm{2}}{dx}=\mathrm{2}\sqrt{\mathrm{2}}{sin}\frac{{x}}{\mathrm{2}}\:+{c} \\ $$ Commented by Frix last updated on…
Question Number 203726 by mr W last updated on 27/Jan/24 Commented by mr W last updated on 26/Jan/24 $${solution}\:{to}\:{Q}#\mathrm{203636} \\ $$ Answered by mr W…
Question Number 203694 by Numsey last updated on 26/Jan/24 Answered by Calculusboy last updated on 26/Jan/24 $$\boldsymbol{{Solution}}:\:\boldsymbol{{by}}\:\boldsymbol{{sub}}\:\boldsymbol{{directly}},\boldsymbol{{we}}\:\boldsymbol{{get}}\:\frac{\mathrm{0}}{\mathrm{0}}\left(\boldsymbol{{indeterminant}}\right) \\ $$$$\boldsymbol{{let}}\:\boldsymbol{\Delta}=\boldsymbol{{li}}\underset{\boldsymbol{{x}}\rightarrow\mathrm{0}} {\boldsymbol{{m}}}\frac{\left(\mathrm{1}+\boldsymbol{{x}}\right)^{\mathrm{5}} }{\boldsymbol{{x}}^{\mathrm{2}} }−\boldsymbol{{li}}\underset{\boldsymbol{{x}}\rightarrow\mathrm{0}} {\boldsymbol{{m}}}\frac{\boldsymbol{{e}}^{\mathrm{5}\boldsymbol{{x}}} }{\boldsymbol{{x}}^{\mathrm{2}} }+\boldsymbol{{li}}\underset{\boldsymbol{{x}}\rightarrow\mathrm{0}}…
Question Number 203695 by Numsey last updated on 26/Jan/24 Commented by BaliramKumar last updated on 26/Jan/24 $$\mathrm{Step}\:\mathrm{III}\:\:\:\:\:\:\:\:\:\frac{\mathrm{1}}{\mathrm{4}\left(\mathrm{27}\right)}\left(\mathrm{1}.\mathrm{5}\right) \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 203688 by ajfour last updated on 26/Jan/24 Commented by ajfour last updated on 26/Jan/24 $${Repost}\:\:\:{Q}.\mathrm{203636}\: \\ $$ Commented by ajfour last updated on…
Question Number 203690 by yaslm last updated on 26/Jan/24 Answered by Frix last updated on 26/Jan/24 $$=\frac{\mathrm{1}}{\mathrm{3}}\int\frac{{x}+\mathrm{1}}{{x}^{\mathrm{2}} −{x}+\mathrm{1}}−\frac{\mathrm{1}}{{x}+\mathrm{1}}{dx} \\ $$$$\mathrm{Should}\:\mathrm{be}\:\mathrm{easy}\:\mathrm{now} \\ $$ Terms of Service…