Question Number 203625 by professorleiciano last updated on 23/Jan/24 Answered by esmaeil last updated on 23/Jan/24 $$\mathrm{1}+\frac{\left({sin}^{\mathrm{2}} {x}+{cos}^{\mathrm{2}} {x}\right)^{\mathrm{2}} −\mathrm{2}{sin}^{\mathrm{2}} {xcos}^{\mathrm{2}} {x}}{{sin}^{\mathrm{2}} {xcos}^{\mathrm{2}} {x}}=\mathrm{3}\rightarrow \\…
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Question Number 203576 by sonukgindia last updated on 22/Jan/24 Answered by mr W last updated on 22/Jan/24 Commented by mr W last updated on 22/Jan/24…
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Question Number 203605 by a.lgnaoui last updated on 22/Jan/24 $$\mathrm{Value}\:\mathrm{of}\:\boldsymbol{\mathrm{x}}? \\ $$ Commented by cortano12 last updated on 25/Jan/24 Commented by a.lgnaoui last updated on…
Question Number 203573 by sonukgindia last updated on 22/Jan/24 Answered by esmaeil last updated on 22/Jan/24 $$\int−{e}^{{cosx}} \left(\mathrm{1}−{cos}^{\mathrm{2}} {x}−{cosx}\right){dx} \\ $$$$\int−{e}^{{cosx}} \left({sin}^{\mathrm{2}} {x}−{cosx}\right){dx}= \\ $$$$\int−{e}^{{cosx}}…
Question Number 203568 by Mastermind last updated on 22/Jan/24 $$\mathrm{Reduce}\:\mathrm{a}\:\mathrm{differential}\:\mathrm{equation} \\ $$$$\mathrm{x}^{'''} \:+\:\mathrm{ax}^{''} \:+\:\mathrm{bx}^{'} \:+\:\mathrm{cx}\:=\:\mathrm{0}\:\left(\mathrm{where}\:\mathrm{a},\mathrm{b},\mathrm{c}\:\mathrm{are}\right. \\ $$$$\left.\mathrm{constants}\right)\:\mathrm{to}\:\mathrm{an}\:\mathrm{equivalent}\:\mathrm{system}\:\mathrm{of}\:\mathrm{first} \\ $$$$\mathrm{order}\:\mathrm{equation}. \\ $$$$\mathrm{x}_{\mathrm{1}} =\:\mathrm{x},\:\mathrm{x}_{\mathrm{2}} \:=\:\mathrm{x}^{'} ,\:\mathrm{x}_{\mathrm{3}} \:=\:\mathrm{x}^{''}…
Question Number 203569 by cherokeesay last updated on 22/Jan/24 Commented by a.lgnaoui last updated on 22/Jan/24 $$\mathrm{2}\left(\mathrm{a}+\mathrm{b}+\mathrm{c}+\mathrm{d}\right)=\mathrm{360} \\ $$$$\:\:\left(\mathrm{a}+\mathrm{b}+\mathrm{c}+\mathrm{d}\right)=\mathrm{180} \\ $$$$\:\:\left(\mathrm{a}+\mathrm{b}\right)=\mathrm{180}−\left(\mathrm{c}+\mathrm{d}\right) \\ $$$$ \\ $$$$\:\:\:\:\mathrm{tan}\:\left(\boldsymbol{\mathrm{a}}+\boldsymbol{\mathrm{b}}\right)=−\mathrm{tan}\:\left(\boldsymbol{\mathrm{c}}+\boldsymbol{\mathrm{d}}\right)…
Question Number 203602 by mr W last updated on 22/Jan/24 Answered by mr W last updated on 23/Jan/24 Commented by mr W last updated on…
Question Number 203570 by Frix last updated on 22/Jan/24 $$\mathrm{Suggested}\:\mathrm{solution}\:\mathrm{method}\:\mathrm{to} \\ $$$$\mathrm{question}\:\mathrm{203502} \\ $$$$ \\ $$$${z}\mathrm{e}^{{z}} =\mathrm{1} \\ $$$$\mathrm{Obviously}\:\mathrm{the}\:\mathrm{only}\:\mathrm{real}\:\mathrm{solution}\:\mathrm{is} \\ $$$${z}={W}\left(\mathrm{1}\right)\approx.\mathrm{567143290} \\ $$$$ \\ $$$${z}={a}+{b}\mathrm{i}\wedge{b}\neq\mathrm{0}…