Question Number 212618 by MrGaster last updated on 19/Oct/24 $$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\underset{{n}\rightarrow\mathrm{0}} {\mathrm{lim}}\left(\underset{{k}=\mathrm{1}} {\overset{{n}} {\prod}}\frac{{k}^{\mathrm{2}} +\mathrm{3}{k}+\mathrm{2}}{{k}^{\mathrm{2}} +\mathrm{2}{k}+\mathrm{1}}\right)^{\frac{\mathrm{1}}{{n}}} \\ $$ Commented by mehdee7396 last updated on…
Question Number 212615 by MrGaster last updated on 19/Oct/24 $$\mathrm{Verify}\:\mathrm{the}\:\mathrm{equation}:\mathrm{tan}\:{nx}=\underset{{k}=\mathrm{1}} {\overset{\left[\frac{{n}+\mathrm{1}}{\mathrm{2}}\right]} {\sum}}\left(−\mathrm{1}\right)^{{k}−\mathrm{1}} \begin{pmatrix}{{n}}\\{\mathrm{2}{k}−\mathrm{1}}\end{pmatrix}\:\mathrm{tan}^{\mathrm{2}{k}−\mathrm{1}} {x}/\underset{{k}=\mathrm{0}} {\overset{\left[\frac{{n}}{\mathrm{2}}\right]} {\sum}}\left(−\mathrm{1}\right)^{{k}} \begin{pmatrix}{{n}}\\{\mathrm{2}{k}}\end{pmatrix}\mathrm{tan}^{\mathrm{2}{k}} {x} \\ $$ Terms of Service Privacy Policy…
Question Number 212604 by klipto last updated on 18/Oct/24 $$\boldsymbol{\mathrm{draw}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{structural}}\:\boldsymbol{\mathrm{formula}}\:\boldsymbol{\mathrm{for}} \\ $$$$ \\ $$Spiro [2.2.2.5.8.6] compounds Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 212607 by RojaTaniya last updated on 18/Oct/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 212600 by MrGaster last updated on 18/Oct/24 $$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{certificate}: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\underset{{n}\rightarrow\infty} {\mathrm{lim}}\int_{\mathrm{0}} ^{\mathrm{1}} \frac{{n}}{\mathrm{1}+{n}^{\mathrm{2}} {x}^{\mathrm{2}} }{e}^{{x}^{\mathrm{3}} } {dx}=\frac{\pi}{\mathrm{2}}. \\ $$ Answered by…
Question Number 212601 by Spillover last updated on 18/Oct/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 212602 by Spillover last updated on 18/Oct/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 212598 by MATHEMATICSAM last updated on 18/Oct/24 $$\mathrm{Help}\:\mathrm{me}\:\mathrm{to}\:\mathrm{solve}\:\mathrm{pls} \\ $$$$\mathrm{Q}\:\mathrm{212576}\: \\ $$ Answered by A5T last updated on 18/Oct/24 $${Lemma}:\:\frac{{a}}{{b}}=\frac{{c}}{{d}}\Rightarrow\frac{{a}}{{b}}=\frac{{c}}{{d}}=\frac{{a}\underset{−} {+}{c}}{{b}\underset{−} {+}{d}} \\…
Question Number 212593 by mr W last updated on 18/Oct/24 Commented by mr W last updated on 18/Oct/24 $${a}\:{more}\:{general}\:{case}\:{from}\:{Q}\mathrm{212514} \\ $$ Answered by mr W…
Question Number 212595 by MrGaster last updated on 18/Oct/24 $$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\left(\frac{\mathrm{1}^{\mathrm{2}} }{{n}^{\mathrm{2}} +\mathrm{1}}+\frac{\mathrm{2}^{\mathrm{2}} }{{n}^{\mathrm{2}} +\mathrm{2}}+\frac{\mathrm{3}^{\mathrm{2}} }{{n}^{\mathrm{2}} +\mathrm{3}}+\ldots+\frac{{n}^{\mathrm{2}} }{{n}^{\mathrm{2}} +{n}}−\frac{{n}}{\mathrm{3}}\right)=? \\ $$ Answered by Berbere last…