Question Number 201166 by mnjuly1970 last updated on 01/Dec/23 Answered by mr W last updated on 01/Dec/23 $$\frac{{ah}}{\mathrm{2}}=\mathrm{4} \\ $$$$\Rightarrow{h}=\frac{\mathrm{2}×\mathrm{4}}{\:\sqrt{\mathrm{2}}}=\mathrm{4}\sqrt{\mathrm{2}} \\ $$$${h}×\mathrm{cot}\:{B}+{h}×\mathrm{cot}\:{C}={a} \\ $$$$\Rightarrow\mathrm{cot}\:{B}+\mathrm{cot}\:{C}=\frac{{a}}{{h}}=\frac{\sqrt{\mathrm{2}}}{\mathrm{4}\sqrt{\mathrm{2}}}=\frac{\mathrm{1}}{\mathrm{4}} \\…
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Question Number 201192 by Euclid last updated on 01/Dec/23 Answered by Calculusboy last updated on 01/Dec/23 $$\boldsymbol{{Solution}}:\:\boldsymbol{{Apply}}\:\boldsymbol{{I}\mathrm{n}}\:\boldsymbol{\mathrm{to}}\:\boldsymbol{{both}}\:\boldsymbol{{sides}} \\ $$$$\boldsymbol{{In}}\:\boldsymbol{{x}}^{\boldsymbol{{x}}^{\mathrm{4}} } =\boldsymbol{{In}}\mathrm{64} \\ $$$$\boldsymbol{{x}}^{\mathrm{4}} \boldsymbol{{Inx}}=\boldsymbol{{In}}\mathrm{64} \\…
Question Number 201162 by Calculusboy last updated on 01/Dec/23 Answered by Frix last updated on 01/Dec/23 $${x}={y}={z}=\mathrm{1} \\ $$ Answered by Rasheed.Sindhi last updated on…
Question Number 201190 by Calculusboy last updated on 01/Dec/23 Answered by mr W last updated on 01/Dec/23 $$\frac{\mathrm{1}}{\left(−{x}\right)^{\left(−{x}\right)} }=\frac{\mathrm{1}}{\mathrm{1000}} \\ $$$$\left(−{x}\right)^{\left(−{x}\right)} =\mathrm{1000} \\ $$$$\Rightarrow{x}=−\frac{\mathrm{4ln}\:\mathrm{10}}{{W}\left(\mathrm{4ln}\:\mathrm{10}\right)}\approx−\mathrm{5}.\mathrm{438583} \\…
Question Number 201184 by Calculusboy last updated on 01/Dec/23 Answered by Sutrisno last updated on 01/Dec/23 $${misal}\::\:\:\sqrt{\mathrm{2}{x}}+\mathrm{4}={u}\rightarrow{dx}=\sqrt{\mathrm{2}{x}}{du} \\ $$$$=\int\frac{\sqrt{\mathrm{2}{x}}}{{u}}.\sqrt{\mathrm{2}{x}}{du} \\ $$$$=\int\frac{\left({u}−\mathrm{4}\right)^{\mathrm{2}} }{{u}}{du} \\ $$$$=\int\frac{{u}^{\mathrm{2}} −\mathrm{8}{u}+\mathrm{16}}{{u}}{du}…
Question Number 201152 by mathlove last updated on 01/Dec/23 $${if}\:\:\mathrm{4}^{{x}} +\mathrm{4}^{−{x}} =\mathrm{7} \\ $$$${then}\:\:\:\mathrm{8}^{{x}} +\mathrm{8}^{−{x}} =? \\ $$ Answered by BaliramKumar last updated on 01/Dec/23…
Question Number 201185 by Calculusboy last updated on 01/Dec/23 Answered by witcher3 last updated on 02/Dec/23 $$\mathrm{non}\:\mathrm{close}\:\mathrm{formes} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 201149 by Mingma last updated on 30/Nov/23 Answered by witcher3 last updated on 03/Dec/23 $$\mathrm{x}=\mathrm{n}\in\mathbb{N}\:\mathrm{y}=\frac{\mathrm{1}}{\mathrm{n}},\mathrm{z}=\frac{\mathrm{1}}{\mathrm{n}},\mathrm{n}\geqslant\mathrm{2} \\ $$$$\forall\mathrm{n}\in\mathbb{N}−\left\{\mathrm{0},\mathrm{1}\right\}\:\:\left(\mathrm{n},\frac{\mathrm{1}}{\mathrm{n}},\frac{\mathrm{1}}{\mathrm{n}}\right)\mathrm{is}\:\mathrm{solution} \\ $$$$ \\ $$ Terms of…
Question Number 201150 by Mingma last updated on 30/Nov/23 Answered by mr W last updated on 02/Dec/23 $${a}={side}\:{length}\:{of}\:{square} \\ $$$$\left(\frac{{a}^{\mathrm{2}} +{x}^{\mathrm{2}} −\mathrm{15}^{\mathrm{2}} }{\mathrm{2}{ax}}\right)^{\mathrm{2}} +\left(\frac{{a}^{\mathrm{2}} +{x}^{\mathrm{2}}…