Question Number 205245 by pticantor last updated on 13/Mar/24 $$\boldsymbol{{calculate}} \\ $$$$\:\:\: \\ $$$$\int\frac{\mathrm{3}\boldsymbol{{xdx}}}{\:\sqrt{\mathrm{1}−\boldsymbol{{x}}^{\mathrm{4}} }} \\ $$$$\boldsymbol{{plsssssss}} \\ $$ Answered by mr W last updated…
Question Number 205211 by cortano12 last updated on 13/Mar/24 Answered by Berbere last updated on 13/Mar/24 $$\begin{cases}{\mathrm{5}{x}^{\mathrm{2}} \left({y}^{\mathrm{2}} −\mathrm{1}\right)=\mathrm{4}{x}\left({x}^{\mathrm{2}} +{y}^{\mathrm{2}} \right)}\\{\mathrm{5}{y}^{\mathrm{2}} \left({x}^{\mathrm{2}} +\mathrm{1}\right)=\mathrm{3}{y}\left({x}^{\mathrm{2}} +{y}^{\mathrm{2}} \right)}\end{cases}…
Question Number 205237 by universe last updated on 13/Mar/24 Answered by Berbere last updated on 13/Mar/24 $${n}^{\mathrm{2}} +{x}^{\mathrm{2}} \geqslant{n}^{\mathrm{2}} \\ $$$$\frac{{x}}{\mathrm{1}+{x}}\leqslant\mathrm{1}\Rightarrow\frac{{nx}\mathrm{tan}^{−\mathrm{1}} \left({x}\right)}{\left(\mathrm{1}+{x}\right)\left({n}^{\mathrm{2}} +{x}^{\mathrm{2}} \right)}\leqslant{n}.\mathrm{1}.\frac{\mathrm{tan}^{−\mathrm{1}} \left({x}\right)}{{n}^{\mathrm{2}}…
Question Number 205238 by necx122 last updated on 13/Mar/24 $$\mathrm{4}^{{x}} \:+\:{x}\:=\:\mathrm{260} \\ $$$${find}\:{the}\:{possible}\:{values}\:{of}\:{x} \\ $$$$ \\ $$ Commented by Ghisom last updated on 13/Mar/24 $$\mathrm{generally}…
Question Number 205264 by pticantor last updated on 13/Mar/24 $$\boldsymbol{{pls}}\:\boldsymbol{{how}}\:\boldsymbol{{to}}\:\boldsymbol{{calculate}}\:\boldsymbol{{this}}? \\ $$$$\int_{\frac{\mathrm{1}}{\mathrm{2}}} ^{\mathrm{1}} \frac{\boldsymbol{{ln}}\left(\boldsymbol{{x}}+\mathrm{1}\right)}{\boldsymbol{{x}}}\boldsymbol{{dx}} \\ $$ Answered by Berbere last updated on 13/Mar/24 $$=−\left(−\int_{\frac{\mathrm{1}}{\mathrm{2}}} ^{\mathrm{1}}…
Question Number 205262 by mathzup last updated on 13/Mar/24 $${nature}\:{of}\:{the}\:{serie}\:\sum_{{n}\geqslant\mathrm{1}} \:\frac{{ln}\left({n}\right)}{{n}} \\ $$ Answered by Berbere last updated on 13/Mar/24 $$\forall{n}\geqslant\mathrm{2}\:{ln}\left({n}\right)\geqslant{ln}\left(\mathrm{2}\right)>\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\underset{{n}\geqslant\mathrm{1}} {\sum}\frac{{ln}\left({n}\right)}{{n}}\geqslant\frac{\mathrm{1}}{\mathrm{2}}\underset{{n}\geqslant\mathrm{1}} {\sum}\frac{\mathrm{1}}{{n}}\rightarrow+\infty\:{serie}\:{dv}…
Question Number 205230 by louisyanni last updated on 13/Mar/24 $$ \\ $$ Commented by Rasheed.Sindhi last updated on 13/Mar/24 $$\mathcal{R}{eserved}\:{space}\:{for}\:{a}\:{question}? \\ $$ Commented by Frix…
Question Number 205256 by hardmath last updated on 13/Mar/24 $$\mathrm{Find}:\:\:\:\underset{\boldsymbol{\mathrm{x}}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\left(\frac{\mathrm{1}}{\mathrm{x}}\right)\:=\:? \\ $$ Commented by mr W last updated on 13/Mar/24 $${your}\:{earnest}? \\ $$ Commented…
Question Number 205227 by Ari last updated on 13/Mar/24 Commented by Ari last updated on 13/Mar/24 $${colored}\:{surface}? \\ $$ Commented by cherokeesay last updated on…
Question Number 205220 by hardmath last updated on 13/Mar/24 $$\mathrm{cos}^{\mathrm{4}} \:\mathrm{x}\:−\:\mathrm{sin}^{\mathrm{4}} \:\mathrm{x}\:=\:\mathrm{cos}^{\mathrm{2}} \:\mathrm{x} \\ $$$$\Rightarrow\:\mathrm{x}\:=\:? \\ $$ Answered by Sutrisno last updated on 13/Mar/24 $$\left({cos}^{\mathrm{2}}…