Question Number 202716 by Rasheed.Sindhi last updated on 01/Jan/24 $$\overline {\:\:{abcd}\:\:}{is}\:{a}\:{four}\:{digit}\:{number} \\ $$$${such}\:{that}\:{a}^{\mathrm{2}} +{b}^{\mathrm{2}} +{c}^{\mathrm{2}} +{d}^{\mathrm{2}} =\overline {\:{cd}\:} \\ $$$${and}\:\overline {\:{cd}\:}−\overline {\:{d}\:}=\overline {\:{ab}\:}. \\ $$$$\mathcal{F}{ind}\:{the}\:{number}.…
Question Number 202715 by Rasheed.Sindhi last updated on 01/Jan/24 $$\begin{array}{|c|}{\:\:\underset{\mathrm{is}\:\mathrm{2025}} {\mathrm{Square}\:\mathrm{of}\:\mathrm{mean}\:\mathrm{of}\:\mathrm{two}\:\mathrm{numbers}}\:\:}\\\hline\end{array}\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\& \\ $$$$\begin{array}{|c|}{\:\:\underset{\:\mathrm{is}\:\mathrm{2026}} {\mathrm{mean}\:\mathrm{of}\:\mathrm{squares}\:\mathrm{of}\:\mathrm{the}\:\mathrm{numbers}}\:\:}\\\hline\end{array} \\ $$$$\:\:\:\:\: \\ $$$$\begin{array}{|c|}{\mathrm{Find}\:\mathrm{the}\:\mathrm{product}\:\mathrm{of}\:\mathrm{the}\:\mathrm{numbers}.}\\\hline\end{array}\: \\ $$ Answered by JDamian…
Question Number 202726 by ajfour last updated on 02/Jan/24 $${pk}={b} \\ $$$${pq}+{sk}={c} \\ $$$${sq}={d} \\ $$$$\sqrt{{t}}=\frac{{t}−{q}}{{k}}=\frac{{t}−{s}}{{p}} \\ $$$${Given}\:{are}\:{b},\:{c},\:{d}.\:{Find}\:{t}. \\ $$ Commented by MATHEMATICSAM last updated…
Question Number 202721 by Rasheed.Sindhi last updated on 01/Jan/24 $$\:\:\:\begin{array}{|c|}{\underset{\mathcal{HAPPY}\:\mathcal{NEW}\:\mathcal{YEAR}!} {\mathrm{2}^{\mathrm{2}} +\mathrm{4}^{\mathrm{2}} +\mathrm{6}^{\mathrm{2}} +\centerdot\centerdot\centerdot\centerdot\centerdot+\mathrm{22}^{\mathrm{2}} =\mathrm{2024}}}\\\hline\end{array} \\ $$$$\begin{array}{|c|}{\:\:\:\mathrm{May}\:\mathrm{2024}\:\mathrm{be}\:\begin{cases}{\mathrm{war}-\mathrm{free}!}\\{\&}\\{{peaceful}!}\end{cases}\:\:\:}\\\hline\end{array} \\ $$$$ \\ $$ Terms of Service Privacy…
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Question Number 202684 by ajfour last updated on 31/Dec/23 Answered by mr W last updated on 02/Jan/24 $$\mathrm{cos}\:\alpha=\frac{{s}^{\mathrm{2}} +{q}^{\mathrm{2}} −\left(\frac{{s}}{\mathrm{2}}\right)^{\mathrm{2}} }{\mathrm{2}{sq}}=\frac{\mathrm{3}{s}^{\mathrm{2}} +\mathrm{4}{q}^{\mathrm{2}} }{\mathrm{8}{sq}} \\ $$$$\mathrm{cos}\:\beta=\frac{{p}}{\mathrm{2}{s}}=\frac{{s}−{q}}{\mathrm{2}{s}}=\mathrm{sin}\:\alpha…
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Question Number 202648 by liuxinnan last updated on 31/Dec/23 $${how}\:{to}\:{use}\:{the}\:{fewest}\:“\mathrm{2}''\:{to}\:{make}\:\mathrm{2024} \\ $$$${you}\:{only}\:{can}\:{use}\:“\mathrm{2}''\:{and}\:−\:+\:×\:/\:\left(\:\right)\:!\:\:\hat {\:}\:… \\ $$$${as}\:{the}\:{following} \\ $$$$\:\:\:\:\:\:\mathrm{2}×\mathrm{2}×\mathrm{2}\left(\left(\mathrm{2}×\mathrm{2}\right)!−\mathrm{2}/\mathrm{2}\right)\left(\mathrm{2}×\left(\mathrm{2}+\mathrm{2}/\mathrm{2}\right)!−\mathrm{2}/\mathrm{2}\right)=\mathrm{2024} \\ $$$${totally}\:{use}\:{thirteen}\:“\:\mathrm{2}'' \\ $$ Commented by Frix last…
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Question Number 202651 by hardmath last updated on 31/Dec/23 Commented by Frix last updated on 31/Dec/23 $${y}=\frac{\mathrm{3cos}\:{x}\:+\mathrm{sin}\:{x}}{\mathrm{10}}+{c}_{\mathrm{1}} \mathrm{e}^{\mathrm{2}{x}} +{c}_{\mathrm{2}} \mathrm{e}^{{x}} \\ $$ Answered by Mathspace…