Question Number 200729 by mnjuly1970 last updated on 22/Nov/23 $$ \\ $$$$\:\:\:{if}\:\:\:\:{a}<{b}<\mathrm{0}\:\:\: \\ $$$$\:\:\:{and}\:\:\sqrt{\:{a}^{\mathrm{4}} +\mathrm{2}{a}^{\mathrm{2}} {b}^{\mathrm{2}} +{b}^{\mathrm{4}} }\:+\sqrt{{a}^{\mathrm{4}} −\mathrm{2}{a}^{\mathrm{2}} {b}^{\mathrm{2}} +{b}^{\mathrm{4}} }\:=\:? \\ $$$$ \\…
Question Number 200720 by cortano12 last updated on 22/Nov/23 Answered by BaliramKumar last updated on 22/Nov/23 $$\mathrm{18}+\mathrm{3}+\mathrm{8}\:=\:\mathrm{29} \\ $$ Answered by Rasheed.Sindhi last updated on…
Question Number 200722 by cortano12 last updated on 22/Nov/23 $$\:\:\mathrm{Find}\:\mathrm{all}\:\mathrm{polynomials}\:\mathrm{P}\left(\mathrm{x}\right)\:\mathrm{with} \\ $$$$\:\mathrm{real}\:\mathrm{coefficients}\:\mathrm{such}\:\mathrm{that}\:\mathrm{for} \\ $$$$\:\mathrm{all}\:\mathrm{nonzero}\:\mathrm{real}\:\mathrm{numbers}\:\mathrm{x},\: \\ $$$$\:\:\:\:\:\mathrm{P}\left(\mathrm{x}\right)+\mathrm{P}\left(\frac{\mathrm{1}}{\mathrm{x}}\right)=\frac{\mathrm{P}\left(\mathrm{x}+\frac{\mathrm{1}}{\mathrm{x}}\right)+\mathrm{P}\left(\mathrm{x}−\frac{\mathrm{1}}{\mathrm{x}}\right)}{\mathrm{2}}\:\:\: \\ $$ Commented by Frix last updated on 22/Nov/23…
Question Number 200723 by hardmath last updated on 22/Nov/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 200716 by hardmath last updated on 22/Nov/23 $$\mathrm{1}.\: \\ $$$$\frac{{a}}{\mathrm{8}}\:+\:\frac{{b}}{\mathrm{5}}\:=\:\mathrm{6}\:\:\:\Rightarrow\:\:\:\left({a}+{b}\right)_{\boldsymbol{{max}}} \:=\:? \\ $$ Answered by AST last updated on 22/Nov/23 $$\mathrm{5}{a}+\mathrm{8}{b}=\mathrm{240}\Rightarrow{a}=\frac{\mathrm{240}−\mathrm{8}{b}}{\mathrm{5}} \\ $$$${remains}\:{to}\:{find}\:\left({a}+{b}\right)_{{max}}…
Question Number 200717 by hardmath last updated on 22/Nov/23 $$\mathrm{2}. \\ $$$${A}\:=\:\mathrm{12}\:−\:\mathrm{2}{x} \\ $$$${B}\:=\:\mathrm{3}\:+\:\mathrm{2}{x} \\ $$$$\left({A}\centerdot{B}\right)_{\boldsymbol{{min}}} \:=\:? \\ $$ Answered by AST last updated on…
Question Number 200718 by hardmath last updated on 22/Nov/23 $$\mathrm{3}. \\ $$$$\mathrm{1}+\mathrm{3}+\mathrm{5}+\mathrm{7}+…+\left(\mathrm{2}{n}+\mathrm{1}\right)\:=\:? \\ $$ Answered by AST last updated on 22/Nov/23 $$\mathrm{2}+\mathrm{4}+..+\mathrm{2}{n}=\mathrm{2}\left(\mathrm{1}+\mathrm{2}+\mathrm{3}+…+{n}\right)={n}^{\mathrm{2}} +{n} \\ $$$$\mathrm{1}+\mathrm{2}+\mathrm{3}+…+\mathrm{2}{n}+\mathrm{1}=\left(\mathrm{2}{n}+\mathrm{1}\right)\left({n}+\mathrm{1}\right)…
Question Number 200636 by a.lgnaoui last updated on 21/Nov/23 $$\mathrm{1}−\mathrm{Determiner}\:\mathrm{la}\:\mathrm{valeur}\:\mathrm{de}\:\:\boldsymbol{\mathrm{EF}} \\ $$$$\mathrm{2}−\mathrm{Laire}\:\mathrm{du}\:\mathrm{triangle}\:\:\boldsymbol{\mathrm{ADE}} \\ $$$$ \\ $$ Commented by a.lgnaoui last updated on 21/Nov/23 Commented by…
Question Number 200632 by pascal889 last updated on 21/Nov/23 $$\boldsymbol{\mathrm{help}}\:\boldsymbol{\mathrm{me}}\:\boldsymbol{\mathrm{derived}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{formular}}\:\boldsymbol{\mathrm{of}} \\ $$$$\:\boldsymbol{\mathrm{motion}} \\ $$ Commented by mr W last updated on 21/Nov/23 $${do}\:{you}\:{really}\:{think}\:{this}\:{is}\: \\ $$$${appropriate}?\:{this}\:{is}\:{like}\:{when}\:{i}\:{ask}…
Question Number 200627 by cherokeesay last updated on 21/Nov/23 Answered by Frix last updated on 21/Nov/23 $$\mathrm{The}\:\mathrm{1}^{\mathrm{st}} \:\mathrm{equation}\:\mathrm{is}\:\mathrm{true}\:\mathrm{for}\:{y}=\frac{\mathrm{1}}{{x}} \\ $$$$\Rightarrow\:{x}=\mathrm{2}\wedge{y}=\frac{\mathrm{1}}{\mathrm{2}} \\ $$ Commented by cherokeesay…