Question Number 213741 by bourasi last updated on 15/Nov/24 $$\sqrt{\mathrm{1}−\mathrm{sin}} \\ $$ Commented by Frix last updated on 15/Nov/24 $$\mathrm{Is}\:\mathrm{sin}\:\mathrm{a}\:\mathrm{variable}\:\mathrm{name}\:\mathrm{or}\:\mathrm{s}×\mathrm{i}×\mathrm{n}? \\ $$$$\mathrm{In}\:\mathrm{the}\:\mathrm{2}^{\mathrm{nd}} \:\mathrm{case},\:\mathrm{is}\:\mathrm{i}=\sqrt{−\mathrm{1}}? \\ $$…
Question Number 213759 by Spillover last updated on 15/Nov/24 Answered by MrGaster last updated on 06/Feb/25 $$=\int_{\mathrm{0}} ^{\infty} \frac{\mathrm{1}}{\frac{{e}^{{nx}} −\mathrm{1}}{{e}^{{x}} −\mathrm{1}}}{dx}=\int_{\mathrm{0}} ^{\infty} \frac{{e}^{{x}} −\mathrm{1}}{{e}^{{nx}} −\mathrm{1}}{dx}…
Question Number 213738 by Spillover last updated on 15/Nov/24 Answered by MrGaster last updated on 03/Feb/25 $$=\frac{\mathrm{1}}{\mathrm{2}}\mathrm{ln}^{\mathrm{2}} \mathrm{2}+\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{{n}+\mathrm{1}} }{\mathrm{2}^{{n}} {n}^{\mathrm{2}} } \\ $$…
Question Number 213751 by hardmath last updated on 15/Nov/24 $$\mathrm{m}\:;\:\mathrm{n}\:\in\:\mathbb{Z}_{+} \\ $$$$\mathrm{2m}^{\mathrm{2}} \:+\:\mathrm{n}^{\mathrm{2}} \:−\:\mathrm{mn}\:=\:\mathrm{54} \\ $$$$ \\ $$$$\mathrm{1}.\:\left(\mathrm{m};\mathrm{n}\right)=? \\ $$$$\mathrm{2}.\:\left(\mathrm{m};\mathrm{n}\right)=? \\ $$$$……………. \\ $$ Commented…
Question Number 213735 by Spillover last updated on 15/Nov/24 Answered by Spillover last updated on 15/Nov/24 Answered by Spillover last updated on 15/Nov/24 Terms of…
Question Number 213744 by efronzo1 last updated on 15/Nov/24 Answered by golsendro last updated on 15/Nov/24 $$\:\:=\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\left(\mathrm{1}+\mathrm{4x}\right)^{\frac{\mathrm{3}}{\mathrm{4}}} +\left(\mathrm{1}−\mathrm{4x}\right)^{\frac{\mathrm{3}}{\mathrm{4}}} −\mathrm{2}}{\mathrm{x}^{\mathrm{2}} } \\ $$$$\:\:=\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{3}\left(\mathrm{1}+\mathrm{4x}\right)^{−\frac{\mathrm{1}}{\mathrm{4}}} −\mathrm{3}\left(\mathrm{1}−\mathrm{4x}\right)^{−\frac{\mathrm{1}}{\mathrm{4}}}…
Question Number 213745 by efronzo1 last updated on 15/Nov/24 Answered by mnjuly1970 last updated on 16/Nov/24 $$\:\left(\mathrm{M}{edian}\:{theorem}\:\right):\:\:\:\:\:\:\mathrm{7}^{\mathrm{2}} \:+\:{R}^{\mathrm{2}} =\:\mathrm{2}\left(\sqrt{\mathrm{14}}\:\right)^{\mathrm{2}} \:+\:\frac{\left(\mathrm{2}{R}\right)^{\mathrm{2}} }{\mathrm{2}} \\ $$$$\:\:\:\:\:\:\mathrm{49}\:+\:{R}^{\mathrm{2}} \:=\:\mathrm{28}\:+\:\mathrm{2}{R}^{\mathrm{2}} \\…
Question Number 213724 by Spillover last updated on 14/Nov/24 Commented by TonyCWX08 last updated on 16/Nov/24 $${I}\:{see}\:{who}\:{you}\:{are}… \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 213725 by zakirullah last updated on 14/Nov/24 $${please}\:{prove}\:\frac{\mathrm{1}}{{x}}\:=\:{x}^{−\mathrm{1}} \\ $$ Answered by Rasheed.Sindhi last updated on 14/Nov/24 $$\:\:\:\:\:\frac{\mathrm{1}}{{x}}=\frac{{x}^{\mathrm{0}} }{{x}^{\mathrm{1}} }={x}^{\mathrm{0}−\mathrm{1}} ={x}^{−\mathrm{1}} \\ $$…
Question Number 213726 by hardmath last updated on 14/Nov/24 $$\mathrm{ax}\:=\:\mathrm{by}\:=\:\mathrm{cz}\:=\:\mathrm{36} \\ $$$$\frac{\mathrm{1}}{\mathrm{x}}\:\:+\:\:\frac{\mathrm{1}}{\mathrm{y}}\:\:+\:\:\frac{\mathrm{1}}{\mathrm{z}}\:\:=\:\:\frac{\mathrm{1}}{\mathrm{9}} \\ $$$$\mathrm{a}\:+\:\mathrm{b}\:+\:\mathrm{c}\:=\:? \\ $$ Answered by Rasheed.Sindhi last updated on 14/Nov/24 $${a}=\frac{\mathrm{36}}{{x}},\:{b}=\frac{\mathrm{36}}{{y}},\:{c}=\frac{\mathrm{36}}{{z}} \\…