Question Number 200432 by galivan last updated on 18/Nov/23 Commented by mr W last updated on 19/Nov/23 $${it}\:{seems}\:{you}\:{are}\:{using}\:{the}\:{forum}\:{just} \\ $$$${for}\:{editing}\:{and}\:{storing}\:{your}\:{own} \\ $$$${formulas}.\:{please}\:{use}\:{the}\:{editor} \\ $$$${function}\:{of}\:{this}\:{app}\:{for}\:{such}\:{purpose}! \\…
Question Number 200428 by Spillover last updated on 18/Nov/23 Answered by ajfour last updated on 18/Nov/23 $${F}={mg}−\frac{{kv}^{\mathrm{2}} }{\mathrm{2}} \\ $$$$\frac{{vdv}}{{dx}}={g}−\frac{{kv}^{\mathrm{2}} }{\mathrm{2}{m}}=−\frac{{k}}{\mathrm{2}{m}}\left({v}^{\mathrm{2}} −\frac{\mathrm{2}{mg}}{{k}}\right) \\ $$$$\frac{\mathrm{1}}{\mathrm{2}}\int_{\mathrm{0}} ^{\:{v}}…
Question Number 200424 by hardmath last updated on 18/Nov/23 Commented by Frix last updated on 18/Nov/23 $$\mathrm{This}\:\mathrm{is}\:\mathrm{soft}\:\mathrm{math}… \\ $$$$\Omega=\frac{\pi\sqrt{\mathrm{2}}}{\mathrm{4}}+\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}\mathrm{ln}\:\left(\mathrm{1}+\sqrt{\mathrm{2}}\right) \\ $$ Commented by hardmath last…
Question Number 200420 by ajfour last updated on 18/Nov/23 Commented by ajfour last updated on 18/Nov/23 $${plz}\:{solve}.. \\ $$ Commented by ajfour last updated on…
Question Number 200423 by Tawa11 last updated on 18/Nov/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 200417 by hardmath last updated on 18/Nov/23 $$\mathrm{find}:\:\:\:\Omega\:=\:\int_{\mathrm{1}} ^{\:\infty} \:\frac{\sqrt{\mathrm{x}}}{\left(\mathrm{1}\:+\:\mathrm{x}^{\mathrm{2}} \right)}\:\mathrm{dx}\:=\:? \\ $$ Answered by witcher3 last updated on 18/Nov/23 $$\sqrt{\mathrm{x}}=\mathrm{y} \\ $$$$=\int_{\mathrm{1}}…
Question Number 200418 by mnjuly1970 last updated on 18/Nov/23 $$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{calculus}\:\:\left(\:\:\mathrm{I}\:\:\right)\:\: \\ $$$$\:\:\mathrm{I}{f}\:,\:\:\:\mathrm{I}\:=\:\int_{\mathrm{0}} ^{\:\pi} \:\frac{\:{x}\:}{\mathrm{1}\:\:+\:\mathrm{sin}^{\mathrm{2}} \left({x}\right)}\:\mathrm{d}{x}\:=\:{a}\:\zeta\:\left(\:\mathrm{2}\:\right)\:\: \\ $$$$\:\:\:\:\:\:\:\Rightarrow\:\:\:\:{a}\:=\:?\:\:\:\:\:\:\:\:\: \\ $$$$\:\:\:\:{where}\:\:,\:\:\:\zeta\:\left({s}\:\right)\:=\:\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\:\frac{\:\mathrm{1}}{{n}^{\:{s}} } \\…
Question Number 200412 by hardmath last updated on 18/Nov/23 $$\mathrm{If} \\ $$$$\sqrt{\left(\mathrm{x}-\mathrm{6}\right)^{\mathrm{2}} \:+\:\left(\mathrm{y}+\mathrm{1}\right)^{\mathrm{2}} }\:+\:\sqrt{\left(\mathrm{x}-\mathrm{9}\right)^{\mathrm{2}} \:+\:\left(\mathrm{y}+\mathrm{5}\right)^{\mathrm{2}} } \\ $$$$ \\ $$$$\mathrm{find}:\:\:\:\mathrm{minumum}\:=\:? \\ $$ Answered by witcher3…
Question Number 200413 by Mingma last updated on 18/Nov/23 Commented by Mingma last updated on 18/Nov/23 Evaluate! Answered by witcher3 last updated on 18/Nov/23 $$\:\mathrm{x}−\frac{\mathrm{x}^{\mathrm{3}}…
Question Number 200415 by Mingma last updated on 18/Nov/23 Answered by witcher3 last updated on 18/Nov/23 $$\Leftrightarrow\underset{\mathrm{h}\rightarrow\mathrm{0}} {\mathrm{lim}}\left(−\frac{\mathrm{f}\left(\mathrm{x}\right)−\mathrm{f}\left(\mathrm{x}−\mathrm{h}\right)}{\mathrm{x}−\left(\mathrm{x}−\mathrm{h}\right)}\right)=−\mathrm{f}'\left(\mathrm{x}\right) \\ $$$$\Leftrightarrow−\mathrm{f}''\left(\mathrm{x}\right)=\underset{\mathrm{n}\geqslant\mathrm{1}} {\sum}\frac{\mathrm{f}^{\left(\mathrm{n}\right)} \left(\mathrm{0}\right)\mathrm{x}^{\mathrm{n}} }{\mathrm{n}!} \\ $$$$=\mathrm{f}\left(\mathrm{x}\right)−\mathrm{f}\left(\mathrm{0}\right)=−\mathrm{f}''\left(\mathrm{x}\right)…