Question Number 213658 by Danielacrsz last updated on 13/Nov/24 $${r}=\frac{\mathrm{112452}−\frac{\left(\mathrm{2108}\right)\left(\mathrm{3820}\right)}{\mathrm{80}}}{\:\sqrt{\mathrm{67778}−\frac{\left(\mathrm{2108}\right)^{\mathrm{2}} }{\mathrm{80}}\sqrt{\mathrm{232470}−\frac{\left(\mathrm{3820}\right)^{\mathrm{2}} }{\mathrm{80}}}}} \\ $$$$ \\ $$$$ \\ $$ Answered by MathematicalUser2357 last updated on 14/Nov/24…
Question Number 213659 by efronzo1 last updated on 13/Nov/24 $$\:\:\:\:\underset{−\infty} {\overset{\infty} {\int}}\:\frac{\mid\mathrm{24x}−\mathrm{24}\mid−\mathrm{20}}{\mathrm{22}^{\mathrm{x}} +\mathrm{22}}\:\mathrm{dx}\:=? \\ $$ Answered by MrGaster last updated on 03/Feb/25 $$=\frac{\mathrm{40}\:\mathrm{ln}\:\mathrm{22}}{\left(\mathrm{ln}\:\mathrm{22}\right)^{\mathrm{2}} } \\…
Question Number 213680 by issac last updated on 13/Nov/24 Commented by Frix last updated on 13/Nov/24 $$\mathrm{WolframAlpha} \\ $$$$\mathrm{It}'\mathrm{s}\:\mathrm{worthless}\:\mathrm{if}\:\mathrm{you}\:\mathrm{don}'\mathrm{t}\:\mathrm{understand}\:\mathrm{how} \\ $$$$\mathrm{to}\:\mathrm{get}\:\mathrm{there}. \\ $$ Commented by…
Question Number 213679 by issac last updated on 13/Nov/24 $${Q}\mathrm{213662} \\ $$$$…… \\ $$$$\mathrm{Not}\:\mathrm{easy}……. \\ $$$$\:\:_{{p}} \boldsymbol{\mathrm{F}}_{{q}} \left({z};\cancel{\underbrace{ }}\:\boldsymbol{\mathrm{a}},\boldsymbol{\mathrm{b}}\right)\:\mathrm{is}\:\mathrm{hypergeometric}\:\mathrm{function} \\ $$$$\mathrm{Li}_{\nu} \left({z}\right)\:\mathrm{is}\:\mathrm{Dilogarithm}\:\mathrm{function}. \\ $$ Terms…
Question Number 213668 by mr W last updated on 13/Nov/24 Commented by mr W last updated on 13/Nov/24 $${find}\:{shaded}\:{area} \\ $$ Answered by BHOOPENDRA last…
Question Number 213664 by 281981 last updated on 13/Nov/24 Answered by mr W last updated on 13/Nov/24 Commented by mr W last updated on 13/Nov/24…
Question Number 213667 by efronzo1 last updated on 13/Nov/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 213656 by efronzo1 last updated on 12/Nov/24 Answered by golsendro last updated on 13/Nov/24 $$\:\:\left(\mathrm{i}\right)\:\mathrm{g}\left(\mathrm{4}−\mathrm{x}\right)=\:−\mathrm{g}\left(\mathrm{x}\right)\: \\ $$$$\:\:\:\:\:\:\:\:\underset{\mathrm{0}} {\overset{\mathrm{4}} {\int}}\:\mathrm{g}\left(\mathrm{x}\right)\mathrm{dx}\:=\:\underset{\mathrm{0}} {\overset{\mathrm{4}} {\int}}\:\mathrm{g}\left(\mathrm{4}−\mathrm{x}\right)\mathrm{dx}\: \\ $$$$\:\:\:\:\:\:\:\:\underset{\mathrm{0}}…
Question Number 213641 by Abdullahrussell last updated on 12/Nov/24 Answered by Ghisom last updated on 03/Dec/24 $$\alpha_{{k}} \in\mathbb{Z} \\ $$$${p}\left({x}\right)=\underset{{k}=\mathrm{3}} {\overset{{n}} {\sum}}\alpha_{{k}} {x}^{{k}} \\ $$$${x}\in\mathbb{Z}\:\Rightarrow\:{p}\left({x}\right)\in\mathbb{Z}…
Question Number 213642 by universe last updated on 12/Nov/24 Answered by Berbere last updated on 12/Nov/24 $${a}_{{n}} =\underset{{N}\rightarrow\infty} {\mathrm{lim}}\underset{{k}={n}} {\overset{{N}} {\sum}}\frac{\mathrm{1}}{{k}^{\mathrm{2}} };\forall{k}\geqslant{n}>\mathrm{1}\:\:{k}\left({k}−\mathrm{1}\right)\:\leqslant{k}^{\mathrm{2}} \leqslant{k}\left({k}+\mathrm{1}\right)\Rightarrow \\ $$$$\underset{{N}\rightarrow\infty}…