Question Number 201940 by Calculusboy last updated on 15/Dec/23 $$\boldsymbol{{tan}}^{\mathrm{3}} \left(\boldsymbol{{xy}}^{\mathrm{2}} +\boldsymbol{{y}}\right)=\boldsymbol{{x}}\:\:\boldsymbol{{find}}\:\frac{\boldsymbol{{dy}}}{\boldsymbol{{dx}}} \\ $$ Answered by cortano12 last updated on 16/Dec/23 $$\:\:\Rightarrow\frac{\mathrm{d}}{\mathrm{dx}}\:\left[\:\mathrm{tan}\:^{\mathrm{3}} \left(\mathrm{xy}^{\mathrm{2}} +\mathrm{y}\right)\:\right]\:=\:\frac{\mathrm{d}}{\mathrm{dx}}\left(\mathrm{x}\right) \\…
Question Number 201941 by ajfour last updated on 15/Dec/23 $${x}^{\mathrm{4}} −\frac{\mathrm{17}}{\mathrm{18}}{x}^{\mathrm{2}} +\frac{\mathrm{40}}{\mathrm{3}}{x}+\frac{\mathrm{1625}}{\mathrm{144}}=\mathrm{0} \\ $$$${Find}\:{roots}.\:\left({Two}\:{are}\:{real}\:{and}\:{two}\:\right. \\ $$$$\left.{are}\:{complex}\right)\bigstar \\ $$ Commented by Frix last updated on 17/Dec/23…
Question Number 201936 by aurpeyz last updated on 15/Dec/23 Commented by aurpeyz last updated on 15/Dec/23 $${Using}\:{complex}\:{analysis}\:{method} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 201938 by AROUNAMoussa last updated on 15/Dec/23 Commented by AROUNAMoussa last updated on 15/Dec/23 $${Veillez}\:{bien}\:{vouloir}\:{m}'{aider}\:! \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 201906 by sonukgindia last updated on 15/Dec/23 Answered by AST last updated on 15/Dec/23 $${sin}\left({x}\right)=\frac{{s}}{{h}}…\left({i}\right) \\ $$$$\left({ii}\right)…\frac{{sin}\left(\mathrm{2}{x}\right)}{{h}}=\frac{{sin}\left({x}\right)}{\mathrm{2}{s}}\Rightarrow\mathrm{2}{sin}\left({x}\right)=\frac{{sin}\left({x}\right)}{{sin}\left(\mathrm{2}{x}\right)} \\ $$$$\Rightarrow{sin}\left(\mathrm{2}{x}\right)=\frac{\mathrm{1}}{\mathrm{2}}\Rightarrow{x}=\mathrm{15}° \\ $$ Answered by…
Question Number 201907 by mnjuly1970 last updated on 15/Dec/23 Answered by Rasheed.Sindhi last updated on 15/Dec/23 $$\bullet{Radius}\:{of}\:{Semi}-{circle}\:{R}=\:\frac{\mathrm{10}}{\mathrm{2}}=\mathrm{5}\:{cm} \\ $$$$\bullet{let}\:{radous}\:{of}\:{greater}\:{quarter}-{circle}={r}_{\mathrm{1}} \\ $$$$\left({R}+{r}_{\mathrm{1}} \right)^{\mathrm{2}} =\mathrm{10}^{\mathrm{2}} +\mathrm{5}^{\mathrm{2}} =\mathrm{125}…
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Question Number 201934 by aurpeyz last updated on 15/Dec/23 Commented by aurpeyz last updated on 15/Dec/23 $${By}\:{complex}\:{analysis}\:{method}. \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 201902 by sonukgindia last updated on 15/Dec/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 201897 by mnjuly1970 last updated on 15/Dec/23 $$ \\ $$$$\:\:\:\:\:\mathrm{Q}{uestion}:\:\:{The}\:{congruence} \\ $$$$\:\:\:\:\:\:\:{equation}\:\:\:''\:\:\:\:\left(\:\mathrm{5}{a}\:+\mathrm{3}\:\right){x}\:\:\overset{\mathrm{3}{a}\:+\:\mathrm{4}} {\equiv}\:\mathrm{19}\:\:\:''\:\:{is}\:{given}. \\ $$$$\:\:\:\:\:\:\:{Find}\:{the}\:{sum}\:{of}\:{digits}\:{of}\:\: \\ $$$$\:\:\:\:\:\:\:{the}\:{smallest}\:\:{three}\:−{digit}\:{natural}\:{number}\:\:''\:{a}\:''\: \\ $$$$\:\:\:\:\:\:\:{such}\:{that}\:{the}\:{assumed}\:{equation}\:{has}\: \\ $$$$\:\:\:\:\:\:\:\:\:{no}\:\:{solution}\:\:{in}\:\:\:''\:\:\:\mathbb{Z}\:\:''. \\ $$$$…