Question Number 212627 by MrGaster last updated on 19/Oct/24 $$ \\ $$$$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\left(\frac{\sqrt{\mathrm{1}\centerdot\mathrm{2}}}{{n}^{\mathrm{2}} +\mathrm{1}}+\frac{\sqrt{\mathrm{2}\centerdot\mathrm{3}}}{{n}^{\mathrm{2}} +\mathrm{2}}+\ldots+\frac{\sqrt{{n}\left({n}+\mathrm{1}\right)}}{{n}^{\mathrm{2}} +{n}}\right) \\ $$ Answered by mehdee7396 last updated on 19/Oct/24…
Question Number 212621 by mr W last updated on 19/Oct/24 $$\mathrm{A}\:\mathrm{group}\:\mathrm{of}\:\boldsymbol{\mathrm{n}}\:\mathrm{people}\:\mathrm{are}\:\mathrm{standing}\:\mathrm{in} \\ $$$$\mathrm{a}\:\mathrm{circle}.\:\:\mathrm{They}\:\mathrm{are}\:\mathrm{numbered}\:\mathrm{with}\: \\ $$$$\mathrm{1},\:\mathrm{2},\:\mathrm{3},\:\mathrm{etc}.\:\mathrm{Starting}\:\mathrm{with}\:\mathrm{the}\:\mathrm{person} \\ $$$$\mathrm{with}\:\mathrm{the}\:\mathrm{number}\:\mathrm{1},\:\mathrm{every}\:\mathrm{second}\: \\ $$$$\mathrm{person}\:\mathrm{is}\:\mathrm{removed}\:\mathrm{from}\:\mathrm{the}\:\mathrm{circle}\:\mathrm{and}\: \\ $$$$\mathrm{this}\:\mathrm{process}\:\mathrm{continues}\:\mathrm{until}\:\mathrm{only}\:\mathrm{one}\: \\ $$$$\mathrm{person}\:\mathrm{remains}\:\mathrm{in}\:\mathrm{the}\:\mathrm{circle}.\:\:\mathrm{What} \\ $$$$\mathrm{will}\:\mathrm{be}\:\mathrm{the}\:\mathrm{number}\:\mathrm{of}\:\mathrm{the}\:\mathrm{last}\:\mathrm{person}…
Question Number 212616 by im13 last updated on 19/Oct/24 $$ \\ $$$$ \\ $$$${if}\:\:\mathrm{f}\left(\mathrm{x}\right)=\:^{{a}} {x}={x}^{{x}^{{x}^{\iddots^{{x}} } } } \left({there}\:{are}\:{a}\:{x}'{s};{a}\in\mathbb{N}\:{and}\:{a}\neq\mathrm{0}\right) \\ $$$$\int{f}\left({x}\right){dx}=? \\ $$ Commented by…
Question Number 212618 by MrGaster last updated on 19/Oct/24 $$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\underset{{n}\rightarrow\mathrm{0}} {\mathrm{lim}}\left(\underset{{k}=\mathrm{1}} {\overset{{n}} {\prod}}\frac{{k}^{\mathrm{2}} +\mathrm{3}{k}+\mathrm{2}}{{k}^{\mathrm{2}} +\mathrm{2}{k}+\mathrm{1}}\right)^{\frac{\mathrm{1}}{{n}}} \\ $$ Commented by mehdee7396 last updated on…
Question Number 212615 by MrGaster last updated on 19/Oct/24 $$\mathrm{Verify}\:\mathrm{the}\:\mathrm{equation}:\mathrm{tan}\:{nx}=\underset{{k}=\mathrm{1}} {\overset{\left[\frac{{n}+\mathrm{1}}{\mathrm{2}}\right]} {\sum}}\left(−\mathrm{1}\right)^{{k}−\mathrm{1}} \begin{pmatrix}{{n}}\\{\mathrm{2}{k}−\mathrm{1}}\end{pmatrix}\:\mathrm{tan}^{\mathrm{2}{k}−\mathrm{1}} {x}/\underset{{k}=\mathrm{0}} {\overset{\left[\frac{{n}}{\mathrm{2}}\right]} {\sum}}\left(−\mathrm{1}\right)^{{k}} \begin{pmatrix}{{n}}\\{\mathrm{2}{k}}\end{pmatrix}\mathrm{tan}^{\mathrm{2}{k}} {x} \\ $$ Terms of Service Privacy Policy…
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Question Number 212600 by MrGaster last updated on 18/Oct/24 $$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{certificate}: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\underset{{n}\rightarrow\infty} {\mathrm{lim}}\int_{\mathrm{0}} ^{\mathrm{1}} \frac{{n}}{\mathrm{1}+{n}^{\mathrm{2}} {x}^{\mathrm{2}} }{e}^{{x}^{\mathrm{3}} } {dx}=\frac{\pi}{\mathrm{2}}. \\ $$ Answered by…
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