Question Number 226962 by MDYeaminJr last updated on 22/Dec/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 226958 by efronzo1 last updated on 21/Dec/25 $$\:\:\:\mathrm{3}^{\mathrm{x}} =\mathrm{x}^{\mathrm{9}} \: \\ $$$$\:\:\:\:\mathrm{x}^{\mathrm{2}} =\:..? \\ $$ Answered by TonyCWX last updated on 21/Dec/25 $${x}\mathrm{ln}\left(\mathrm{3}\right)\:=\:\mathrm{9ln}\left({x}\right)…
Question Number 226942 by Spillover last updated on 20/Dec/25 Answered by Spillover last updated on 24/Dec/25 Answered by Spillover last updated on 24/Dec/25 Answered by…
Question Number 226943 by Spillover last updated on 20/Dec/25 Commented by fantastic2 last updated on 26/Dec/25 $${the}\:{rectangle}\:{is}\:{not}\:{unique} \\ $$ Commented by fantastic2 last updated on…
Question Number 226952 by Spillover last updated on 20/Dec/25 Answered by Spillover last updated on 24/Dec/25 $$\left({a}\right) \\ $$$${I}_{{n}} =\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} {e}^{−{x}} \mathrm{cos}\:^{{n}} {xdx} \\…
Question Number 226953 by Spillover last updated on 20/Dec/25 $${If}\:{I}_{{n}} =\int\left({x}^{\mathrm{2}} +{a}^{\mathrm{2}} \right)^{{n}} {dx}\: \\ $$$${Show}\:{that} \\ $$$${I}_{{n}} =\frac{\mathrm{1}}{\mathrm{2}{n}+\mathrm{1}}{x}\left({x}^{\mathrm{2}} +{a}^{\mathrm{2}} \right)^{{n}} +\mathrm{2}{na}^{\mathrm{2}} {I}_{{n}−\mathrm{1}} \: \\…
Question Number 226936 by Estevao last updated on 19/Dec/25 Answered by Ghisom_ last updated on 19/Dec/25 $$\int\mathrm{2}^{\mathrm{ln}\:{x}} {dx}=\int{x}^{\mathrm{ln}\:\mathrm{2}} {dx}=\frac{{x}^{\mathrm{1}+\mathrm{ln}\:\mathrm{2}} }{\mathrm{1}+\mathrm{ln}\:\mathrm{2}}+{C} \\ $$ Commented by Estevao…
Question Number 226935 by Estevao last updated on 19/Dec/25 Commented by Kassista last updated on 21/Dec/25 Commented by Kassista last updated on 21/Dec/25 Answered by…
Question Number 226919 by Spillover last updated on 19/Dec/25 Answered by Ghisom_ last updated on 19/Dec/25 $$\underset{{n}} {\underbrace{\mathrm{6}…}}\mathrm{8}^{\mathrm{2}} =\underset{{n}} {\underbrace{\mathrm{4}…}}\mathrm{6}\underset{{n}} {\underbrace{\mathrm{2}…}}\mathrm{4} \\ $$$$\Rightarrow\:\underset{{digits}} {\sum}=\left(\mathrm{4}+\mathrm{2}\right){n}+\mathrm{6}+\mathrm{4}=\mathrm{6}{n}+\mathrm{10} \\…
Question Number 226908 by mr W last updated on 18/Dec/25 Commented by mr W last updated on 18/Dec/25 $${find}\:{the}\:{area}\:{of}\:{the}\:{circle}. \\ $$ Answered by A5T last…