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Author: Tinku Tara

A-group-of-n-people-are-standing-in-a-circle-They-are-numbered-with-1-2-3-etc-Starting-with-the-person-with-the-number-1-every-second-person-is-removed-from-the-circle-and-this-process-conti

Question Number 212621 by mr W last updated on 19/Oct/24 $$\mathrm{A}\:\mathrm{group}\:\mathrm{of}\:\boldsymbol{\mathrm{n}}\:\mathrm{people}\:\mathrm{are}\:\mathrm{standing}\:\mathrm{in} \\ $$$$\mathrm{a}\:\mathrm{circle}.\:\:\mathrm{They}\:\mathrm{are}\:\mathrm{numbered}\:\mathrm{with}\: \\ $$$$\mathrm{1},\:\mathrm{2},\:\mathrm{3},\:\mathrm{etc}.\:\mathrm{Starting}\:\mathrm{with}\:\mathrm{the}\:\mathrm{person} \\ $$$$\mathrm{with}\:\mathrm{the}\:\mathrm{number}\:\mathrm{1},\:\mathrm{every}\:\mathrm{second}\: \\ $$$$\mathrm{person}\:\mathrm{is}\:\mathrm{removed}\:\mathrm{from}\:\mathrm{the}\:\mathrm{circle}\:\mathrm{and}\: \\ $$$$\mathrm{this}\:\mathrm{process}\:\mathrm{continues}\:\mathrm{until}\:\mathrm{only}\:\mathrm{one}\: \\ $$$$\mathrm{person}\:\mathrm{remains}\:\mathrm{in}\:\mathrm{the}\:\mathrm{circle}.\:\:\mathrm{What} \\ $$$$\mathrm{will}\:\mathrm{be}\:\mathrm{the}\:\mathrm{number}\:\mathrm{of}\:\mathrm{the}\:\mathrm{last}\:\mathrm{person}…

lim-n-0-k-1-n-k-2-3k-2-k-2-2k-1-1-n-

Question Number 212618 by MrGaster last updated on 19/Oct/24 $$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\underset{{n}\rightarrow\mathrm{0}} {\mathrm{lim}}\left(\underset{{k}=\mathrm{1}} {\overset{{n}} {\prod}}\frac{{k}^{\mathrm{2}} +\mathrm{3}{k}+\mathrm{2}}{{k}^{\mathrm{2}} +\mathrm{2}{k}+\mathrm{1}}\right)^{\frac{\mathrm{1}}{{n}}} \\ $$ Commented by mehdee7396 last updated on…

Verify-the-equation-tan-nx-k-1-n-1-2-1-k-1-n-2k-1-tan-2k-1-x-k-0-n-2-1-k-n-2k-tan-2k-x-

Question Number 212615 by MrGaster last updated on 19/Oct/24 $$\mathrm{Verify}\:\mathrm{the}\:\mathrm{equation}:\mathrm{tan}\:{nx}=\underset{{k}=\mathrm{1}} {\overset{\left[\frac{{n}+\mathrm{1}}{\mathrm{2}}\right]} {\sum}}\left(−\mathrm{1}\right)^{{k}−\mathrm{1}} \begin{pmatrix}{{n}}\\{\mathrm{2}{k}−\mathrm{1}}\end{pmatrix}\:\mathrm{tan}^{\mathrm{2}{k}−\mathrm{1}} {x}/\underset{{k}=\mathrm{0}} {\overset{\left[\frac{{n}}{\mathrm{2}}\right]} {\sum}}\left(−\mathrm{1}\right)^{{k}} \begin{pmatrix}{{n}}\\{\mathrm{2}{k}}\end{pmatrix}\mathrm{tan}^{\mathrm{2}{k}} {x} \\ $$ Terms of Service Privacy Policy…

Help-me-to-solve-pls-Q-212576-

Question Number 212598 by MATHEMATICSAM last updated on 18/Oct/24 $$\mathrm{Help}\:\mathrm{me}\:\mathrm{to}\:\mathrm{solve}\:\mathrm{pls} \\ $$$$\mathrm{Q}\:\mathrm{212576}\: \\ $$ Answered by A5T last updated on 18/Oct/24 $${Lemma}:\:\frac{{a}}{{b}}=\frac{{c}}{{d}}\Rightarrow\frac{{a}}{{b}}=\frac{{c}}{{d}}=\frac{{a}\underset{−} {+}{c}}{{b}\underset{−} {+}{d}} \\…