Question Number 201000 by mokys last updated on 27/Nov/23 $${find}\: \\ $$$$ \\ $$$$\left.\:\mathrm{1}\right)\left(\mathrm{0},\mathrm{2}\right)\:\cup\:\left\{\mathrm{3}\right\}\:\: \\ $$$$ \\ $$$$\left.\:\:\mathrm{2}\right)\left[\mathrm{0},\mathrm{2}\right]\:\cup\:\left\{\mathrm{3}\right\} \\ $$$$ \\ $$$$\left.\:\:\mathrm{3}\right)\:\left(−\mathrm{5},\mathrm{5}\right)\:\cup\:\left\{\mathrm{6}\right\} \\ $$$$\:\: \\…
Question Number 200968 by Mastermind last updated on 27/Nov/23 Commented by AST last updated on 27/Nov/23 $${P}\overset{\mathrm{10}} {−}{S}\overset{\mathrm{12}} {−}{U}\overset{\mathrm{8}} {−}{T}\overset{\mathrm{7}} {−}{R}\overset{\mathrm{15}} {−}{Q}\overset{\mathrm{11}} {−}{P}\Rightarrow{min}=\mathrm{63} \\ $$…
Question Number 200970 by Mastermind last updated on 27/Nov/23 Answered by JDamian last updated on 27/Nov/23 $${Really}? \\ $$ Answered by mr W last updated…
Question Number 200971 by Mingma last updated on 27/Nov/23 Answered by AST last updated on 27/Nov/23 $${WLOG},{let}\:{a}\:{be}\:{the}\:{max}\:{element} \\ $$$${abcd}={a}+{b}+{c}+{d}\leqslant\mathrm{4}{a}\Rightarrow{bcd}\leqslant\mathrm{4} \\ $$$${bcd}=\mathrm{1}\Rightarrow{b}={c}={d}=\mathrm{1}\Rightarrow{a}+\mathrm{3}={a}\left({absurd}\right) \\ $$$${bcd}=\mathrm{2}\Rightarrow{b}+{c}+{d}=\mathrm{4}\Rightarrow\mathrm{4}+{a}=\mathrm{2}{a}\Rightarrow{a}=\mathrm{4} \\ $$$$\Rightarrow\left({a},{b},{c},{d}\right)=\left(\mathrm{4},\mathrm{2},\mathrm{1},\mathrm{1}\right);\left(\mathrm{4},\mathrm{1},\mathrm{2},\mathrm{1}\right);\left(\mathrm{4},\mathrm{1},\mathrm{1},\mathrm{2}\right)…
Question Number 200964 by Mastermind last updated on 27/Nov/23 Answered by MM42 last updated on 27/Nov/23 $$\mathrm{3} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 200960 by sonukgindia last updated on 27/Nov/23 Answered by Frix last updated on 27/Nov/23 $${t}=\mathrm{1}+\sqrt{{x}^{\mathrm{2}} +\mathrm{1}} \\ $$$$\Rightarrow \\ $$$$\int…=\int\left(\mathrm{1}−\frac{\mathrm{1}}{{t}}\right){dt}={t}−\mathrm{ln}\:{t}\:= \\ $$$$=\mathrm{1}+\sqrt{{x}^{\mathrm{2}} +\mathrm{1}}−\mathrm{ln}\:\left(\mathrm{1}+\sqrt{{x}^{\mathrm{2}}…
Question Number 200961 by jabarsing last updated on 27/Nov/23 $$\: \\ $$$$\:\:\:\:\:−{x}^{\mathrm{3}} +\mathrm{1}=\sqrt[{\mathrm{3}}]{−{x}+\mathrm{1}}\:\Rightarrow{x}=? \\ $$$$ \\ $$ Answered by cortano12 last updated on 27/Nov/23 Answered…
Question Number 200894 by sonukgindia last updated on 26/Nov/23 Answered by Frix last updated on 26/Nov/23 $$=\mathrm{4}\underset{\mathrm{0}} {\overset{\frac{\pi}{\mathrm{2}}} {\int}}\frac{{dx}}{\mathrm{1}+\mathrm{4sin}^{\mathrm{2}} \:{x}}\:\overset{{t}=\mathrm{tan}\:{x}} {=} \\ $$$$=\mathrm{4}\underset{\mathrm{0}} {\overset{\infty} {\int}}\frac{{dt}}{\mathrm{5}{t}^{\mathrm{2}}…
Question Number 200895 by sonukgindia last updated on 26/Nov/23 Answered by mathematicsmagic last updated on 26/Nov/23 $${beta}\:{functions}\:,{we}\:{put}\:{x}^{\varphi} ={t} \\ $$ Terms of Service Privacy Policy…
Question Number 200954 by Mingma last updated on 27/Nov/23 Commented by Frix last updated on 27/Nov/23 $$\mathrm{1}+\sqrt{\mathrm{2}} \\ $$ Terms of Service Privacy Policy Contact:…