Question Number 212424 by hardmath last updated on 13/Oct/24 $$\begin{cases}{\mathrm{x}\:+\:\mathrm{2y}\:−\:\mathrm{3z}\:=\:\mathrm{1}}\\{\mathrm{2x}\:−\:\mathrm{y}\:+\:\mathrm{z}\:=\:\mathrm{4}}\\{\mathrm{3x}\:+\:\mathrm{y}\:+\:\mathrm{2z}\:=\:\mathrm{7}}\end{cases}\:\:\:\:\:\mathrm{find}:\:\mathrm{x},\mathrm{y},\mathrm{z}\:=\:? \\ $$ Answered by A5T last updated on 13/Oct/24 $$\left({ii}\right)+\left({iii}\right)\Rightarrow\mathrm{5}{x}+\mathrm{3}{z}=\mathrm{11}…\left({iv}\right) \\ $$$$\mathrm{2}\left({iii}\right)−\left({i}\right)\Rightarrow\mathrm{5}{x}+\mathrm{7}{z}=\mathrm{13}…\left({v}\right) \\ $$$$\left({v}\right)−\left({iv}\right)\Rightarrow\mathrm{4}{z}=\mathrm{2}\Rightarrow{z}=\frac{\mathrm{1}}{\mathrm{2}}\Rightarrow{x}=\frac{\mathrm{19}}{\mathrm{10}}\Rightarrow{y}=\frac{\mathrm{3}}{\mathrm{10}} \\…
Question Number 212427 by Spillover last updated on 13/Oct/24 Commented by Ghisom last updated on 13/Oct/24 $$−\frac{\mathrm{1}}{\mathrm{10}×\mathrm{10}!} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 212448 by hardmath last updated on 13/Oct/24 $$\mathrm{If}\:\:\mathrm{x}^{\mathrm{2}} \:−\:\mathrm{x}\:+\:\mathrm{3}\:=\:\mathrm{0} \\ $$$$\mathrm{Find}\:\:\mathrm{x}\:+\:\frac{\mathrm{9}}{\mathrm{x}^{\mathrm{2}} }\:=\:? \\ $$ Answered by A5T last updated on 13/Oct/24 $${x}^{\mathrm{2}} −{x}+\mathrm{3}=\mathrm{0}\Rightarrow{x}^{\mathrm{3}}…
Question Number 212416 by MrGaster last updated on 13/Oct/24 $$\frac{\frac{\int_{\mathrm{0}} ^{+\infty} {e}^{−{s}} {s}^{\mathrm{5}} {ds}}{\mathrm{2}}+\frac{\int_{−\infty} ^{+\infty} {e}^{−\frac{{t}^{\mathrm{2}} }{\mathrm{2}}} {dt}}{\int_{\mathrm{0}} ^{+\infty} \mathrm{sin}{t}^{\mathrm{2}} {dt}}\left(\frac{\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{{n}} }{\mathrm{2}{n}+\mathrm{1}}}{\int_{\mathrm{0}} ^{+\infty}…
Question Number 212417 by mr W last updated on 13/Oct/24 Commented by mr W last updated on 13/Oct/24 $${unsolved}\:{old}\:{question}\:\mathrm{212291} \\ $$ Answered by mr W…
Question Number 212383 by Ismoiljon_008 last updated on 12/Oct/24 $$ \\ $$$$\:\:\:{AB}={BC}={CD}={DE}\:\:{in}\:{pentagon}\:{ABCDE}, \\ $$$$\:\:\:{angle}\:{B}=\mathrm{96}^{{o}} \:{and}\:{angle}\:{C}\:{and}\:{angle}\: \\ $$$$\:\:\:{D}=\mathrm{108}^{{o}} .\:{Then}\:{find}\:{angle}\:{A} \\ $$$$\:\:\:\mathbb{H}{elp}\:{me}\:{please} \\ $$$$ \\ $$ Terms…
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Question Number 212384 by a.lgnaoui last updated on 14/Oct/24 $$\mathrm{Reponse}\:\mathrm{a}\:\mathrm{la}\:\mathrm{question}\:\mathrm{N}° \\ $$$$\mathrm{Q212291}\:\:\:\:\:\:\mathrm{S}\left(\mathrm{ABCD}\right)=\:\:\mathrm{66},\mathrm{69} \\ $$ Commented by hardmath last updated on 12/Oct/24 $$\mathrm{dear}\:\mathrm{professor},\:\mathrm{answer}:\:\mathrm{90} \\ $$ Terms…
Question Number 212368 by Spillover last updated on 12/Oct/24 Answered by MathematicalUser2357 last updated on 13/Oct/24 $$\infty \\ $$ Commented by Ghisom last updated on…
Question Number 212360 by MrGaster last updated on 11/Oct/24 $$ \\ $$$$\:\:\:\:\:{T}=\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\left(\frac{\mathrm{1}}{\left(\mathrm{4}{n}+\mathrm{1}\right)^{\mathrm{2}} }−\frac{\mathrm{1}}{\left(\mathrm{4}{n}+\mathrm{3}\right)^{\mathrm{2}} }\right. \\ $$ Answered by Berbere last updated on 15/Oct/24…