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Question-198644

Question Number 198644 by cortano12 last updated on 22/Oct/23 Commented by Rasheed.Sindhi last updated on 22/Oct/23 $${ab}=\left(\frac{\mathrm{8}−{a}+{b}}{\mathrm{6}}\right)^{\mathrm{3}} \:{or}\:\left(\frac{\mathrm{8}+{a}−{b}}{\mathrm{6}}\right)^{\mathrm{3}} \:? \\ $$ Commented by cortano12 last…

Question-198647

Question Number 198647 by ajfour last updated on 22/Oct/23 Commented by ajfour last updated on 22/Oct/23 $${Q}\:{is}\:{center}\:{of}\:{smaller}\:{circle}\:{of} \\ $$$${radius}\:{a}.\:{Find}\:{maximum}\:{area}\:{of}\: \\ $$$$\bigtriangleup{ABC}\:\:{in}\:{terms}\:{of}\:{a},\:{b}. \\ $$ Answered by…

Given-an-isosceles-triangle-ABC-which-A-30-AB-AC-A-point-D-is-midpoint-of-BC-A-point-P-is-chosen-on-then-segment-AD-and-a-point-Q-is-chosen-on-the-side-AB-so-that-BP-PQ-Find-the-angle-

Question Number 198643 by cortano12 last updated on 22/Oct/23 $$ \\ $$$$\mathrm{Given}\:\mathrm{an}\:\mathrm{isosceles}\:\mathrm{triangle}\:\mathrm{ABC} \\ $$$$\:\mathrm{which}\:\:\angle\mathrm{A}=\:\mathrm{30}°,\:\mathrm{AB}\:=\:\mathrm{AC}.\: \\ $$$$\mathrm{A}\:\mathrm{point}\:\mathrm{D}\:\mathrm{is}\:\mathrm{midpoint}\:\mathrm{of}\:\mathrm{BC}\:.\: \\ $$$$\mathrm{A}\:\mathrm{point}\:\mathrm{P}\:\mathrm{is}\:\mathrm{chosen}\:\mathrm{on}\:\mathrm{then} \\ $$$$\mathrm{segment}\:\mathrm{AD}\:\mathrm{and}\:\mathrm{a}\:\mathrm{point}\:\mathrm{Q}\:\mathrm{is} \\ $$$$\mathrm{chosen}\:\mathrm{on}\:\mathrm{the}\:\mathrm{side}\:\mathrm{AB}\:\mathrm{so}\:\mathrm{that} \\ $$$$\mathrm{BP}=\:\mathrm{PQ}. \\…

Question-198604

Question Number 198604 by ajfour last updated on 22/Oct/23 Commented by ajfour last updated on 22/Oct/23 $$\theta+\phi=\alpha\:\left({known}\right) \\ $$$${radius}\:{of}\:{arc}\:{is}\:{unity}. \\ $$$${If}\:{the}\:{two}\:{shaded}\:{parts}\:{are}\:{equal}, \\ $$$${find}\:\theta={f}\left(\alpha\right). \\ $$…

3x-2-1-x-5x-3x-2-x-1-119-18-

Question Number 198566 by tri26112004 last updated on 22/Oct/23 $$\frac{\mathrm{3}{x}^{\mathrm{2}} −\mathrm{1}}{{x}}+\frac{\mathrm{5}{x}}{\mathrm{3}{x}^{\mathrm{2}} −{x}−\mathrm{1}}=\frac{\mathrm{119}}{\mathrm{18}} \\ $$ Answered by Rasheed.Sindhi last updated on 22/Oct/23 $$\frac{\mathrm{3}{x}^{\mathrm{2}} −\mathrm{1}}{{x}}+\frac{\mathrm{5}{x}}{\mathrm{3}{x}^{\mathrm{2}} −{x}−\mathrm{1}}=\frac{\mathrm{119}}{\mathrm{18}} \\…