Question Number 200356 by sonukgindia last updated on 17/Nov/23 Commented by mr W last updated on 17/Nov/23 $${i}\:{guess}\:{you}\:{meant}\:{that}\:{the}\:{plane}\: \\ $$$${x}+\mathrm{8}{y}−\mathrm{4}{z}+{k}=\mathrm{0}\:{should}\:{touch}\:{the} \\ $$$${sphere}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} +\mathrm{2}{y}−\mathrm{3}=\mathrm{0}.…
Question Number 200357 by ajfour last updated on 17/Nov/23 Commented by ajfour last updated on 17/Nov/23 $$\:\:\:\:\:\:{Find}\:{r},\:{if}\:{square}\:{side}\:{is}\:{unity}. \\ $$ Commented by Frix last updated on…
Question Number 200353 by faysal last updated on 17/Nov/23 $$\mathrm{If}\:\mathrm{the}\:\mathrm{roots}\:\mathrm{of}\:\mathrm{x}^{\mathrm{3}} +\mathrm{3px}^{\mathrm{2}} +\mathrm{3qx}+\mathrm{r}=\mathrm{0}\:\mathrm{are} \\ $$$$\mathrm{in}\:\mathrm{harmonic}\:\mathrm{progression},\:\mathrm{then}\:\mathrm{prove}\:\mathrm{that} \\ $$$$\mathrm{2q}^{\mathrm{3}} =\mathrm{r}\left(\mathrm{3pq}−\mathrm{r}\right) \\ $$ Answered by jabarsing last updated on…
Question Number 200348 by samikshasuresh last updated on 17/Nov/23 $$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 200349 by samikshasuresh last updated on 17/Nov/23 $$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 200351 by faysal last updated on 17/Nov/23 $$\mathrm{Solve}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{x}^{\mathrm{3}} −\mathrm{12x}^{\mathrm{2}} −\mathrm{6x}−\mathrm{10}=\mathrm{0}\: \\ $$$$\mathrm{by}\:\mathrm{cardon}'\mathrm{s}\:\mathrm{method} \\ $$ Answered by Frix last updated on 17/Nov/23 $$\mathrm{The}\:\mathrm{name}\:\mathrm{is}\:{Cardano} \\…
Question Number 200347 by samikshasuresh last updated on 17/Nov/23 $$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 200336 by faysal last updated on 17/Nov/23 Answered by cortano12 last updated on 17/Nov/23 $$\:\:\begin{array}{|c|c|c|}{}&\hline{\mathrm{1}}&\hline{\mathrm{2}}&\hline{−\mathrm{3}}&\hline{\mathrm{5}}&\hline{−\mathrm{2}}&\hline{\mathrm{3}}\\{\mathrm{x}=\mathrm{2}}&\hline{\ast}&\hline{\mathrm{2}}&\hline{\mathrm{8}}&\hline{\mathrm{10}}&\hline{\mathrm{30}}&\hline{\mathrm{56}}\\{}&\hline{\mathrm{1}}&\hline{\mathrm{4}}&\hline{\mathrm{5}}&\hline{\mathrm{15}}&\hline{\mathrm{28}}&\hline{\mathrm{59}}\\\hline\end{array} \\ $$$$\:\mathrm{the}\:\mathrm{remainder}\:\mathrm{is}\:\mathrm{59} \\ $$$$\mathrm{the}\:\mathrm{quotient}\:\mathrm{is}\:\mathrm{h}\left(\mathrm{x}\right)=\mathrm{x}^{\mathrm{4}} +\mathrm{4x}^{\mathrm{3}} +\mathrm{5x}^{\mathrm{2}} +\mathrm{15x}+\mathrm{28} \\…
Question Number 200330 by hardmath last updated on 17/Nov/23 $$\mathrm{2}^{\boldsymbol{\mathrm{x}}} \:−\:\mathrm{3}^{\boldsymbol{\mathrm{x}}} \:=\:\sqrt{\mathrm{6}^{\boldsymbol{\mathrm{x}}} \:−\:\mathrm{9}^{\boldsymbol{\mathrm{x}}} } \\ $$$$\mathrm{find}:\:\:\:\mathrm{x}\:=\:? \\ $$ Answered by Rasheed.Sindhi last updated on 17/Nov/23…