Menu Close

Author: Tinku Tara

Given-function-f-4567-321567-567-321-888-f-32156-12062-156-120-276-find-the-value-of-f-20-22-21-

Question Number 198447 by cortano12 last updated on 20/Oct/23 $$\:\:\mathrm{Given}\:\mathrm{function}\: \\ $$$$\:\:\mathrm{f}\left(\mathrm{4567},\mathrm{321567}\right)=\:\mathrm{567}+\mathrm{321}=\mathrm{888}. \\ $$$$\:\:\mathrm{f}\left(\mathrm{32156},\mathrm{12062}\right)=\:\mathrm{156}+\mathrm{120}=\mathrm{276} \\ $$$$\:\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\: \\ $$$$\:\:\:\:\:\mathrm{f}\left(\frac{\mathrm{20}^{\mathrm{22}} }{\mathrm{21}}\:\right). \\ $$ Commented by mr W…

16000-x-3-1-x-2-x-

Question Number 198474 by cortano12 last updated on 20/Oct/23 $$\mathrm{16000}\:=\:\frac{\mathrm{x}^{\mathrm{3}} }{\left(\mathrm{1}−\mathrm{x}\right)^{\mathrm{2}} }\: \\ $$$$\:\mathrm{x}=? \\ $$ Answered by Frix last updated on 20/Oct/23 $${n}=\frac{{x}^{\mathrm{3}} }{\left(\mathrm{1}−{x}\right)^{\mathrm{2}}…

The-furier-series-approximation-to-the-forcing-function-is-given-by-f-t-5-1-4-pi-sin120pit-1-sin360pit-2-sin600pit-3-The-transfer-function-for-this-problem-T-s-X

Question Number 198465 by BHOOPENDRA last updated on 20/Oct/23 $${The}\:{furier}\:{series}\:{approximation}\:{to}\: \\ $$$${the}\:{forcing}\:{function}\:{is}\:{given}\:{by}\: \\ $$$${f}\left({t}\right)=\mathrm{5}\left[\mathrm{1}+\frac{\mathrm{4}}{\pi}\left(\frac{}{}\frac{{sin}\mathrm{120}\pi{t}}{\mathrm{1}}+\frac{{sin}\mathrm{360}\pi{t}}{\mathrm{2}}+\frac{{sin}\mathrm{600}\pi{t}}{\mathrm{3}}\right.\right. \\ $$$$\left.\:\left.\:\:\:\:\:+………\right)\right] \\ $$$${The}\:{transfer}\:{function}\:{for}\:{this} \\ $$$${problem}\:\:{T}\left({s}\right)=\frac{{X}\left({s}\right)}{{f}\left({s}\right)}=\frac{\mathrm{1}}{{ms}^{\mathrm{2}} +{cs}+{k}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\frac{\mathrm{1}}{\mathrm{0}.\mathrm{001}{s}+\mathrm{1}} \\ $$$$\mathrm{1}.\:{plot}\:{the}\:{amplitude}\:{spectrum}\:…

Question-198434

Question Number 198434 by cortano12 last updated on 20/Oct/23 Commented by mr W last updated on 20/Oct/23 $${due}\:{to}\:{symmetry} \\ $$$${max}=\left(\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}\right)\left(\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}\right)\left(\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}\right)=\frac{\sqrt{\mathrm{2}}}{\mathrm{4}} \\ $$ Answered by mr…

Question-198435

Question Number 198435 by Abdullahrussell last updated on 20/Oct/23 Answered by Rasheed.Sindhi last updated on 20/Oct/23 $$\mathrm{2}\:\&\:\mathrm{5}\:{make}\:\mathrm{0}\:\left[\mathrm{2}×\mathrm{5}=\mathrm{10}\right] \\ $$$$\mathcal{T}{here}\:{are}\:{more}\:\mathrm{2}'{s}\:{than}\:\mathrm{5}'{s} \\ $$$$\therefore\:{Number}\:{of}\:{trailing}\:{zeros} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:={Number}\:{of}\:\mathrm{5}'{s}\:{as}\:{a}\:{factor} \\ $$$${Counting}\:\mathrm{5}'{s}:…