Question Number 200262 by sonukgindia last updated on 16/Nov/23 Answered by Frix last updated on 17/Nov/23 $$\mathrm{I}\:\mathrm{get}\:\frac{{a}}{{b}}=−\mathrm{1}+\sqrt{\mathrm{2}+\mathrm{2}\sqrt{\mathrm{2}}}\approx\mathrm{1}.\mathrm{19737} \\ $$ Answered by AST last updated on…
Question Number 200256 by Calculusboy last updated on 16/Nov/23 Commented by Rasheed.Sindhi last updated on 17/Nov/23 $${In}\:{first}\:{sight}\:{your}\:{post}\:{seems} \\ $$$$\left.{to}\:{be}\:{red}\:{flagged}!\::\right) \\ $$ Terms of Service Privacy…
Question Number 200257 by Calculusboy last updated on 16/Nov/23 Answered by witcher3 last updated on 16/Nov/23 $$\mathrm{ln}^{\mathrm{2}} \left(\mathrm{x}\right)+\mathrm{1}=\mathrm{y}\Rightarrow\mathrm{dy}=\mathrm{2}\frac{\mathrm{ln}\left(\mathrm{x}\right)}{\mathrm{x}} \\ $$$$=\int\mathrm{y}^{\mathrm{2}} \mathrm{tan}^{−\mathrm{1}} \left(\mathrm{y}\right)\mathrm{dy} \\ $$$$=\frac{\mathrm{y}^{\mathrm{3}} }{\mathrm{3}}\mathrm{tan}^{−\mathrm{1}}…
Question Number 200159 by Calculusboy last updated on 15/Nov/23 Commented by 0670322918 last updated on 15/Nov/23 $$\underset{\mathrm{0}} {\int}^{\mathrm{1}} \frac{{x}^{\mathrm{3}} −\mathrm{3}{x}^{\mathrm{2}} +\mathrm{3}{x}−\mathrm{1}}{{x}^{\mathrm{4}} +\mathrm{4}{x}^{\mathrm{3}} +\mathrm{6}{x}^{\mathrm{2}} +\mathrm{4}{x}+\mathrm{1}}{dx}= \\…
Question Number 200186 by Calculusboy last updated on 15/Nov/23 Answered by ajfour last updated on 15/Nov/23 $$\frac{{y}}{{x}}={p}\:,\:\frac{{z}}{{y}}={q}\:,\:\frac{{x}}{{z}}={r}\:=\frac{\mathrm{1}}{{pq}} \\ $$$$\mathrm{1}+{p}+{p}^{\mathrm{2}} =\left(\mathrm{2}+{p}\right)\left(\frac{\mathrm{1}}{{r}}\right)^{\mathrm{2}/\mathrm{3}} \\ $$$$\mathrm{1}+{q}+{q}^{\mathrm{2}} =\left(\mathrm{2}+{q}\right)\left(\frac{\mathrm{1}}{{p}}\right)^{\mathrm{2}/\mathrm{3}} \\ $$$$\mathrm{1}+{r}+{r}^{\mathrm{2}}…
Question Number 200187 by sonukgindia last updated on 15/Nov/23 Answered by Mathspace last updated on 15/Nov/23 $${I}={Re}\left(\int_{−\infty} ^{+\infty} \frac{{e}^{{iax}} }{{x}^{\mathrm{2}} +\mathrm{1}}{dx}\right) \\ $$$${and}\:\int_{−\infty} ^{+\infty} \frac{{e}^{{iax}}…
Question Number 200155 by Calculusboy last updated on 15/Nov/23 Answered by Frix last updated on 15/Nov/23 $${s}>\mathrm{0} \\ $$$$\underset{\mathrm{0}} {\overset{\infty} {\int}}\sqrt{{t}}\mathrm{e}^{−{st}} {dt}= \\ $$$$=−\frac{\mathrm{1}}{{s}}\left[\sqrt{{t}}\mathrm{e}^{−{st}} \right]_{\mathrm{0}}…
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Question Number 200204 by cherokeesay last updated on 15/Nov/23 Commented by MM42 last updated on 15/Nov/23 $${is}\:,\:{ABCD},\:{is}\:{square}? \\ $$ Commented by ajfour last updated on…
Question Number 200205 by cherokeesay last updated on 15/Nov/23 Commented by Frix last updated on 15/Nov/23 $$\mathrm{min}\:=\mathrm{4} \\ $$$$\mathrm{max}=+\infty \\ $$ Terms of Service Privacy…