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Question Number 198431 by hardmath last updated on 19/Oct/23 $$\mathrm{f}\::\:\mathbb{R}\:\rightarrow\:\mathbb{R} \\ $$$$\mathrm{f}\:\left(\mathrm{3x}\:−\:\mathrm{1}\right)\:=\:\mathrm{x}\:+\:\mathrm{5} \\ $$$$\mathrm{Find}:\:\:\:\mathrm{f}\left(\mathrm{x}\right)\:=\:? \\ $$ Answered by AST last updated on 20/Oct/23 $${f}\left[\mathrm{3}\left(\frac{{x}}{\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{3}}\right)−\mathrm{1}\right]=\frac{{x}+\mathrm{1}}{\mathrm{3}}+\mathrm{5}\Rightarrow{f}\left({x}\right)=\frac{{x}+\mathrm{16}}{\mathrm{3}} \\…
Question Number 198426 by BHOOPENDRA last updated on 19/Oct/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 198427 by ks last updated on 19/Oct/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 198395 by BHOOPENDRA last updated on 19/Oct/23 Commented by mr W last updated on 22/Oct/23 $${what}\:{is}\:{the}\:{question}? \\ $$ Commented by mr W last…
Question Number 198420 by Mingma last updated on 19/Oct/23 Answered by Frix last updated on 19/Oct/23 $$\int\frac{{x}^{\mathrm{2}} }{\left(\mathrm{3}+\mathrm{4}{x}−\mathrm{4}{x}^{\mathrm{2}} \right)^{\frac{\mathrm{3}}{\mathrm{2}}} }{dx}\:\underset{{dx}=−\frac{\left(\mathrm{2}{x}−\mathrm{1}\right)\sqrt{\mathrm{3}+\mathrm{4}{x}−\mathrm{4}{x}^{\mathrm{2}} }}{\mathrm{4}{t}}} {\overset{{t}=\frac{\mathrm{2}+\sqrt{\mathrm{3}+\mathrm{4}{x}−\mathrm{4}{x}^{\mathrm{2}} }}{\mathrm{2}{x}−\mathrm{1}}} {=}}\: \\…
Question Number 198421 by mr W last updated on 19/Oct/23 Commented by mr W last updated on 19/Oct/23 $${given}\:{that}\:{the}\:{midpoints}\:{of}\:{the}\:{sides} \\ $$$${of}\:{a}\:{convex}\:{quadrilaterial}\:{are} \\ $$$${concyclic}.\:{if}\:{the}\:{lengthes}\:{of}\:{three}\:{of} \\ $$$${its}\:{sides}\:{are}\:{a},\:{b},\:{c}\:{respectively},\:{find}…
Question Number 198423 by pascal889 last updated on 19/Oct/23 $$\mathrm{show}\:\mathrm{that} \\ $$$$\frac{\mathrm{1}+\mathrm{sin}\varnothing}{\mathrm{cos}\varnothing}\:=\frac{\mathrm{cos}\varnothing}{\mathrm{1}−\mathrm{sin}\varnothing} \\ $$$$\mathrm{Pls}\:\mathrm{help} \\ $$$$ \\ $$ Answered by BaliramKumar last updated on 19/Oct/23…
Question Number 198391 by mr W last updated on 19/Oct/23 Commented by mr W last updated on 19/Oct/23 $${prove}\:{that}\:{BE}\:{is}\:{bisector}\:{of}\:\angle{CBD}. \\ $$$$\left({B},\:{E}\:{are}\:{touching}\:{points}\right) \\ $$ Answered by…
Question Number 198418 by cortano12 last updated on 19/Oct/23 $$\:\mathrm{20}^{\mathrm{22}} −\mathrm{1}\:=\:…\:\left(\mathrm{mod}\:\mathrm{1000}\right) \\ $$$$ \\ $$ Answered by BaliramKumar last updated on 19/Oct/23 $$ \\ $$$$\frac{\mathrm{20}^{\mathrm{22}}…