Question Number 198355 by lapache last updated on 18/Oct/23 $${solve}\:{the}\:{EDP} \\ $$$$\mathrm{1}−\:\:\:{x}\frac{\partial{f}}{\partial{x}}−{y}\frac{\partial{f}}{\partial{y}}=\mathrm{0} \\ $$$$\mathrm{2}−\:\:\:{x}\frac{\partial{f}}{\partial{x}}−\frac{\partial{f}}{\partial{y}}=\frac{{z}^{\mathrm{2}} }{{x}} \\ $$$$ \\ $$$$\mathrm{3}−\:\:{x}^{\mathrm{2}} \frac{\partial^{\mathrm{2}} {f}}{\partial{x}^{\mathrm{2}} }−{y}^{\mathrm{2}} \frac{\partial^{\mathrm{2}} {f}}{\partial{y}^{\mathrm{2}} }=\mathrm{0}…
Question Number 198380 by pascal889 last updated on 18/Oct/23 Commented by Rasheed.Sindhi last updated on 18/Oct/23 $$\mathbb{U}=? \\ $$$${Universal}\:{set}\:{is}\:{not}\:{given} \\ $$ Commented by AST last…
Question Number 198377 by sonukgindia last updated on 18/Oct/23 Answered by witcher3 last updated on 19/Oct/23 $$=\int_{\mathrm{0}} ^{\infty} \mathrm{xe}^{−\mathrm{4x}^{\mathrm{2}} } .\mathrm{xe}^{\frac{−\mathrm{9}}{\mathrm{x}^{\mathrm{2}} }} \mathrm{dx}\:\:\:\mathrm{IBP} \\ $$$$=\left[−\frac{\mathrm{e}^{−\mathrm{4x}^{\mathrm{2}}…
Question Number 198372 by cortano12 last updated on 18/Oct/23 $$\:\:\:\frac{\mathrm{1}}{\mathrm{1}×\mathrm{5}}\:+\:\frac{\mathrm{1}}{\mathrm{4}×\mathrm{8}}\:+\:\frac{\mathrm{1}}{\mathrm{7}×\mathrm{11}}\:+\frac{\mathrm{1}}{\mathrm{10}×\mathrm{14}}\:+\:\ldots=? \\ $$ Commented by Frix last updated on 19/Oct/23 $$\frac{\mathrm{1}}{\mathrm{8}}+\frac{\sqrt{\mathrm{3}}\pi}{\mathrm{36}} \\ $$ Answered by mr…
Question Number 198373 by sonukgindia last updated on 18/Oct/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 198339 by cherokeesay last updated on 18/Oct/23 Answered by witcher3 last updated on 18/Oct/23 $$\mathrm{didint}\:\mathrm{existe}\: \\ $$$$\left(\mathrm{x},\mathrm{y}\right)=\left(\frac{\mathrm{1}}{\mathrm{n}},\mathrm{2}−\frac{\mathrm{1}}{\mathrm{n}}\right);\mathrm{n}\geqslant\mathrm{1} \\ $$$$\mathrm{n}\rightarrow\infty \\ $$$$\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{x}^{\mathrm{2}} }+\frac{\mathrm{1}}{\left(\mathrm{x}+\mathrm{1}\right)^{\mathrm{2}} }\right)\rightarrow\infty…
Question Number 198332 by necx122 last updated on 17/Oct/23 $${Of}\:{men}\:{that}\:{attended}\:{a}\:{party},\:\mathrm{30}\:{of} \\ $$$${them}\:{wore}\:{coats},\:\mathrm{20}\:{wore}\:{ties}\:{and}\:\mathrm{10} \\ $$$${wore}\:{hats}.\:{There}\:{were}\:\mathrm{4}\:{men}\:{who}\:{wore} \\ $$$${coats}\:{and}\:{tie},\:{or}\:{tie}\:{and}\:{hat}\:{or}\:{coat}\:{and} \\ $$$${hat}.\:\mathrm{14}\:{men}\:{wore}\:{tie}\:{only}\:{with}\:{no} \\ $$$${coat}\:{and}\:{hat}.\:{Find}\:{the}\:{number}\:{of}\:{men} \\ $$$${who}\:{wore}: \\ $$$$\left.{a}\right)\:{coat},\:{tie}\:{and}\:{hat} \\…
Question Number 198302 by sonukgindia last updated on 17/Oct/23 Answered by mr W last updated on 17/Oct/23 $${z}_{\mathrm{1}} =\mathrm{1}+{i}\sqrt{\mathrm{3}}=\mathrm{2}{e}^{{i}\left(\frac{\pi}{\mathrm{3}}\right)} \\ $$$${z}_{\mathrm{2}} =\mathrm{2}{e}^{{i}\left(\frac{\pi}{\mathrm{3}}+\frac{\mathrm{2}\pi}{\mathrm{3}}\right)} =\mathrm{2}{e}^{{i}\pi} =−\mathrm{2} \\…
Question Number 198296 by York12 last updated on 17/Oct/23 $${Let}\:\left\{{x}_{{r}} \right\}_{{r}=\mathrm{1}} ^{{n}} {be}\:{n}\:{positive}\:{real}\:{numbers}\:{Show}\:{That}: \\ $$$$\frac{{x}_{\mathrm{1}} }{\mathrm{1}+{x}_{\mathrm{1}} ^{\mathrm{2}} }+\frac{{x}_{\mathrm{2}} }{\mathrm{1}+{x}_{\mathrm{1}} ^{\mathrm{2}} +{x}_{\mathrm{2}} ^{\mathrm{2}} }+…+\frac{{x}_{{n}} }{\mathrm{1}+{x}_{\mathrm{1}} ^{\mathrm{2}}…
Question Number 198326 by MrGHK last updated on 17/Oct/23 $$\boldsymbol{\mathrm{express}}\:\boldsymbol{\Gamma}\left(\boldsymbol{{k}}−\boldsymbol{{n}}\right)\:\boldsymbol{{in}}\:\boldsymbol{{pocchammer}}\:\boldsymbol{{symbol}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com