Question Number 215730 by MathematicalUser2357 last updated on 16/Jan/25 $$\boldsymbol{\mathrm{Determine}}\:\boldsymbol{{a}},\:\boldsymbol{{b}},\:\boldsymbol{{c}}\:\left[\mathrm{Lazy}\:\mathrm{problem}\right] \\ $$$$\mathrm{J181}-\mathrm{2}.\:{x}^{\mathrm{3}} −\mathrm{6}{x}^{\mathrm{2}} +\mathrm{15}{x}−\mathrm{7}=\left({x}+{a}\right)^{\mathrm{3}} +{bx}+{c} \\ $$$$\mathrm{J182}-\left(\mathrm{1}\right)\:{x}^{\mathrm{3}} +{ax}+\mathrm{2}=\left({x}+\mathrm{1}\right)\left({x}^{\mathrm{2}} +{bx}+{c}\right) \\ $$ Answered by A5T last…
Question Number 215708 by essaad last updated on 15/Jan/25 Answered by A5T last updated on 15/Jan/25 $$\left(\mathrm{i}\right)+\left(\mathrm{ii}\right)\Rightarrow\mathrm{n}^{\mathrm{3}} +\mathrm{y}^{\mathrm{3}} =\mathrm{0}\Rightarrow\left(\mathrm{n}+\mathrm{y}\right)\left(\mathrm{n}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} −\mathrm{ny}\right)=\mathrm{0}…\left(\mathrm{iii}\right) \\ $$$$\left(\mathrm{i}\right)−\left(\mathrm{ii}\right)\Rightarrow\mathrm{4n}^{\mathrm{3}} −\mathrm{4y}^{\mathrm{3}} −\mathrm{8n}+\mathrm{8y}=\mathrm{0}…
Question Number 215710 by Red1ight last updated on 15/Jan/25 $$ \\ $$3 different integer numbers are chosen from 0 to 10. what is the probability…
Question Number 215704 by universe last updated on 15/Jan/25 Commented by universe last updated on 16/Jan/25 $${HI}\:{MR}\:{W}\:{please}\:{solve}\:{this}\:{problem} \\ $$ Answered by mr W last updated…
Question Number 215687 by Ajeemkhan last updated on 15/Jan/25 Answered by som(math1967) last updated on 15/Jan/25 $$\int{sec}^{{p}−\mathrm{1}} {xsecxtanxdx} \\ $$$$\Rightarrow\int{sec}^{{p}−\mathrm{1}} {xd}\left({secx}\right) \\ $$$$\Rightarrow\:\frac{\mathrm{1}}{{p}}{sec}^{{p}} {x}+{C} \\…
Question Number 215696 by BaliramKumar last updated on 15/Jan/25 Answered by MATHEMATICSAM last updated on 15/Jan/25 $$\mathrm{sec}^{\mathrm{4}} \mathrm{x}\:−\:\mathrm{cosec}^{\mathrm{4}} \mathrm{x}\:−\:\mathrm{2sec}^{\mathrm{2}} \mathrm{x}\:+\:\mathrm{2cosec}^{\mathrm{2}} \mathrm{x}\:=\:\frac{\mathrm{63}}{\mathrm{8}} \\ $$$$\Rightarrow\:\mathrm{sec}^{\mathrm{2}} {x}\left(\mathrm{sec}^{\mathrm{2}} {x}\:−\:\mathrm{2}\right)\:+\:\mathrm{cosec}^{\mathrm{2}}…
Question Number 215714 by Masonmh last updated on 15/Jan/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 215715 by Hanuda354 last updated on 15/Jan/25 Commented by Hanuda354 last updated on 15/Jan/25 $$\mathrm{Find}\:{x} \\ $$ Answered by som(math1967) last updated on…
Question Number 215679 by BaliramKumar last updated on 14/Jan/25 Answered by MATHEMATICSAM last updated on 14/Jan/25 $$\mathrm{sec}^{\mathrm{2}} \theta\:=\:\frac{\mathrm{4}{xy}}{\left({x}\:+\:{y}\right)^{\mathrm{2}} } \\ $$$$\Rightarrow\:\mathrm{cos}^{\mathrm{2}} \theta\:=\:\frac{\left({x}\:+\:{y}\right)^{\mathrm{2}} }{\mathrm{4}{xy}} \\ $$$$\left({x}\:−\:{y}\right)^{\mathrm{2}}…
Question Number 215667 by mathlove last updated on 14/Jan/25 $$\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}{sec}\left(\frac{\pi}{\mathrm{2}}{x}\right)\left({arctanx}−\frac{\pi}{\mathrm{4}}\right)=? \\ $$ Answered by issac last updated on 14/Jan/25 $$\mathrm{sec}\left(\frac{\pi}{\mathrm{2}}\right)\left(\mathrm{arctan}\left(\mathrm{1}\right)−\frac{\pi}{\mathrm{4}}\right) \\ $$ Commented by…