Question Number 198124 by stevoh last updated on 10/Oct/23 $${solve}\:{for}\:{x}\:{log}\mathrm{100}+{log}\left(\mathrm{2}+{x}\right)=\mathrm{10} \\ $$ Answered by a.lgnaoui last updated on 10/Oct/23 $$\:\boldsymbol{\mathrm{xlog}}\mathrm{100}+\boldsymbol{\mathrm{log}}\left(\mathrm{2}+\boldsymbol{\mathrm{x}}\right)=\mathrm{10} \\ $$$$ \\ $$$$\:\:\:\:\mathrm{x}=\mathrm{10}−\mathrm{log}\left(\mathrm{2}+\mathrm{x}\right)\:\:\:\:\:\mathrm{log100}=\mathrm{2} \\…
Question Number 198092 by SteveX last updated on 10/Oct/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 198093 by SteveX last updated on 10/Oct/23 Answered by Safojon last updated on 10/Oct/23 $$\sqrt{{x}}=\frac{−\mathrm{4}+\mathrm{108}−\mathrm{24}}{\mathrm{8}} \\ $$$$\sqrt{{x}}=\frac{\mathrm{80}}{\mathrm{8}}\:\:\left(\sqrt{{x}}\right)^{\mathrm{2}} =\left(\mathrm{10}\right)^{\mathrm{2}} \\ $$$${x}=\mathrm{100}. \\ $$$${answer}\:{x}=\mathrm{100} \\…
Question Number 198123 by a.lgnaoui last updated on 10/Oct/23 $$\mathrm{Determiner} \\ $$$$\mathrm{lim}_{\mathrm{x}\rightarrow\mathrm{3}} \:\frac{\boldsymbol{\mathrm{x}}−\mathrm{3}}{\:^{\mathrm{3}} \sqrt{\boldsymbol{\mathrm{x}}+\mathrm{5}}\:−\mathrm{2}} \\ $$$$ \\ $$ Answered by Mathspace last updated on 10/Oct/23…
Question Number 198084 by SANOGO last updated on 10/Oct/23 Answered by witcher3 last updated on 10/Oct/23 $$\mathrm{Ex}\:\mathrm{1} \\ $$$$\mathrm{soit}\:\mathrm{u}_{\mathrm{n}} \:\mathrm{de}\:\mathrm{cachy}\:\Rightarrow\forall\epsilon>\mathrm{0}\:\exists\mathrm{N}\:\forall\:\mathrm{n}>\mathrm{m}>\mathrm{N}\:\mathrm{d}\left(\mathrm{u}_{\mathrm{n}} ,\mathrm{u}_{\mathrm{m}} \right)<\epsilon \\ $$$$\mathrm{pour}\:\epsilon=\frac{\mathrm{1}}{\mathrm{2}}\:\mathrm{on}\:\:\mathrm{a}\:\mathrm{d}\left(\mathrm{u}_{\mathrm{n}} ,\mathrm{u}_{\mathrm{m}}…
Question Number 198114 by Tawa11 last updated on 10/Oct/23 Commented by mr W last updated on 10/Oct/23 $${it}\:{should}\:{be}\:\mathrm{20}\:{m}\:\cancel{{longer}}\:{shorter}. \\ $$ Answered by mr W last…
Question Number 198074 by sonukgindia last updated on 09/Oct/23 Answered by a.lgnaoui last updated on 10/Oct/23 $$\mathrm{x}^{\mathrm{20}} +\mathrm{2x}^{\mathrm{10}} +\mathrm{1}=\left(\mathrm{x}^{\mathrm{10}} +\mathrm{1}\right)^{\mathrm{2}} \\ $$$$\mathrm{x}^{\mathrm{8}} =\frac{\mathrm{x}^{\mathrm{10}} }{\mathrm{x}^{\mathrm{2}} }\Rightarrow…
Question Number 198064 by giovi last updated on 09/Oct/23 $$\mathrm{3}×\mathrm{5}^{{x}} +\mathrm{5}^{{x}+\mathrm{1}} =\mathrm{8}×\mathrm{5}^{\mathrm{3}} \\ $$ Answered by a.lgnaoui last updated on 09/Oct/23 $$\mathrm{3}×\mathrm{5}^{\mathrm{x}} +\mathrm{5}×\mathrm{5}^{\mathrm{x}} =\mathrm{8}×\mathrm{5}^{\mathrm{3}} \\…
Question Number 198065 by giovi last updated on 09/Oct/23 $$\mathrm{2}^{{x}} +\mathrm{9}+\mathrm{2}^{{x}} =\mathrm{40} \\ $$ Answered by a.lgnaoui last updated on 09/Oct/23 $$\:\mathrm{2}^{\mathrm{x}+\mathrm{1}} =\mathrm{31}\Rightarrow\:\:\left(\:\mathrm{x}+\mathrm{1}\right)\mathrm{ln2}=\mathrm{ln31} \\ $$$$\:\:\mathrm{x}=\frac{\mathrm{ln31}}{\mathrm{ln2}}−\mathrm{1}\:\:\:\:\:\:\:\:\:\boldsymbol{\mathrm{x}}=\frac{\boldsymbol{\mathrm{ln}}\mathrm{31}−\boldsymbol{\mathrm{ln}}\mathrm{2}}{\boldsymbol{\mathrm{ln}}\mathrm{2}}…
Question Number 198067 by necx122 last updated on 09/Oct/23 $${A}\:{father}\:{reduced}\:{the}\:{quantity}\:{of}\:{food} \\ $$$${bought}\:{for}\:{the}\:{family}\:{by}\:\mathrm{10\%}\:{when}\:{he} \\ $$$${found}\:{that}\:{the}\:{cost}\:{of}\:{living}\:{had} \\ $$$${increased}\:{by}\:\mathrm{15\%}.\:{What}\:{is}\:{the}\:{fractional} \\ $$$${increase}\:{in}\:{the}\:{family}\:{food}\:{bill}? \\ $$ Answered by yogamulyadi last updated…