Question Number 210629 by peter frank last updated on 14/Aug/24 Answered by Rasheed.Sindhi last updated on 14/Aug/24 $$\begin{cases}{{x}={a}+\left({a}+{d}\right)+\left({a}+\mathrm{2}{d}\right)+,…+\left({a}+\left({m}−\mathrm{1}\right){d}\right)}\\{{y}=\left({a}+{md}\right)+\left({a}+\left({m}+\mathrm{1}\right){d}\right)+…+\left({a}+\left(\mathrm{2}{m}−\mathrm{1}\right){d}\right)}\\{{z}=\left({a}+\mathrm{2}{md}\right)+\left({a}+\left(\mathrm{2}{m}+\mathrm{1}\right){d}\right)+…+\left({a}+\left(\mathrm{3}{m}−\mathrm{1}\right){d}\right)}\end{cases}\: \\ $$$$\begin{cases}{{x}−{ma}=\left({d}\right)+\left(\mathrm{2}{d}\right)+,…+\left(\left({m}−\mathrm{1}\right){d}\right)}\\{{y}−{ma}=\left({md}\right)+\left(\left({m}+\mathrm{1}\right){d}\right)+…+\left(\left(\mathrm{2}{m}−\mathrm{1}\right){d}\right)}\\{{z}−{ma}=\left(\mathrm{2}{md}\right)+\left(\left(\mathrm{2}{m}+\mathrm{1}\right){d}\right)+…+\left(\left(\mathrm{3}{m}−\mathrm{1}\right){d}\right)}\end{cases}\:\: \\ $$$$\begin{cases}{\frac{{x}−{ma}}{{d}}=\left(\mathrm{1}\right)+\left(\mathrm{2}\right)+,…+\left(\left({m}−\mathrm{1}\right)\right)}\\{\frac{{y}−{ma}}{{d}}=\left({m}\right)+\left(\left({m}+\mathrm{1}\right)\right)+…+\left(\left(\mathrm{2}{m}−\mathrm{1}\right)\right)\:}\\{\frac{{z}−{ma}}{{d}}=\left(\mathrm{2}{m}\right)+\left(\left(\mathrm{2}{m}+\mathrm{1}\right)\right)+…+\left(\left(\mathrm{3}{m}−\mathrm{1}\right)\right)}\end{cases}\: \\ $$$$…\:\: \\…
Question Number 210630 by peter frank last updated on 14/Aug/24 Answered by mm1342 last updated on 14/Aug/24 $${a}_{{n}} ={a}+\left({n}−\mathrm{1}\right){d}\:\:\:\&\:\:{b}_{{n}} =\mathrm{2}^{{n}−\mathrm{1}} {g} \\ $$$${c}_{{n}} ={a}_{{n}} +{b}_{{n}}…
Question Number 210590 by hardmath last updated on 13/Aug/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 210591 by Tawa11 last updated on 13/Aug/24 $$\mathrm{If} \\ $$$$\:\:\:\:\mathrm{a}\:\:+\:\:\mathrm{b}\:\:=\:\:\mathrm{1} \\ $$$$\:\:\:\mathrm{a}^{\mathrm{2}} \:\:+\:\:\mathrm{b}^{\mathrm{2}} \:\:=\:\:\mathrm{2} \\ $$$$\mathrm{then},\:\:\:\:\:\mathrm{a}^{\mathrm{11}} \:\:+\:\:\mathrm{b}^{\mathrm{11}} \:\:=\:\:?? \\ $$ Answered by mr…
Question Number 210587 by mnjuly1970 last updated on 13/Aug/24 $$ \\ $$$$\:\:\:\:\:{f}\left({x}\right)=\:\sqrt{\:\mathrm{13}\:−\mathrm{12}\sqrt{{x}}\:\:}\:+\:\sqrt{\mathrm{25}\:−\mathrm{24}\sqrt{\mathrm{1}−{x}}\:} \\ $$$$ \\ $$$$\:\:\:\:\:\:{find}\::\:\:\:\:\mathrm{M}{in}\:\left(\:{f}\:\right)=? \\ $$$$ \\ $$$$ \\ $$ Commented by Frix…
Question Number 210581 by alusto22 last updated on 13/Aug/24 $$\:\:\begin{cases}{{x}^{\mathrm{2}} +\mathrm{3}{x}−\sqrt{{x}^{\mathrm{2}} +\mathrm{3}{x}−\mathrm{1}\:=\:\mathrm{7}}}\\{\mathrm{2}\sqrt{\mathrm{2}}\:\mathrm{sin}\:{y}\:=\:{x}}\end{cases} \\ $$$$\:\:\:{x}=?\:\:\:\:{and}\:\:\:\:{y}=? \\ $$ Answered by Rasheed.Sindhi last updated on 14/Aug/24 $${x}^{\mathrm{2}} +\mathrm{3}{x}−\sqrt{{x}^{\mathrm{2}}…
Question Number 210608 by peter frank last updated on 13/Aug/24 Commented by peter frank last updated on 13/Aug/24 $$\mathrm{help}\:\left(\mathrm{b}\right) \\ $$ Answered by mr W…
Question Number 210579 by Nimnim111118 last updated on 13/Aug/24 $${Please}…\:{Can}\:{anyone}\:{help}\:{me}.. \\ $$$$ \\ $$$$\:{Find}\:{the}\:{value}\left({s}\right)\:{of}\:{x},\:{if} \\ $$$$\:\:\:\left({x}−\mathrm{2}\right)^{\left({x}^{\mathrm{2}} −\mathrm{2}{x}+\mathrm{4}\right)} =\mathrm{3} \\ $$$$ \\ $$ Commented by mr…
Question Number 210605 by peter frank last updated on 13/Aug/24 Answered by A5T last updated on 13/Aug/24 $${a}=\mathrm{2}^{{x}} ;{b}=\mathrm{2}^{{y}} \Rightarrow{a}+{b}=\mathrm{18};\frac{{a}}{{b}}=\mathrm{5}\Rightarrow{a}=\mathrm{5}{b} \\ $$$$\Rightarrow\mathrm{6}{b}=\mathrm{18}\Rightarrow{b}=\mathrm{3}\Rightarrow{a}=\mathrm{15} \\ $$$$\mathrm{2}^{{x}+{y}} ={ab}=\mathrm{15}×\mathrm{3}=\mathrm{45}…
Question Number 210606 by peter frank last updated on 13/Aug/24 Answered by A5T last updated on 14/Aug/24 $$\mathrm{3}\left({y}^{{log}_{\mathrm{5}} \mathrm{2}} \right)+\left({y}^{{log}_{{y}} \mathrm{2}×{log}_{\mathrm{5}} {y}} \right)=\mathrm{3}\left({y}^{{log}_{\mathrm{5}} \mathrm{2}} \right)+{y}^{{log}_{\mathrm{5}}…