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1-3-x-2-x-2-4x-dx-

Question Number 198948 by ArifinTanjung last updated on 26/Oct/23 $$\int_{\mathrm{1}} ^{\mathrm{3}} \frac{\mathrm{x}−\mathrm{2}}{\mathrm{x}^{\mathrm{2}} −\mathrm{4x}}\:\mathrm{dx}=\:…. \\ $$ Answered by ajfour last updated on 26/Oct/23 $${I}=\frac{\mathrm{1}}{\mathrm{2}}\int_{−\mathrm{1}} ^{\:\mathrm{1}} \frac{\mathrm{2}{tdt}}{{t}^{\mathrm{2}}…

5-4-3-2-

Question Number 198949 by ArifinTanjung last updated on 26/Oct/23 $$\:\:\frac{\mathrm{5}!×\mathrm{4}!}{\mathrm{3}!×\mathrm{2}!}\:=\:….\:\: \\ $$ Answered by Rasheed.Sindhi last updated on 26/Oct/23 $$\:\:\frac{\mathrm{5}!×\mathrm{4}!}{\mathrm{3}!×\mathrm{2}!}\:=\:\frac{\mathrm{5}!×\cancel{\overset{\mathrm{2}} {\mathrm{4}}}×\cancel{\mathrm{3}!}}{\cancel{\mathrm{3}!}×\cancel{\underset{\mathrm{1}} {\mathrm{2}}}×\mathrm{1}}=\mathrm{2}×\mathrm{5}! \\ $$$$ \\…

3x-2y-6-2x-3y-6-x-and-y-

Question Number 198950 by ArifinTanjung last updated on 26/Oct/23 $$\mathrm{3x}+\mathrm{2y}=\mathrm{6} \\ $$$$\mathrm{2x}+\mathrm{3y}=\mathrm{6}\:\rightarrow\:\mathrm{x}\:\mathrm{and}\:\mathrm{y}\:=…? \\ $$ Answered by Rasheed.Sindhi last updated on 26/Oct/23 $$\begin{cases}{\mathrm{3x}+\mathrm{2y}=\mathrm{6}}\\{\mathrm{2x}+\mathrm{3y}=\mathrm{6}}\end{cases}\:\:\:\:\:\:\:\:\:\mathrm{x},\mathrm{y}=? \\ $$$$\mathrm{Adding}:\:\:\mathrm{5}\left(\mathrm{x}+\mathrm{y}\right)=\mathrm{12}\Rightarrow\mathrm{x}+\mathrm{y}=\frac{\mathrm{12}}{\mathrm{5}} \\…

Question-199015

Question Number 199015 by Tawa11 last updated on 26/Oct/23 Answered by Rasheed.Sindhi last updated on 26/Oct/23 $$\sqrt{{a}−{x}}\:+\sqrt{{b}−{x}}\:+\sqrt{{c}−{x}}\:=\mathrm{0} \\ $$$$\sqrt{{a}−{x}}\:=\mathrm{0}\:\wedge\:\sqrt{{b}−{x}}\:=\mathrm{0}\:\wedge\:\sqrt{{c}−{x}}\:=\mathrm{0} \\ $$$${x}={a}={b}={c} \\ $$$$\left({a}+{b}+{c}+\mathrm{3}{x}\right)\left({a}+{b}+{c}−{x}\right)=\mathrm{4}\left({bc}+{ca}+{ab}\right) \\ $$$$\left({x}+{x}+{x}+\mathrm{3}{x}\right)\left({x}+{x}+{x}−{x}\right)=\mathrm{4}\left({x}.{x}+{x}.{x}+{x}.{x}\right)…

8-48-

Question Number 198951 by ArifinTanjung last updated on 26/Oct/23 $$\sqrt{\mathrm{8}+\sqrt{\mathrm{48}}\:}=….? \\ $$ Commented by mr W last updated on 26/Oct/23 $${are}\:{you}\:{serious}? \\ $$$${you}\:{ask}\:{both}\:{this}\:\sqrt{\mathrm{8}+\sqrt{\mathrm{48}}\:}=…. \\ $$$${and}\:{this}\:\int_{\mathrm{1}}…

Sum-of-two-irrational-numbers-is-1-less-than-their-product-and-8-less-than-their-sum-of-squares-Find-the-larger-of-the-two-numbers-

Question Number 199011 by necx122 last updated on 26/Oct/23 $${Sum}\:{of}\:{two}\:{irrational}\:{numbers}\:{is}\:\mathrm{1} \\ $$$${less}\:{than}\:{their}\:{product},\:{and}\:\mathrm{8}\:{less}\:{than} \\ $$$${their}\:{sum}\:{of}\:{squares}.\:{Find}\:{the}\:{larger} \\ $$$${of}\:{the}\:{two}\:{numbers}. \\ $$ Commented by nikif99 last updated on 27/Oct/23…

Given-that-ABCD-is-a-trapezium-such-that-AD-BC-The-centroid-of-ABD-lies-on-the-bisector-of-BCD-Show-that-the-centroid-of-ABC-lies-on-the-bisector-of-ADC-

Question Number 199006 by adhigenz last updated on 26/Oct/23 $$\mathrm{Given}\:\mathrm{that}\:{ABCD}\:\mathrm{is}\:\mathrm{a}\:\mathrm{trapezium}\:\mathrm{such}\:\mathrm{that}\:{AD}//{BC}. \\ $$$$\mathrm{The}\:\mathrm{centroid}\:\mathrm{of}\:\bigtriangleup{ABD}\:\mathrm{lies}\:\mathrm{on}\:\mathrm{the}\:\mathrm{bisector}\:\mathrm{of}\:\angle{BCD}. \\ $$$$\mathrm{Show}\:\mathrm{that}\:\mathrm{the}\:\mathrm{centroid}\:\mathrm{of}\:\bigtriangleup{ABC}\:\mathrm{lies}\:\mathrm{on}\:\mathrm{the}\:\mathrm{bisector}\:\mathrm{of}\:\angle{ADC}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com