Question Number 198754 by essaad last updated on 24/Oct/23 Answered by Frix last updated on 24/Oct/23 $${x}^{\frac{\mathrm{1}}{\mathrm{2}}} +{x}^{\frac{\mathrm{2}}{\mathrm{3}}} =\mathrm{12} \\ $$$$\mathrm{We}\:\mathrm{can}\:\mathrm{only}\:\mathrm{approximate} \\ $$$${x}\approx\mathrm{20}.\mathrm{4490371248} \\ $$…
Question Number 198684 by cortano12 last updated on 23/Oct/23 $$\:\cancel{\zeta} \\ $$ Answered by Red1ight last updated on 23/Oct/23 $$\mathrm{24},\mathrm{88} \\ $$$${A}=\mathrm{24}×\mathrm{88}=\mathrm{2112} \\ $$$${P}=\mathrm{24}+\mathrm{88}=\mathrm{112} \\…
Question Number 198749 by ajfour last updated on 23/Oct/23 $${Find}\:{area}\:{bounded}\:{by}\:{curve}\:{below} \\ $$$${cx}^{\mathrm{3}} +{c}^{\mathrm{2}} +{y}\left({y}+\mathrm{1}\right)^{\mathrm{2}} ={x}^{\mathrm{2}} {y}+{cx}\left(\mathrm{3}{y}+\mathrm{1}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 198743 by mnjuly1970 last updated on 23/Oct/23 Answered by witcher3 last updated on 24/Oct/23 $$\left(\mathrm{A}−\mathrm{I}\right)\left(\mathrm{A}−\mathrm{I}\right)^{−} =\mathrm{I} \\ $$$$=\mathrm{A}\left(\mathrm{A}−\mathrm{I}\right)−\mathrm{I}\left(\mathrm{A}−\mathrm{I}\right)^{−} = \\ $$$$\mathrm{A}\left(\mathrm{A}−\mathrm{I}\right)^{−} −\left(\mathrm{A}−\mathrm{I}\right)^{−} =\mathrm{I}…
Question Number 198731 by cortano12 last updated on 23/Oct/23 Commented by cortano12 last updated on 24/Oct/23 $$\mathrm{what}\:\mathrm{this}\:\mathrm{formula}\:? \\ $$ Commented by mr W last updated…
Question Number 198692 by BHOOPENDRA last updated on 23/Oct/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 198695 by universe last updated on 23/Oct/23 $$\:\:\:\:\:\:\int_{\mathrm{0}} ^{\infty} \frac{\mathrm{e}^{\mathrm{at}} −\mathrm{e}^{−\mathrm{at}} }{\mathrm{e}^{\pi\mathrm{t}} −\mathrm{e}^{−\pi\mathrm{t}} }\:\mathrm{dt}\:\:\:=\:\:\:?? \\ $$ Answered by witcher3 last updated on 25/Oct/23…
Question Number 198688 by tri26112004 last updated on 23/Oct/23 $${y}''\:+\:\frac{\mathrm{2}}{{x}}.{y}'\:+\:{y}\:=\:\mathrm{0} \\ $$$${y}=¿ \\ $$ Answered by witcher3 last updated on 23/Oct/23 $$\mathrm{xy}=\mathrm{z} \\ $$$$\mathrm{xy}'+\mathrm{y}=\mathrm{z}' \\…
Question Number 198722 by MathedUp last updated on 23/Oct/23 $$\mathrm{I}\:\mathrm{have}\:\mathrm{one}\:\mathrm{question}. \\ $$$$\mathrm{What}\:\mathrm{is}\:\mathrm{Exact}\:\mathrm{definition}\:\mathrm{of}\:\mathrm{the}\:\mathrm{Vector}\:\mathrm{Field}\:\mathrm{Form}\:\mathrm{Of}\:\mathrm{an}\:\mathrm{Eletric}\:\mathrm{Field}?? \\ $$$$\mathrm{for}\:\mathrm{exmple}.. \\ $$$$\mathrm{Vector}\:\mathrm{Field}\: \\ $$$$\hat {\boldsymbol{\mathrm{v}}}\left({x},{y},{z}\right)={yz}\hat {\boldsymbol{\mathrm{e}}}_{\mathrm{1}} +{xz}\hat {\boldsymbol{\mathrm{e}}}_{\mathrm{2}} +{xy}\hat {\boldsymbol{\mathrm{e}}}_{\mathrm{3}} \\…
Question Number 198558 by hardmath last updated on 22/Oct/23 Commented by mr W last updated on 22/Oct/23 $${hardmath}={shrinava}\:? \\ $$ Answered by mr W last…