Question Number 196972 by otchereabdullai@gmail.com last updated on 05/Sep/23 Answered by Frix last updated on 05/Sep/23 $${t}=\mathrm{tan}\:\theta \\ $$$$\frac{\mathrm{2}}{{t}^{\mathrm{2}} +\mathrm{1}}\left(\mathrm{14}{t}^{\mathrm{2}} +\mathrm{9}{t}−\mathrm{14}\right)=\mathrm{0} \\ $$$${t}=−\frac{\mathrm{9}}{\mathrm{28}}\pm\frac{\sqrt{\mathrm{865}}}{\mathrm{28}} \\ $$$$\theta=\mathrm{tan}^{−\mathrm{1}}…
Question Number 196973 by sonukgindia last updated on 05/Sep/23 Answered by Frix last updated on 05/Sep/23 $$\mathrm{We}\:\mathrm{don}'\mathrm{t}\:\mathrm{need}\:\mathrm{the}\:\mathrm{approximate}\:\mathrm{solution}. \\ $$$${x}^{\mathrm{5}} −\mathrm{5}{x}−\mathrm{3}=\mathrm{0} \\ $$$$\left({x}^{\mathrm{2}} −{x}−\mathrm{1}\right)\left({x}^{\mathrm{3}} +{x}^{\mathrm{2}} +\mathrm{2}{x}+\mathrm{3}\right)=\mathrm{0}…
Question Number 196968 by sonukgindia last updated on 05/Sep/23 Answered by MM42 last updated on 05/Sep/23 $${if}\:\:{x},{y}\in\:\mathbb{R} \\ $$$$\begin{cases}{\mathrm{5}{s}−{p}=\mathrm{10}+\mathrm{7}\sqrt{\mathrm{3}}}\\{{s}^{\mathrm{2}} −\mathrm{2}{p}=\mathrm{7}}\end{cases} \\ $$$$\Rightarrow{s}^{\mathrm{2}} +\mathrm{10}{s}−\mathrm{27}−\mathrm{14}\sqrt{\mathrm{3}}=\mathrm{0} \\ $$$$\Rightarrow{s}=\mathrm{2}+\sqrt{\mathrm{3}\:}\Rightarrow{p}=\mathrm{2}\sqrt{\mathrm{3}}\:…
Question Number 197001 by josemate19 last updated on 05/Sep/23 $$\:\underset{{n}\rightarrow\infty} {\mathrm{lim}}\underset{−\pi} {\overset{\:\:\:\pi} {\int}}\frac{{n}!\mathrm{2}^{\mathrm{2}{ncos}\left(\phi\right)} }{\underset{{k}=\mathrm{1}} {\overset{{n}} {\prod}}\left(\mathrm{2}{ne}^{{i}\phi} −{k}\right)}{d}\phi \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 197002 by hardmath last updated on 05/Sep/23 Commented by Frix last updated on 06/Sep/23 $$\mathrm{See}\:\mathrm{my}\:\mathrm{answer}\:\mathrm{to}\:\mathrm{question}\:\mathrm{197011} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 197003 by hardmath last updated on 05/Sep/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 196971 by dimentri last updated on 05/Sep/23 $$\:\:{solve}\:\begin{cases}{\mathrm{3}{x}^{\mathrm{2}} −\mathrm{9}{y}=\mathrm{1}}\\{\mathrm{3}{y}^{\mathrm{2}} −\mathrm{9}{x}=\mathrm{0}}\end{cases} \\ $$ Answered by Frix last updated on 05/Sep/23 $${y}=\frac{\mathrm{3}{x}^{\mathrm{2}} −\mathrm{1}}{\mathrm{9}} \\ $$$${x}^{\mathrm{4}}…
Question Number 196964 by Mingma last updated on 05/Sep/23 Answered by Rasheed.Sindhi last updated on 05/Sep/23 $${x}+{y}=−\mathrm{9}\:\wedge\:{x}+\mathrm{2}{y}=−\mathrm{25} \\ $$$$\Rightarrow{x}+\mathrm{2}\left(−\mathrm{9}−{x}\right)=−\mathrm{25} \\ $$$$\:\:\:\:{x}−\mathrm{2}{x}=−\mathrm{25}+\mathrm{18}=−\mathrm{7} \\ $$$$\:\:\:\:\:\:\:{x}=\mathrm{7} \\ $$…
Question Number 196965 by sonukgindia last updated on 05/Sep/23 Answered by qaz last updated on 05/Sep/23 $$\int_{\mathrm{0}} ^{\infty} \frac{{dx}}{\:\sqrt{{x}}\left(\mathrm{1}+{x}\right)\left(\mathrm{1}+\sqrt[{\mathrm{4}}]{{x}}\right)}\overset{{x}\rightarrow{x}^{\mathrm{4}} } {=}\int_{\mathrm{0}} ^{\infty} \frac{\mathrm{4}{xdx}}{\left(\mathrm{1}+{x}^{\mathrm{4}} \right)\left(\mathrm{1}+{x}\right)} \\…
Question Number 196992 by MATHEMATICSAM last updated on 05/Sep/23 $$\mathrm{If}\:\mathrm{A}\left({a}^{\mathrm{2}} ,\:\mathrm{2}{a}\right),\:\mathrm{B}\left(\frac{\mathrm{1}}{{a}^{\mathrm{2}} },\:\frac{−\:\mathrm{2}}{{a}}\right)\:\mathrm{and}\:\mathrm{S}\left(\mathrm{1},\:\mathrm{0}\right)\: \\ $$$$\mathrm{are}\:\mathrm{three}\:\mathrm{points}\:\mathrm{then}\:\mathrm{prove}\:\mathrm{that}, \\ $$$$\frac{\mathrm{1}}{\mathrm{SA}}\:+\:\frac{\mathrm{1}}{\mathrm{SB}}\:=\:\mathrm{1}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com