Question Number 196971 by dimentri last updated on 05/Sep/23 $$\:\:{solve}\:\begin{cases}{\mathrm{3}{x}^{\mathrm{2}} −\mathrm{9}{y}=\mathrm{1}}\\{\mathrm{3}{y}^{\mathrm{2}} −\mathrm{9}{x}=\mathrm{0}}\end{cases} \\ $$ Answered by Frix last updated on 05/Sep/23 $${y}=\frac{\mathrm{3}{x}^{\mathrm{2}} −\mathrm{1}}{\mathrm{9}} \\ $$$${x}^{\mathrm{4}}…
Question Number 196964 by Mingma last updated on 05/Sep/23 Answered by Rasheed.Sindhi last updated on 05/Sep/23 $${x}+{y}=−\mathrm{9}\:\wedge\:{x}+\mathrm{2}{y}=−\mathrm{25} \\ $$$$\Rightarrow{x}+\mathrm{2}\left(−\mathrm{9}−{x}\right)=−\mathrm{25} \\ $$$$\:\:\:\:{x}−\mathrm{2}{x}=−\mathrm{25}+\mathrm{18}=−\mathrm{7} \\ $$$$\:\:\:\:\:\:\:{x}=\mathrm{7} \\ $$…
Question Number 196965 by sonukgindia last updated on 05/Sep/23 Answered by qaz last updated on 05/Sep/23 $$\int_{\mathrm{0}} ^{\infty} \frac{{dx}}{\:\sqrt{{x}}\left(\mathrm{1}+{x}\right)\left(\mathrm{1}+\sqrt[{\mathrm{4}}]{{x}}\right)}\overset{{x}\rightarrow{x}^{\mathrm{4}} } {=}\int_{\mathrm{0}} ^{\infty} \frac{\mathrm{4}{xdx}}{\left(\mathrm{1}+{x}^{\mathrm{4}} \right)\left(\mathrm{1}+{x}\right)} \\…
Question Number 196992 by MATHEMATICSAM last updated on 05/Sep/23 $$\mathrm{If}\:\mathrm{A}\left({a}^{\mathrm{2}} ,\:\mathrm{2}{a}\right),\:\mathrm{B}\left(\frac{\mathrm{1}}{{a}^{\mathrm{2}} },\:\frac{−\:\mathrm{2}}{{a}}\right)\:\mathrm{and}\:\mathrm{S}\left(\mathrm{1},\:\mathrm{0}\right)\: \\ $$$$\mathrm{are}\:\mathrm{three}\:\mathrm{points}\:\mathrm{then}\:\mathrm{prove}\:\mathrm{that}, \\ $$$$\frac{\mathrm{1}}{\mathrm{SA}}\:+\:\frac{\mathrm{1}}{\mathrm{SB}}\:=\:\mathrm{1}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 196940 by sonukgindia last updated on 04/Sep/23 Answered by MM42 last updated on 04/Sep/23 $${sin}\mathrm{8}{x}=\mathrm{8}{sinxcosxcos}\mathrm{2}{xcos}\mathrm{4}{x} \\ $$$$\Rightarrow{I}=\mathrm{2}\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} {cosxcos}\mathrm{2}{xcos}\mathrm{4}{xdx} \\ $$$${cosxcos}\mathrm{2}{xcos}\mathrm{4}{x}=\frac{\mathrm{1}}{\mathrm{4}}\left({cos}\mathrm{7}{x}+{cos}\mathrm{5}{x}+{cos}\mathrm{3}{x}+{cosx}\right) \\ $$$$\Rightarrow{I}=\frac{\mathrm{1}}{\mathrm{2}}\left(\frac{\mathrm{1}}{\mathrm{7}}{sin}\mathrm{7}{x}+\frac{\mathrm{1}}{\mathrm{5}}{sin}\mathrm{5}{x}+\frac{\mathrm{1}}{\mathrm{3}}{sin}\mathrm{3}{x}+{sinx}\right)\mid_{\mathrm{0}}…
Question Number 196957 by otchereabdullai@gmail.com last updated on 04/Sep/23 Answered by dimentri last updated on 05/Sep/23 $$\:\:\:\:\frac{\mathrm{9}!}{{x}!\:\left(\mathrm{9}−{x}\right)!}\:=\:\mathrm{4}\left(\frac{\mathrm{7}!}{\left({x}−\mathrm{1}\right)!\left(\mathrm{8}−{x}\right)!}\right) \\ $$$$\:\:\:\:\frac{\mathrm{72}}{{x}\left(\mathrm{9}−{x}\right)}\:=\:\mathrm{4} \\ $$$$\:\:\:\:\mathrm{18}=\:\mathrm{9}{x}−{x}^{\mathrm{2}} \\ $$$$\:\:\:\:\:{x}^{\mathrm{2}} −\mathrm{9}{x}+\mathrm{18}=\mathrm{0} \\…
Question Number 196953 by Khalmohmmad last updated on 04/Sep/23 Answered by MM42 last updated on 05/Sep/23 $${p}×\mathrm{2}^{{n}} =\mathrm{15}\Rightarrow{p}=\mathrm{15\&}{n}=\mathrm{0}\Rightarrow\mathrm{2}{p}−\mathrm{3}{n}=\mathrm{30} \\ $$ Terms of Service Privacy Policy…
Question Number 196954 by Khalmohmmad last updated on 04/Sep/23 Answered by MM42 last updated on 05/Sep/23 $$\left.\mathrm{1}\right){x}×\mathrm{2}^{{m}} ×\mathrm{5}^{{n}} =\mathrm{24}\Rightarrow{n}=\mathrm{0} \\ $$$$\left.{a}\right){x}×\mathrm{2}^{{m}} =\mathrm{24}×\mathrm{1}\Rightarrow{x}=\mathrm{24\&}{m}=\mathrm{0}\Rightarrow\mathrm{2}{x}+\mathrm{3}{n}−{m}=\mathrm{48} \\ $$$$\left.{b}\right){x}×\mathrm{2}^{{m}} =\mathrm{12}×\mathrm{2}\Rightarrow{x}=\mathrm{12\&}{m}=\mathrm{1}\Rightarrow\mathrm{2}{x}+\mathrm{3}{n}−{m}=\mathrm{23}…
Question Number 196938 by sonukgindia last updated on 04/Sep/23 Answered by AST last updated on 04/Sep/23 $${xy}+{yz}+{zx}\leqslant\mathrm{147}\left({equality}\:{when}\:{x}={y}={z}=\underset{−} {+}\mathrm{7}\right) \\ $$$$\left(\frac{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} }{\mathrm{3}}\right)\geqslant\left(\frac{{x}+{y}+{z}}{\mathrm{3}}\right)^{\mathrm{2}} \Rightarrow\mathrm{3}\left(\mathrm{147}\right)\geqslant\left({x}+{y}+{z}\right)^{\mathrm{2}} \\…
Question Number 196955 by mokys last updated on 04/Sep/23 Commented by mokys last updated on 05/Sep/23 $$????? \\ $$ Terms of Service Privacy Policy Contact:…