Question Number 196780 by Tawa11 last updated on 31/Aug/23 A tugboat is travelling from Asaba to Onitsha across the River Niger with a resultant velocity…
Question Number 196774 by BaliramKumar last updated on 31/Aug/23 $$ \\ $$A man standing on top of Burj Khalifa. If the height of Burj Khalifa…
Question Number 196775 by Tawa11 last updated on 31/Aug/23 A stream is flowing at 0.75ms−¹ and a boat heading perpendicular for the stream landed at…
Question Number 196770 by Amidip last updated on 31/Aug/23 Commented by Frix last updated on 31/Aug/23 $$“\mathbb{N}\mathrm{atural}\:\mathrm{numbers}\:\left(\mathbb{Z}\right)''\:−\:\mathrm{really}?!? \\ $$ Commented by Frix last updated on…
Question Number 196734 by sonukgindia last updated on 30/Aug/23 Answered by qaz last updated on 31/Aug/23 $${y}''{y}+\left({y}'\right)^{\mathrm{2}} =\left({y}'{y}\right)'=\frac{\mathrm{1}}{\mathrm{2}}\left(\left({y}^{\mathrm{2}} \right)'\right)'=\mathrm{3}{x} \\ $$$$\Rightarrow\left({y}^{\mathrm{2}} \right)'=\mathrm{3}{x}^{\mathrm{2}} +{C}_{\mathrm{1}} \:\:\:\:{y}^{\mathrm{2}} ={x}^{\mathrm{3}}…
Question Number 196735 by sonukgindia last updated on 30/Aug/23 Answered by qaz last updated on 31/Aug/23 $$\int_{\mathrm{0}} ^{\mathrm{1}} \frac{{x}^{\mathrm{7}} −{x}^{\mathrm{3}} }{{lnx}}{dx}=\int_{\mathrm{0}} ^{\mathrm{1}} {dx}\int_{\mathrm{3}} ^{\mathrm{7}} {x}^{{t}}…
Question Number 196728 by Amidip last updated on 30/Aug/23 Commented by mr W last updated on 30/Aug/23 $${Q}#\mathrm{196544}? \\ $$ Answered by Frix last updated…
Question Number 196730 by hardmath last updated on 30/Aug/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 196725 by sonukgindia last updated on 30/Aug/23 Answered by Frix last updated on 30/Aug/23 $$\left({c}\right) \\ $$$${t}^{\mathrm{8}} +\frac{\mathrm{1}}{{t}^{\mathrm{8}} }={m} \\ $$$${t}^{\mathrm{8}} +\frac{\mathrm{1}}{{t}^{\mathrm{8}} }+\mathrm{2}={m}+\mathrm{2}…
Question Number 196723 by mr W last updated on 30/Aug/23 $${prove}\:{that}\:{the}\:{curve}\: \\ $$$$\sqrt{\left({x}−\mathrm{1}\right)^{\mathrm{2}} +{y}^{\mathrm{2}} }+\sqrt{\left({x}+\mathrm{1}\right)^{\mathrm{2}} +{y}^{\mathrm{2}} }=\mathrm{4}\: \\ $$$${is}\:{an}\:{ellipse}\:{and}\:{find}\:{its}\:{semi} \\ $$$${major}\:{axis}\:{and}\:{semi}\:{minor}\:{axis}. \\ $$ Answered by…