Question Number 196691 by justenspi last updated on 29/Aug/23 $$ \\ $$Can someone recommend Calculus book , But I prefer if the book isn't boring…
Question Number 196659 by sonukgindia last updated on 29/Aug/23 Commented by Rasheed.Sindhi last updated on 29/Aug/23 $${Too}\:{many}\:{questions}\:{per}\:{single}\:{post}! \\ $$ Commented by Rasheed.Sindhi last updated on…
Question Number 196682 by sonukgindia last updated on 29/Aug/23 Answered by mr W last updated on 28/Sep/23 $$\mathrm{0}.\mathrm{006}×\mathrm{0}.\mathrm{98}+\mathrm{0}.\mathrm{994}×\mathrm{0}.\mathrm{8}=\mathrm{0}.\mathrm{81\%}\:\checkmark \\ $$ Terms of Service Privacy Policy…
Question Number 196683 by MATHEMATICSAM last updated on 29/Aug/23 $$\mathrm{If}\:{y}\:=\:\frac{{e}^{{x}} \:−\:{e}^{−\:{x}} }{{e}^{{x}} \:+\:{e}^{−\:{x}} }\:\mathrm{then}\:\mathrm{show}\:\mathrm{that} \\ $$$${x}\:=\:\frac{\mathrm{1}}{\mathrm{2}}\mathrm{log}_{{e}} \left(\frac{\mathrm{1}\:+\:{y}}{\mathrm{1}\:−\:{y}}\right). \\ $$ Answered by Frix last updated on…
Question Number 196676 by Rasheed.Sindhi last updated on 29/Aug/23 $${If}\:\overline {{ab}}\:\centerdot\:\overline {{cd}}=\mathrm{899}\:,\:{find}\:\Omega=\:\overline {{abcd}}\:+\:\overline {{cdab}} \\ $$ Commented by Rasheed.Sindhi last updated on 29/Aug/23 $${Q}#\mathrm{196659} \\…
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Question Number 196672 by Rasheed.Sindhi last updated on 29/Aug/23 $${Find}\:{all}\:\Omega\overline {={abcdef}\:\:},\:{such}\:{that} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:{abcdef}={abc}+{def} \\ $$ Commented by Rasheed.Sindhi last updated on 29/Aug/23 $${Q}#\mathrm{196659} \\ $$…
Question Number 196705 by josemate19 last updated on 29/Aug/23 $$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\underset{−\infty} {\overset{\:\:\:\:\infty} {\int}}\frac{{n}!\mathrm{2}^{\mathrm{2}{ncos}\left(\phi\right)} }{\underset{{k}=\mathrm{1}} {\overset{\infty} {\prod}}\left(\mathrm{2}{ne}^{{i}\phi} −{k}\right)}{d}\phi \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 196674 by Erico last updated on 29/Aug/23 $$\mathrm{prove}\:\mathrm{that}\: \\ $$$$\underset{\mathrm{n}\rightarrow+\infty} {\mathrm{lim}}\:\left(−\mathrm{1}\right)^{\mathrm{n}−\mathrm{1}} +\underset{\mathrm{p}=\mathrm{2}} {\overset{\mathrm{n}} {\sum}}\left(−\mathrm{1}\right)^{\mathrm{p}} \mathrm{pln}\left(\frac{\mathrm{p}+\mathrm{1}}{\mathrm{p}−\mathrm{1}}\right)=\mathrm{ln}\left(\pi\right) \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 196637 by sonukgindia last updated on 28/Aug/23 Answered by AST last updated on 28/Aug/23 $${a}=\sqrt{\mathrm{12}−\sqrt{{m}}};{b}=\sqrt{\mathrm{12}+\sqrt{{m}}},{a}^{\mathrm{2}} +{b}^{\mathrm{2}} =\mathrm{24} \\ $$$${ab}=\sqrt{\mathrm{144}−{m}};\left({a}+{b}\right)^{\mathrm{2}} =\mathrm{24}+\mathrm{2}\sqrt{\mathrm{144}−{m}} \\ $$$$\Rightarrow{a}+{b}=\sqrt{\mathrm{24}+\mathrm{2}\sqrt{\mathrm{144}−{m}}}={n} \\…