Question Number 197819 by mnjuly1970 last updated on 30/Sep/23 $$ \\ $$$$\:\:\:\:\:\:{find}\:{the}\:{value}\:{of}\:\:: \\ $$$$\:\:\:\:\:\:\boldsymbol{\phi}\:=\:\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\:\left(−\mathrm{1}\right)^{{n}−\mathrm{1}} \:{H}_{\:\mathrm{2}{n}} }{{n}}\:=\:? \\ $$$${where},{H}_{{n}} =\mathrm{1}+\frac{\mathrm{1}}{\mathrm{2}}\:+\frac{\mathrm{1}}{\mathrm{3}}\:+…+\frac{\mathrm{1}}{{n}} \\ $$ Answered by…
Question Number 197843 by a.lgnaoui last updated on 30/Sep/23 $$\boldsymbol{\mathrm{Exercice}}\:\:\mathrm{2} \\ $$ Commented by a.lgnaoui last updated on 30/Sep/23 Commented by witcher3 last updated on…
Question Number 197811 by Noorzai last updated on 30/Sep/23 Commented by mr W last updated on 30/Sep/23 $${you}\:{didn}'{t}\:{ask}\:{a}\:{question}!\:{what}'{s}\:{your} \\ $$$${question}? \\ $$ Commented by mokys…
Question Number 197838 by hardmath last updated on 30/Sep/23 Answered by MM42 last updated on 30/Sep/23 $$\frac{\mathrm{2}^{\mathrm{49}} }{\mathrm{2}^{\mathrm{49}} +\mathrm{1}}+\frac{\mathrm{2}^{\mathrm{48}} }{\mathrm{2}^{\mathrm{48}} +\mathrm{1}}+…+\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{48}} +\mathrm{1}}+\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{49}} +\mathrm{1}} \\ $$$$=\mathrm{1}+\mathrm{1}+…+\mathrm{1}=\:\mathrm{49}\:\checkmark…
Question Number 197832 by mathlove last updated on 30/Sep/23 $$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\frac{\mathrm{2}+\sqrt{{cosx}}}{−\mathrm{1}+\sqrt{{cosx}}}=? \\ $$ Answered by MM42 last updated on 30/Sep/23 $${let}\:\:{f}\left({x}\right)=\frac{\mathrm{2}+\sqrt{{cosx}}}{−\mathrm{1}+\sqrt{{cosx}}} \\ $$$${for}\:\:{a}_{{n}} =\mathrm{2}{n}\pi\Rightarrow{lim}_{{n}\rightarrow\infty} \:{f}\left({a}_{{n}}…
Question Number 197834 by ajfour last updated on 30/Sep/23 Answered by mr W last updated on 01/Oct/23 Commented by mr W last updated on 03/Oct/23…
Question Number 197805 by Noorzai last updated on 29/Sep/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 197802 by cortano12 last updated on 29/Sep/23 $$\:\:\:\mathrm{I}=\underset{−\mathrm{2}} {\overset{\mathrm{6}} {\int}}\:\frac{\mid\mathrm{x}−\mathrm{1}\mid}{\mathrm{x}−\mathrm{1}}\:\mathrm{dx}\:=? \\ $$ Answered by MM42 last updated on 29/Sep/23 $${I}=\int_{−\mathrm{2}} ^{\mathrm{1}} −{dx}+\int_{\mathrm{1}} ^{\mathrm{6}}…
Question Number 197808 by mokys last updated on 29/Sep/23 $${prove}\:\underset{{n}\rightarrow\infty} {{lim}}\:{x}^{{n}} \:=\:\mathrm{0}\:\:\:\:{when}\:\mid{x}\mid\:<\:\mathrm{1} \\ $$ Commented by Noorzai last updated on 30/Sep/23 $${please}\:{give}\:{more}\:{information}\: \\ $$ Answered…
Question Number 197795 by cortano12 last updated on 29/Sep/23 Answered by AST last updated on 29/Sep/23 $${Let}\:{y}={px};{x}\left({p}+\mathrm{1}\right)={x}^{\mathrm{2}} \left(\mathrm{1}+{p}^{\mathrm{2}} \right)\:;{x}\neq\mathrm{0}\Rightarrow{p}^{\mathrm{2}} ={p}\Rightarrow{p}=\mathrm{0}\:{or}\:\mathrm{1} \\ $$$${p}=\mathrm{0}\Rightarrow{y}=\mathrm{0}\Rightarrow{x}^{\mathrm{2}} ={x}\Rightarrow{x}=\mathrm{1} \\ $$$${p}=\mathrm{1}\Rightarrow\mathrm{2}{x}=\mathrm{2}{x}^{\mathrm{2}}…