Author: Tinku Tara

Question Number 225098 by Ark55 last updated on 17/Oct/25 Answered by Rasheed.Sindhi last updated on 17/Oct/25 $$\mathrm{5}{x}+\frac{\mathrm{1}}{{x}}=\mathrm{6} \\ $$$$\left(\mathrm{5}{x}+\frac{\mathrm{1}}{{x}}=\mathrm{6}\right)^{\mathrm{2}} \\ $$$$\mathrm{25}{x}^{\mathrm{2}} +\mathrm{10}+\frac{\mathrm{1}}{{x}^{\mathrm{2}} }=\mathrm{36} \\ $$$$\mathrm{25}{x}^{\mathrm{2}}…

Question Number 225075 by Ark55 last updated on 17/Oct/25 Answered by Frix last updated on 17/Oct/25 $$\mathrm{Obviously}\:{x}=\mathrm{1} \\ $$$$\:\:\:\:\:\mathrm{because}\:\mathrm{5}+\mathrm{1}=\mathrm{6}\:\mathrm{and}\:\mathrm{25}+\mathrm{1}=\mathrm{26} \\ $$$$\mathrm{or}\:{x}=\frac{\mathrm{1}}{\mathrm{5}} \\ $$$$\:\:\:\:\:\mathrm{because}\:\mathrm{1}+\mathrm{5}=\mathrm{6}\:\mathrm{and}\:\mathrm{1}+\mathrm{25}=\mathrm{26} \\ $$…

Question Number 224989 by CrispyXYZ last updated on 15/Oct/25 $$\mathrm{Calculate} \\ $$$${D}_{{n}} =\begin{vmatrix}{{x}_{\mathrm{1}} +{a}_{\mathrm{1}} ^{\mathrm{2}} }&{{a}_{\mathrm{1}} {a}_{\mathrm{2}} }&{\ldots}&{{a}_{\mathrm{1}} {a}_{{n}} }\\{{a}_{\mathrm{2}} {a}_{\mathrm{1}} }&{{x}_{\mathrm{2}} +{a}_{\mathrm{2}} ^{\mathrm{2}} }&{\ldots}&{{a}_{\mathrm{2}}…