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Author: Tinku Tara

lim-n-1-n-1-2-1-n-1-2-2-n-1-2-3-n-1-2-n-n-

Question Number 196471 by Tawa11 last updated on 25/Aug/23 $$\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}}\:\frac{\mathrm{1}}{\mathrm{n}}\left(\frac{\mathrm{1}}{\mathrm{2}\:\:+\:\:\frac{\mathrm{1}}{\mathrm{n}}}\:\:+\:\:\frac{\mathrm{1}}{\mathrm{2}\:\:+\:\:\frac{\mathrm{2}}{\mathrm{n}}}\:\:+\:\:\frac{\mathrm{1}}{\mathrm{2}\:\:+\:\:\frac{\mathrm{3}}{\mathrm{n}}}\:\:+\:\:..\:\:+\:\:\frac{\mathrm{1}}{\mathrm{2}\:\:+\:\:\frac{\mathrm{n}}{\mathrm{n}}}\right) \\ $$ Answered by mr W last updated on 25/Aug/23 $$=\int_{\mathrm{0}} ^{\mathrm{1}} \frac{{dx}}{\mathrm{2}+{x}} \\…

Question-196467

Question Number 196467 by sonukgindia last updated on 25/Aug/23 Answered by mr W last updated on 25/Aug/23 $${y}'\mathrm{ln}\:{y}={y} \\ $$$${y}'=\frac{{dy}}{{dx}}=\frac{{y}}{\mathrm{ln}\:{y}} \\ $$$$\mathrm{ln}\:{y}\frac{{dy}}{{y}}={dx} \\ $$$$\frac{\mathrm{1}}{\mathrm{2}}\left(\mathrm{ln}\:{y}\right)^{\mathrm{2}} ={x}+{C}_{\mathrm{1}}…

Question-196459

Question Number 196459 by RoseAli last updated on 25/Aug/23 Answered by Frix last updated on 25/Aug/23 $$\mathrm{Use}\:\mathrm{Ostrogradski}'\mathrm{s}\:\mathrm{Method}\:\mathrm{to}\:\mathrm{get} \\ $$$$\int\frac{{x}^{\mathrm{4}} +{x}^{\mathrm{2}} +\mathrm{1}}{\left({x}^{\mathrm{2}} +\mathrm{1}\right)^{\mathrm{3}} }{dx}=\frac{{x}\left(\mathrm{2}{x}^{\mathrm{2}} +\mathrm{3}\right)}{\mathrm{2}\left({x}^{\mathrm{2}} +\mathrm{1}\right)}−\frac{\mathrm{1}}{\mathrm{2}}\int\frac{{dx}}{{x}^{\mathrm{2}}…

Question-196458

Question Number 196458 by peter frank last updated on 25/Aug/23 Answered by Peace last updated on 25/Aug/23 $$\int\left({sin}\left({y}\right)+{ycos}\left({y}\right)\right){dh}=\int{x}\left(\mathrm{2}{ln}\left(\mathrm{x}\right)+\mathrm{1}\right)\mathrm{dx} \\ $$$$\Leftrightarrow+{ysin}\left({y}\right)+{c}={x}^{\mathrm{2}} {ln}\left({x}\right) \\ $$$${x}^{\mathrm{2}} {ln}\left({x}\right)−{ysin}\left({y}\right)+{c}=\mathrm{0} \\…

sec-4-x-cot-4-x-dx-

Question Number 196487 by RoseAli last updated on 25/Aug/23 $$\int\left(\mathrm{sec}\:^{\mathrm{4}} {x}−\mathrm{cot}\:^{\mathrm{4}} {x}\right){dx} \\ $$ Answered by MM42 last updated on 26/Aug/23 $${I}_{\mathrm{1}} =\int{sec}^{\mathrm{4}} {xdx}=\int\left(\mathrm{1}+{tan}^{\mathrm{2}} {x}\right)\left(\mathrm{1}+{tan}^{\mathrm{2}}…