Question Number 196115 by sonukgindia last updated on 18/Aug/23 Answered by Rasheed.Sindhi last updated on 18/Aug/23 $${xy}+\mathrm{66}{x}−\mathrm{88}{y}−\mathrm{88}×\mathrm{66}=\mathrm{23333}−\mathrm{88}×\mathrm{66} \\ $$$${x}\left({y}+\mathrm{66}\right)−\mathrm{88}\left({y}+\mathrm{66}\right)=\mathrm{17525} \\ $$$$\left({x}−\mathrm{88}\right)\left({y}+\mathrm{66}\right)=\mathrm{5}^{\mathrm{2}} ×\mathrm{701}\: \\ $$$$\begin{cases}{\underset{{x}=\mathrm{89}\:} {{x}−\mathrm{88}=\mathrm{1}}\:\wedge\:\underset{{y}=\mathrm{23267}}…
Question Number 196111 by sonukgindia last updated on 18/Aug/23 Answered by mahdipoor last updated on 18/Aug/23 $$\Rightarrow\Rightarrow\Rightarrow\Rightarrow\:{if}\:{n}\leqslant{x}\:\Rightarrow \\ $$$$\Sigma=\left({x}−\mathrm{1}\right)+…+\left({x}−{n}\right)={nx}−\frac{{n}^{\mathrm{2}} +{n}}{\mathrm{2}}= \\ $$$${x}^{\mathrm{2}} −\left({n}+\mathrm{1}\right){x}+\left(\frac{{n}^{\mathrm{2}} +\mathrm{2}{n}+\mathrm{5}}{\mathrm{4}}\right) \\…
Question Number 196107 by maths_plus last updated on 18/Aug/23 $$ \\ $$$$\mathrm{help},\:\mathrm{please}\:! \\ $$$$\underset{{x}\:\rightarrow\:\frac{\boldsymbol{\pi}}{\mathrm{4}}} {{lim}}\:\frac{{cos}\left(\frac{\boldsymbol{\pi}}{\mathrm{4}}\:−{x}\right)−{tan}\:{x}}{\mathrm{1}−{sin}\left(\frac{\boldsymbol{\pi}}{\mathrm{4}}+{x}\right)}\:=\:???\: \\ $$ Answered by MM42 last updated on 21/Aug/23 $${hop}\rightarrow{lim}_{{x}\rightarrow\frac{\pi}{\mathrm{4}}}…
Question Number 196103 by MrGHK last updated on 18/Aug/23 $$\frac{\boldsymbol{\mathrm{d}}^{\boldsymbol{\mathrm{n}}} }{\boldsymbol{\mathrm{dx}}^{\boldsymbol{\mathrm{n}}} }\left[\boldsymbol{\Gamma}\left(\boldsymbol{\mathrm{x}}\right)\right]\:\:\boldsymbol{\mathrm{Hence}}\:\boldsymbol{\mathrm{what}}\:\boldsymbol{\mathrm{is}}\:\frac{\boldsymbol{\mathrm{d}}^{\frac{\mathrm{1}}{\mathrm{2}}} }{\boldsymbol{\mathrm{dx}}^{\frac{\mathrm{1}}{\mathrm{2}}} }\left[\boldsymbol{\Gamma}\left(\boldsymbol{\mathrm{x}}\right)\right] \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
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Question Number 196098 by sonukgindia last updated on 18/Aug/23 Answered by mr W last updated on 18/Aug/23 $${x}^{\frac{\mathrm{1}}{\mathrm{2}^{{x}^{\mathrm{4}} } }} ={x}^{\frac{\mathrm{1}}{\mathrm{4}^{{x}^{\mathrm{2}} } }} \\ $$$$\Rightarrow{x}=\mathrm{0}…
Question Number 196063 by Rodier97 last updated on 17/Aug/23 $$ \\ $$$$ \\ $$$$ \\ $$$$ \\ $$$$\mathrm{calcul}\:\:\:\:\int_{\mathrm{0}} ^{+\infty} \:\frac{\sqrt{\mathrm{u}}\:.\mathrm{arctan}\left(\mathrm{u}\right)}{\mathrm{1}+\mathrm{u}^{\mathrm{2}} }\:\mathrm{du} \\ $$$$ \\ $$$$…
Question Number 196062 by qaz last updated on 17/Aug/23 $$\underset{{i}=\mathrm{1}} {\overset{{n}} {\sum}}\underset{{j}=\mathrm{1}} {\overset{{n}} {\sum}}\left[{gcd}\left({i},{j}\right)=\mathrm{1}\right]=?\:\:\:\:\:\:\:\:\:,\left[{D}\right]=\begin{cases}{\mathrm{1},\:\:\:{D}\:{is}\:{ture}.}\\{\mathrm{0},\:\:\:\:{D}\:{is}\:{false}.\:\:\:}\end{cases} \\ $$ Commented by mr W last updated on 17/Aug/23 $${i}\:{don}'{t}\:{think}\:{we}\:{can}\:{get}\:{it}\:{in}\:{a}\:{closed}…