Menu Close

Author: Tinku Tara

solve-2x-3-3x-8-3x-4-2x-7-

Question Number 196056 by mr W last updated on 17/Aug/23 $${solve} \\ $$$$\sqrt{\mathrm{2}{x}+\mathrm{3}}−\sqrt{\mathrm{3}{x}+\mathrm{8}}=\sqrt{\mathrm{3}{x}+\mathrm{4}}−\sqrt{\mathrm{2}{x}+\mathrm{7}} \\ $$ Answered by cortano12 last updated on 17/Aug/23 $$\:\sqrt{\mathrm{u}}\:−\sqrt{\mathrm{v}+\mathrm{4}}\:=\sqrt{\mathrm{v}}−\sqrt{\mathrm{u}+\mathrm{4}} \\ $$$$\:\:\sqrt{\mathrm{u}}−\sqrt{\mathrm{v}}\:=\:\sqrt{\mathrm{v}+\mathrm{4}}−\sqrt{\mathrm{u}+\mathrm{4}}…

Question-196085

Question Number 196085 by sonukgindia last updated on 17/Aug/23 Answered by MM42 last updated on 17/Aug/23 $$\left(\mathrm{1}^{\mathrm{17}} +\mathrm{2023}^{\mathrm{17}} \right)+\left(\mathrm{2}^{\mathrm{17}} +\mathrm{2022}^{\mathrm{17}} \right)+…+\mathrm{1012}^{\mathrm{17}} = \\ $$$$\left(\mathrm{1}+\mathrm{2023}\right){k}_{\mathrm{1}} +\left(\mathrm{2}+\mathrm{2022}\right){k}_{\mathrm{2}}…

faind-n-terme-4-2-16-9-2-

Question Number 196053 by mathlove last updated on 17/Aug/23 $${faind}\:{n}\:{terme} \\ $$$$\mathrm{4},−\mathrm{2},\frac{\mathrm{16}}{\mathrm{9}},−\mathrm{2},…… \\ $$ Answered by Frix last updated on 17/Aug/23 $$\frac{\mathrm{16}}{\mathrm{4}},−\mathrm{2},\frac{\mathrm{16}}{\mathrm{9}},−\mathrm{2},\frac{\mathrm{16}}{\mathrm{14}},−\mathrm{2},\frac{\mathrm{16}}{\mathrm{19}},… \\ $$$$\frac{\mathrm{16}}{\mathrm{4}},−\mathrm{2},\frac{\mathrm{16}}{\mathrm{9}},−\mathrm{2},\frac{\mathrm{16}}{\mathrm{16}},−\mathrm{2},\frac{\mathrm{16}}{\mathrm{25}},… \\…

Answer-to-the-question-196008-k-1-n-tan-2-kpi-2n-1-n-2n-1-Ans-according-de-moivre-sin-2n-1-2n-1-1-cos-2n-sin-2n-1-3-cos-2n-2-sin-3-

Question Number 196086 by MM42 last updated on 17/Aug/23 $${Answer}\:{to}\:{the}\:{question}\:“\mathrm{196008}'' \\ $$$$\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}{tan}^{\mathrm{2}} \left(\frac{{k}\pi}{\mathrm{2}{n}+\mathrm{1}}\right)={n}\left(\mathrm{2}{n}+\mathrm{1}\right) \\ $$$$\left.{Ans}\right) \\ $$$${according}\:\:“{de}\:{moivre}'' \\ $$$${sin}\left(\mathrm{2}{n}+\mathrm{1}\right)\alpha=\begin{pmatrix}{\mathrm{2}{n}+\mathrm{1}}\\{\:\:\:\:\:\:\mathrm{1}}\end{pmatrix}\left({cos}\alpha\right)^{\mathrm{2}{n}} {sin}\alpha−\begin{pmatrix}{\mathrm{2}{n}+\mathrm{1}}\\{\:\:\:\:\:\mathrm{3}}\end{pmatrix}\left({cos}\alpha\right)^{\mathrm{2}{n}−\mathrm{2}} \left({sin}\alpha\right)^{\mathrm{3}} +…. \\…

a-b-c-gt-0-Find-the-min-value-of-cyc-a-b-a-b-c-

Question Number 196049 by CrispyXYZ last updated on 17/Aug/23 $${a},\:{b},\:{c}\:>\:\mathrm{0}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{min}\:\mathrm{value}\:\mathrm{of} \\ $$$$\underset{\mathrm{cyc}} {\sum}\:\sqrt{\frac{{a}+{b}}{{a}+{b}+{c}}}\:. \\ $$ Commented by Frix last updated on 17/Aug/23 $${b}={pa}\wedge{c}={qa} \\ $$$$\Sigma=\frac{\sqrt{{p}+\mathrm{1}}+\sqrt{{p}+{q}}+\sqrt{{q}+\mathrm{1}}}{\:\sqrt{{p}+{q}+\mathrm{1}}}…

During-an-invasion-In-the-amazon-dominion-Every-evening-every-invader-kills-an-amazon-warrior-Every-morning-every-amazon-kills-an-invader-soldier-The-8-th-day-evening-there-remains-o

Question Number 196070 by sniper237 last updated on 17/Aug/23 $${During}\:{an}\:{invasion}\: \\ $$$${In}\:{the}\:{amazon}\:{dominion} \\ $$$${Every}\:{evening}\:,\:{every}\:\:{invader}\: \\ $$$${kills}\:\:{an}\:\:{amazon}\:{warrior}\: \\ $$$${Every}\:{morning}\:,\:{every}\:{amazon} \\ $$$${kills}\:\:\:{an}\:{invader}\:{soldier} \\ $$$${The}\:\mathrm{8}^{{th}} \:{day}\:{evening}\:,\:{there}\:{remains}\: \\ $$$${only}\:{one}\:{amazon}\:\:{and}\:{no}\:{invader}…