Question Number 195911 by Calculusboy last updated on 13/Aug/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 195910 by Calculusboy last updated on 13/Aug/23 Answered by witcher3 last updated on 20/Aug/23 $$\mathrm{Methode}\:\mathrm{of}\:\mathrm{differentiation}\:? \\ $$$$\mathrm{A}=\mathrm{ln}\left(\mathrm{2}\right)\int_{\mathrm{0}} ^{\mathrm{1}} \frac{\mathrm{x}^{\mathrm{2}} −\mathrm{1}}{\mathrm{ln}\left(\mathrm{x}\right)}\mathrm{dx} \\ $$$$\mathrm{A}\left(\mathrm{a}\right)=\mathrm{ln}\left(\mathrm{2}\right)\int_{\mathrm{0}} ^{\mathrm{1}}…
Question Number 195905 by cortano12 last updated on 13/Aug/23 $$\:\:\:\:\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\sqrt{\mathrm{3}+\mathrm{x}^{\mathrm{4}} }\:−\sqrt{\mathrm{3}+\mathrm{tan}\:^{\mathrm{4}} \mathrm{x}}}{\mathrm{x}^{\mathrm{6}} }\:=? \\ $$ Answered by qaz last updated on 13/Aug/23 $$ \\…
Question Number 195904 by York12 last updated on 13/Aug/23 $$\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\left[\frac{\mathrm{2}^{{n}} \left(\mathrm{2}{n}\right)!}{\mathrm{3}^{\mathrm{2}{n}+\mathrm{1}} \left({n}+\mathrm{1}\right)!{n}!}\right]=\lambda \\ $$$${Evaluate}\:\left(\lambda\right) \\ $$ Answered by qaz last updated on 13/Aug/23…
Question Number 195900 by Calculusboy last updated on 12/Aug/23 Answered by cortano12 last updated on 13/Aug/23 $$\:\:\:\left[\:\frac{\mathrm{1}}{\mathrm{3}}\mathrm{x}^{\mathrm{3}} +\frac{\mathrm{1}}{\mathrm{2}}\mathrm{x}^{\mathrm{2}} \:\right]_{−\mathrm{2}} ^{\mathrm{b}} =\frac{\mathrm{16}}{\mathrm{3}} \\ $$$$\:\:\:\left[\frac{\mathrm{1}}{\mathrm{2}}\mathrm{x}^{\mathrm{2}} \left(\frac{\mathrm{2}}{\mathrm{3}}\mathrm{x}+\mathrm{1}\right)\:\right]_{−\mathrm{2}} ^{\mathrm{b}}…
Question Number 195870 by mr W last updated on 12/Aug/23 Commented by mr W last updated on 12/Aug/23 $${find}\:{the}\:{minimum}\:{speed}\:{with}\:{which} \\ $$$${the}\:{ball}\:{is}\:{launced}\:{from}\:{point}\:{A}\:{such} \\ $$$${that}\:{it}\:{can}\:{return}\:{to}\:{this}\:{point}\:{again} \\ $$$${after}\:{rebounded}\:{at}\:{point}\:{B}.…
Question Number 195896 by AROUNAMoussa last updated on 12/Aug/23 Answered by HeferH last updated on 13/Aug/23 Commented by HeferH last updated on 13/Aug/23 $$\mathrm{180}°−\mathrm{4}{x}\:+\:\mathrm{40}°+\mathrm{2}{x}\:=\:\mathrm{180}° \\…
Question Number 195898 by Calculusboy last updated on 12/Aug/23 Answered by qaz last updated on 13/Aug/23 $${a}_{{n}+\mathrm{2}} {a}_{{n}+\mathrm{1}} −{a}_{{n}+\mathrm{1}} {a}_{{n}} =\mathrm{2}\:\:\:\:\Rightarrow{a}_{{n}+\mathrm{2}} {a}_{{n}+\mathrm{1}} =\mathrm{2}{n}+{a}_{\mathrm{1}} {a}_{\mathrm{2}} =\mathrm{2}\left({n}+\mathrm{1}\right)…
Question Number 195892 by AROUNAMoussa last updated on 12/Aug/23 Answered by mr W last updated on 13/Aug/23 $$\mathrm{1}+\sqrt{\left(\mathrm{4}+\mathrm{1}\right)^{\mathrm{2}} −\left(\mathrm{4}−\mathrm{1}\right)^{\mathrm{2}} }+\sqrt{\left(\mathrm{4}+\mathrm{2}\right)^{\mathrm{2}} −\left(\mathrm{4}−\mathrm{2}\right)^{\mathrm{2}} }+\mathrm{2} \\ $$$$=\mathrm{7}+\mathrm{4}\sqrt{\mathrm{2}} \\…
Question Number 195895 by Erico last updated on 12/Aug/23 $$\mathrm{Calcul}\:\:\:\:\:\:\:\:\underset{\:\mathrm{0}} {\int}^{\:\frac{\pi}{\mathrm{2}}} \mathrm{t}\sqrt{\mathrm{tan}\left(\mathrm{t}\right)}\:\mathrm{dt} \\ $$ Answered by witcher3 last updated on 13/Aug/23 $$\int_{\mathrm{0}} ^{\infty} \frac{\mathrm{tan}^{−\mathrm{1}} \left(\mathrm{t}\right).\sqrt{\mathrm{t}}}{\mathrm{1}+\mathrm{t}^{\mathrm{2}}…