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Author: Tinku Tara

2-x-2-x-5-find-4-x-4-x-so-soon-solve-it-i-need-i-have-rxame-tomarrow-

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Question Number 195532 by bbbbbbbb last updated on 04/Aug/23 $$\mathrm{2}^{\boldsymbol{\mathrm{x}}} −\mathrm{2}^{−\boldsymbol{\mathrm{x}}} =\mathrm{5}\:\boldsymbol{\mathrm{find}}\:\mathrm{4}^{\boldsymbol{\mathrm{x}}} +\mathrm{4}^{−\boldsymbol{\mathrm{x}}} =? \\ $$$$\boldsymbol{\mathrm{so}}\:\boldsymbol{\mathrm{soon}}\:\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{it}}\:\boldsymbol{\mathrm{i}}\:\boldsymbol{\mathrm{need}}\:\boldsymbol{\mathrm{i}}\:\boldsymbol{\mathrm{have}}\:\boldsymbol{\mathrm{rxame}}\:\boldsymbol{\mathrm{tomarrow}} \\ $$ Commented by bbbbbbbb last updated on 04/Aug/23…

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Question-195535

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Question Number 195535 by arkanshh last updated on 04/Aug/23 Answered by AST last updated on 04/Aug/23 $$\frac{{N}={A}×{B}}{{D}}=\frac{\left(\mathrm{3}^{{x}^{\mathrm{2}} } −\mathrm{3}^{{x}+\mathrm{6}} \right)\left(\mathrm{5}^{{x}} −\mathrm{25}\right)}{\mathrm{4}^{{x}^{\mathrm{2}} \left(\mathrm{3}−{x}\right)} −\mathrm{4}^{\mathrm{3}−{x}} }\geqslant\mathrm{0}\left({Equality}\:{at}\:{x}=\mathrm{2},−\mathrm{2}\right) \\…

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2-a-50-find-2-2a-2-soon-as-soon-solve-this-i-need-so-

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Question Number 195521 by bbbbbbbb last updated on 04/Aug/23 $$\mathrm{2}^{\boldsymbol{\mathrm{a}}} =\mathrm{50}\:\:\:\:\boldsymbol{\mathrm{find}}\:\mathrm{2}^{\mathrm{2}\boldsymbol{\mathrm{a}}−\mathrm{2}} =? \\ $$$$\boldsymbol{\mathrm{soon}}\:\boldsymbol{\mathrm{as}}\:\boldsymbol{\mathrm{soon}}\:\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{this}}\:\boldsymbol{\mathrm{i}}\:\boldsymbol{\mathrm{need}}\:\boldsymbol{\mathrm{so}} \\ $$ Answered by Calculusboy last updated on 04/Aug/23 $$\mathrm{625} \\…

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