Question Number 195137 by mathlove last updated on 25/Jul/23 $${f}\left({x}\right)={arctan}\left(\frac{\mathrm{4}{sinx}}{\mathrm{3}+\mathrm{5}{cosx}}\right)\:\:\:{then}\:{f}^{'} \left(\frac{\pi}{\mathrm{3}}\right)=? \\ $$ Answered by Tokugami last updated on 02/Sep/23 $${f}'\left({x}\right)=\frac{\mathrm{1}}{\mathrm{1}+\left(\frac{\mathrm{4sin}\:{x}}{\mathrm{3}+\mathrm{5cos}\:{x}}\right)^{\mathrm{2}} }\:\frac{{d}}{{dx}}\left(\frac{\mathrm{4sin}\:{x}}{\mathrm{3}+\mathrm{5cos}\:{x}}\right) \\ $$$$=\frac{\mathrm{1}}{\mathrm{1}+\frac{\mathrm{16sin}^{\mathrm{2}} {x}}{\left(\mathrm{3}+\mathrm{5cos}\:{x}\right)^{\mathrm{2}}…
Question Number 195136 by mathlove last updated on 25/Jul/23 $${f}\left({x}\right)={arctan}\left({sinx}\right) \\ $$$${and}\:\:{cosa}=\frac{\mathrm{2}}{\mathrm{3}}\:\:\:\:\:\:\:\:{faind}\:\:\:{f}^{'} \left({a}\right)=? \\ $$ Answered by som(math1967) last updated on 25/Jul/23 $$\:\boldsymbol{{f}}\:'\left({x}\right)=\frac{\mathrm{1}}{\mathrm{1}+\boldsymbol{{sin}}^{\mathrm{2}} \boldsymbol{{x}}}×\boldsymbol{{cosx}} \\…
Question Number 195171 by azirali0198316 last updated on 25/Jul/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 195170 by mathlove last updated on 25/Jul/23 $${f}\left({x}\right)=\begin{cases}{{x}^{\mathrm{7}} +\mathrm{2}{x}+\mathrm{1}\:\:\:\:\:\:\:;{x}\geqslant\mathrm{2}}\\{{x}^{\mathrm{2}} +\mathrm{7}{x}+\mathrm{4}\:\:\:\:\:\:\:\:;{x}<\mathrm{1}}\end{cases} \\ $$$${f}^{'} \left(\mathrm{1}\right)=? \\ $$ Answered by MM42 last updated on 25/Jul/23 $${f}\left(\mathrm{1}\right)\:,\:{not}\:{available}\:{so}…
Question Number 195101 by mathlove last updated on 24/Jul/23 $$\sqrt{{ln}\mathrm{2}}\:\:\overset{?} {>}{ln}\mathrm{2} \\ $$ Answered by Frix last updated on 24/Jul/23 $$\mathrm{e}^{{x}} =\mathrm{2} \\ $$$$\mathrm{e}>\mathrm{2}\:\Rightarrow\:{x}<\mathrm{1} \\…
Question Number 195116 by SajaRashki last updated on 24/Jul/23 $${hi}.\:{please}\:{represntation}\:\sqrt[{\mathrm{3}}]{\mathrm{2}}\:{on}\:{number}'{s}\:{axis} \\ $$$${with}\:{ruler}\:{and}\:{compass}\:{and}\:{pen}. \\ $$$${thank}\:{you} \\ $$ Commented by Frix last updated on 25/Jul/23 $$\mathrm{Impossible}. \\…
Question Number 195113 by SirMUTUKU last updated on 24/Jul/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 195097 by Rupesh123 last updated on 24/Jul/23 Answered by Rasheed.Sindhi last updated on 24/Jul/23 $$\mathrm{49}^{\mathrm{sin}\:{x}} =\sqrt[{\mathrm{cos}\:{x}}]{\mathrm{7}}\: \\ $$$$\mathrm{7}^{\mathrm{2}\:\mathrm{sin}\:{x}} =\mathrm{7}^{\frac{\mathrm{1}}{\mathrm{cos}\:{x}}} \\ $$$$\mathrm{2}\:\mathrm{sin}\:{x}=\frac{\mathrm{1}}{\mathrm{cos}\:{x}} \\ $$$$\mathrm{2}\:\mathrm{sin}\:{x}\:\mathrm{cos}\:{x}=\mathrm{1}…
Question Number 195114 by mustafazaheen last updated on 24/Jul/23 $$ \\ $$$$\:\:\:\:\: \\ $$$$\:\:\:\:\:\underset{\mathrm{k}=\mathrm{3}} {\overset{\mathrm{55}} {\sum}}\mathrm{k}=? \\ $$$$\left.\mathrm{1}\left.\right)\left.\mathrm{5}\left.\mathrm{5}\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{2}\right)\mathrm{9k}\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{3}\right)\mathrm{53k}\:\:\:\:\:\:\:\:\:\:\:\mathrm{4}\right)\mathrm{45} \\ $$$$ \\ $$$$ \\ $$ Answered…
Question Number 195093 by Braulio last updated on 24/Jul/23 Answered by cortano12 last updated on 24/Jul/23 Answered by MM42 last updated on 24/Jul/23 $${hop}\rightarrow{lim}_{{x}\rightarrow\pi} \:\frac{\frac{\mathrm{1}}{\mathrm{2}}{cos}\frac{{x}}{\mathrm{2}}−{sinx}}{\mathrm{2}{sinxcosx}−{sinx}}…