Question Number 195092 by mathlove last updated on 24/Jul/23 $$\underset{{x}\rightarrow\mathrm{1}^{+} } {\mathrm{lim}}\:\frac{\mathrm{4}{x}+\mathrm{5}}{{x}−{x}^{\mathrm{2}} }=? \\ $$ Answered by tri26112004 last updated on 24/Jul/23 $${We}\:{have}: \\ $$$$\bullet\underset{{x}\rightarrow\mathrm{1}^{+}…
Question Number 195094 by sonukgindia last updated on 24/Jul/23 Answered by witcher3 last updated on 24/Jul/23 $$\mathrm{no}\:\mathrm{close}\:\mathrm{forme} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 195107 by Rupesh123 last updated on 24/Jul/23 Answered by JDamian last updated on 24/Jul/23 $$\mathrm{5}+\mathrm{15}+\mathrm{25}+\:\centerdot\centerdot\centerdot\:+\mathrm{975}+\mathrm{985}+\mathrm{995}= \\ $$$$=\frac{\mathrm{100}}{\mathrm{2}}\left(\mathrm{5}+\mathrm{995}\right)=\mathrm{50000} \\ $$ Terms of Service Privacy…
Question Number 195065 by alcohol last updated on 23/Jul/23 Answered by Rasheed.Sindhi last updated on 23/Jul/23 $${Let}\:{a}−{d},{a},{a}+{d}\:{are}\:{required}\:{numbers} \\ $$$$\left({a}−{d}\right)+{a}+\left({a}+{d}\right)=\mathrm{21} \\ $$$$\mathrm{3}{a}=\mathrm{21}\Rightarrow{a}=\mathrm{7} \\ $$$$\therefore\:\:\mathrm{7}−{d},\mathrm{7},\mathrm{7}+{d}\:{are}\:{required}\:{numbers} \\ $$$${Now}\:{by}\:{given}:\:…
Question Number 195064 by alcohol last updated on 23/Jul/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 195066 by alcohol last updated on 23/Jul/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 195087 by bett last updated on 23/Jul/23 Answered by JDamian last updated on 23/Jul/23 Answered by Rasheed.Sindhi last updated on 23/Jul/23 $$\mathrm{log}_{\mathrm{3}} \mathrm{4}{x}+\mathrm{3log}_{\mathrm{27}}…
Question Number 195083 by sciencestudentW last updated on 23/Jul/23 $${x}=\sqrt{\mathrm{5}}−\mathrm{2}\:\:\:\:\: \\ $$$${x}+\frac{\mathrm{1}}{{x}}=? \\ $$ Answered by Rasheed.Sindhi last updated on 23/Jul/23 $${x}=\sqrt{\mathrm{5}}−\mathrm{2}\:\:,\:\:{x}+\frac{\mathrm{1}}{{x}}=? \\ $$$$\frac{\mathrm{1}}{{x}}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{5}}−\mathrm{2}}=\frac{\mathrm{1}}{\:\sqrt{\mathrm{5}}−\mathrm{2}}\centerdot\frac{\sqrt{\mathrm{5}}\:+\mathrm{2}}{\:\sqrt{\mathrm{5}}\:+\mathrm{2}} \\…
Question Number 195082 by Rupesh123 last updated on 23/Jul/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 195079 by sonukgindia last updated on 23/Jul/23 Answered by witcher3 last updated on 24/Jul/23 $$\mathrm{we}\:\mathrm{applie}\:\mathrm{S}_{\mathrm{n}} \:\mathrm{to}\:\mathrm{this}\:\mathrm{sum}\:\mathrm{witch}\:\mathrm{symetric}\:\mathrm{Groupe}\:\mathrm{of} \\ $$$$\mathrm{n}\:\mathrm{element}\:\mathrm{we}\:\mathrm{not}\:\mathrm{this}\:\mathrm{elements}\:\sigma \\ $$$$\mathrm{cardS}_{\mathrm{n}} =\mathrm{n}!;\left\{\mathrm{1}…..\mathrm{n}\right\}\overset{\sigma} {\rightarrow}\left\{\mathrm{1},….,\mathrm{n}\right\} \\…