Question Number 195020 by tri26112004 last updated on 22/Jul/23 $${y}={x}^{{x}^{{x}…} } \\ $$$$=>\:\frac{{dy}}{{dx}}=¿ \\ $$ Answered by Frix last updated on 22/Jul/23 $${y}={x}^{{x}^{{x}…} } \\…
Question Number 195017 by mathlove last updated on 22/Jul/23 $$\left({x}+\mathrm{1}\right)^{\mathrm{3}} =\mathrm{1}\:\:\:\:\:\:\:\:\:\:{x}=? \\ $$ Answered by Rasheed.Sindhi last updated on 22/Jul/23 $$\left({x}+\mathrm{1}\right)^{\mathrm{3}} =\mathrm{1}\:\:\:\:\:\:\:\:\:\:\:{x}=? \\ $$$${Let}\:\:\:\:\:{x}+\mathrm{1}={y} \\…
Question Number 195013 by horsebrand11 last updated on 22/Jul/23 $$\:\:\:\:\:\:\underset{\mathrm{x}\rightarrow\mathrm{3}} {\mathrm{lim}}\:\left(\frac{\mathrm{2}\left(\sqrt{\mathrm{6}}−\sqrt{\mathrm{2x}}\:+\sqrt{\mathrm{6}−\mathrm{2x}}\right)}{\:\sqrt{\mathrm{36}−\mathrm{4x}^{\mathrm{2}} }}\:\right) \\ $$ Answered by cortano12 last updated on 22/Jul/23 $$\:\:\:\:=\:\underset{{x}\rightarrow\mathrm{3}} {\mathrm{lim}}\:\frac{\mathrm{2}\left(\frac{\sqrt{\mathrm{6}−\mathrm{2}{x}}}{\:\sqrt{\mathrm{6}}\:+\sqrt{\mathrm{2}{x}}}\:+\mathrm{1}\:\right)}{\:\sqrt{\mathrm{6}+\mathrm{2}{x}}} \\ $$$$\:\:\:\:\:=\:\:\begin{array}{|c|}{\frac{\mathrm{2}}{\:\sqrt{\mathrm{12}}}\:=\:\frac{\mathrm{1}}{\mathrm{3}}\sqrt{\mathrm{3}}}\\\hline\end{array}…
Question Number 195012 by sonukgindia last updated on 22/Jul/23 Answered by a.lgnaoui last updated on 23/Jul/23 Commented by a.lgnaoui last updated on 23/Jul/23 Answered by…
Question Number 195015 by mustafazaheen last updated on 22/Jul/23 Answered by mathlove last updated on 22/Jul/23 $${ass}\Rightarrow{x}=\mathrm{1} \\ $$$${f}\left(\mathrm{1}\right)=\frac{\mathrm{2}}{\mathrm{0}^{{ln}\mathrm{5}} }=\infty \\ $$$$\mathrm{1}\notin{domf}\left({x}\right) \\ $$ Terms…
Question Number 195046 by Mathstar last updated on 22/Jul/23 Commented by Mathstar last updated on 23/Jul/23 $$ \\ $$$$\:\:\mathrm{Given}\:\mathrm{curve}\:\mathrm{ysin}\left(\mathrm{x}\right)\:\mathrm{and}\:\mathrm{a}\:\mathrm{green}\: \\ $$$$\:\:\:\mathrm{square};\:\mathrm{solve}\:\mathrm{for}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{square}.\:\: \\ $$ Answered by…
Question Number 195043 by necx122 last updated on 22/Jul/23 Commented by necx122 last updated on 22/Jul/23 $${Please},\:{I}\:{meed}\:{help}\:{with}\:{this}.\:{It}'{s}\:{quite} \\ $$$${tricky}\:{for}\:{me}\:{to}\:{tackle}. \\ $$ Answered by a.lgnaoui last…
Question Number 195042 by sonukgindia last updated on 22/Jul/23 Answered by MM42 last updated on 22/Jul/23 $$\mathrm{260}=\mathrm{2}^{\mathrm{8}} +\mathrm{2}^{\mathrm{2}} \\ $$$$\Rightarrow\mathrm{2}^{\mathrm{16}^{{sin}^{\mathrm{2}} {x}} } =\mathrm{2}^{\mathrm{8}} \:\:\&\:\:\mathrm{2}^{\mathrm{16}^{{cos}^{\mathrm{2}} {x}}…
Question Number 194988 by vikasgedam last updated on 21/Jul/23 $${ABC}={CBF} \\ $$$${AB} \\ $$ Answered by TheHoneyCat last updated on 22/Jul/23 $$\mathrm{No}\:\mathrm{well}\:\mathrm{defined}\:\mathrm{question}\:\left(\mathrm{hence}\:\mathrm{no}\:\mathrm{proper}\right. \\ $$$$\left.\mathrm{answere}\right) \\…
Question Number 194991 by York12 last updated on 21/Jul/23 $$ \\ $$$${a}_{\mathrm{3}} {x}^{\mathrm{3}} −{x}^{\mathrm{2}} +{a}_{\mathrm{1}} {x}−\mathrm{7}=\mathrm{0}\:{is}\:{a}\:{cubic}\:{polynomial}\:{in}\:{x} \\ $$$${whose}\:{Roots}\:{are}\:\alpha\:,\:\beta\:,\:\gamma\:{positive}\:{real}\:{numbers} \\ $$$${satisfying} \\ $$$$\frac{\mathrm{225}\alpha^{\mathrm{2}} }{\alpha^{\mathrm{2}} +\mathrm{7}}=\frac{\mathrm{144}\beta^{\mathrm{2}} }{\beta^{\mathrm{2}}…