Question Number 194975 by youssef last updated on 21/Jul/23 $$\int\frac{\mathrm{1}}{\boldsymbol{{x}}^{\mathrm{5}} +\mathrm{1}}\boldsymbol{{dx}} \\ $$ Commented by Frix last updated on 21/Jul/23 $$\mathrm{You}\:\mathrm{have}\:\mathrm{to}\:\mathrm{decompose} \\ $$$${x}^{\mathrm{5}} +\mathrm{1}=\left({x}+\mathrm{1}\right)\left({x}^{\mathrm{2}} −\frac{\mathrm{1}+\sqrt{\mathrm{5}}}{\mathrm{2}}{x}+\mathrm{1}\right)\left({x}^{\mathrm{2}}…
Question Number 194990 by anurup last updated on 21/Jul/23 $$\mathrm{I}{f}\:\left({f}\left({x}\right)\right)={x}^{\mathrm{2}} −{x}+\mathrm{1}\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of} \\ $$$${f}\left(\mathrm{1971}\right)+{f}\left(\mathrm{2021}\right)+{f}\left(\mathrm{50}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 194985 by Erico last updated on 21/Jul/23 $$\underset{\mathrm{n}\rightarrow+\infty} {\mathrm{lim}}\left[\left(\frac{\mathrm{1}}{\mathrm{n}}\right)^{\mathrm{n}} +\left(\frac{\mathrm{2}}{\mathrm{n}}\right)^{\mathrm{n}} +…\left(\frac{\mathrm{n}−\mathrm{1}}{\mathrm{n}}\right)^{\mathrm{n}} \right]=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 194968 by cortano12 last updated on 21/Jul/23 Answered by tri26112004 last updated on 21/Jul/23 $$=\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{1}}{\:\sqrt{{x}+\mathrm{1}}+\sqrt{\mathrm{1}−{x}}}.−\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\sqrt{{x}+\mathrm{1}}+\sqrt{\mathrm{1}−{x}}−\mathrm{2}}{{x}^{\mathrm{2}} } \\ $$$$=−\frac{\mathrm{1}}{\mathrm{2}}.\left\{\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\frac{\mathrm{1}}{\mathrm{2}}\left[\sqrt{\mathrm{4}{x}+\mathrm{4}}−\left({x}+\mathrm{2}\right)\right]+\sqrt{\mathrm{1}−{x}}+\frac{\mathrm{1}}{\mathrm{2}}{x}−\mathrm{1}}{{x}^{\mathrm{2}} }\right\} \\…
Question Number 194971 by kapoorshah last updated on 21/Jul/23 Commented by Frix last updated on 21/Jul/23 $$\mathrm{I}\:\mathrm{think}\:\left({abc}\right)^{\mathrm{2}} =\mathrm{8} \\ $$ Commented by sniper237 last updated…
Question Number 194967 by Rupesh123 last updated on 21/Jul/23 Answered by a.lgnaoui last updated on 23/Jul/23 $$\mathrm{4}\:\mathrm{cercles}\:\mathrm{disposes}\:\mathrm{comme}\:\mathrm{suit} \\ $$$$\left.\bullet\mathrm{1}\right)\:\:\mathrm{cercle}\:\boldsymbol{\mathrm{R}}\mathrm{ouge}\:\boldsymbol{\mathrm{C}}\mathrm{1}\left(\mathrm{Rayon}\:\boldsymbol{\mathrm{R}}\mathrm{1}\right) \\ $$$$\:\:\:\:\:\:\mathrm{2}\boldsymbol{\mathrm{R}}\mathrm{1}=\boldsymbol{\mathrm{AB}}=\mathrm{12}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\boldsymbol{\mathrm{R}}\mathrm{1}=\mathrm{6} \\ $$$$\left.\bullet\mathrm{2}\right)\:\mathrm{cercle}\:\boldsymbol{\mathrm{V}}\mathrm{ert}\:\boldsymbol{\mathrm{C}}\mathrm{2}\left(\boldsymbol{\mathrm{R}}\mathrm{ayon}\:\boldsymbol{\mathrm{R}}\mathrm{2}\right)\:/ \\ $$$$\:\:\:\:\:\mathrm{demi}−\mathrm{cercle}\:\:\boldsymbol{\mathrm{C}}\left(\boldsymbol{\mathrm{A}},\boldsymbol{\mathrm{B}},\boldsymbol{\mathrm{C}}\right)…
Question Number 194942 by horsebrand11 last updated on 20/Jul/23 $$\:\:\:\:\: \\ $$ Commented by MJS_new last updated on 20/Jul/23 $$−\mathrm{2} \\ $$ Commented by horsebrand11…
Question Number 194937 by dimentri last updated on 20/Jul/23 $$\:\:{If}\:\mathrm{tan}\:\left(\frac{\pi}{\mathrm{24}}\right)=\:\left(\sqrt{{a}}−\sqrt{{b}}\right)\left(\sqrt{{c}}−\sqrt{{d}}\right) \\ $$$$\:\:{where}\:{a},{b},{c},{d}\:{are}\:{postive}\:{numbers}. \\ $$$$\:\:{Find}\:{the}\:{value}\:{of}\:\left({a}+{b}+{c}+{d}+\mathrm{2}\right) \\ $$ Answered by BaliramKumar last updated on 20/Jul/23 $$\mathrm{tan}\left(\frac{\pi}{\mathrm{24}}\right)\:=\:\mathrm{tan7}.\mathrm{5}° \\…
Question Number 194939 by Mingma last updated on 20/Jul/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 194938 by Mingma last updated on 20/Jul/23 Terms of Service Privacy Policy Contact: info@tinkutara.com