Question Number 194826 by cortano12 last updated on 16/Jul/23 $$\:\:\:\:\:\:\mathrm{tan}\:\mathrm{19}°\:=\:{p}\: \\ $$$$\:\:\:\:\:\:\mathrm{tan}\:\mathrm{7}°\:=? \\ $$ Answered by dimentri last updated on 16/Jul/23 $$\:\:\:\mathrm{tan}\:\mathrm{38}°\:=\:\mathrm{tan}\:\left(\mathrm{45}°−\mathrm{7}\right) \\ $$$$\:\:\:\frac{\mathrm{2tan}\:\mathrm{19}°}{\mathrm{1}−\mathrm{tan}^{\mathrm{2}} \:\mathrm{19}°}\:=\:\frac{\mathrm{1}−\mathrm{tan}\:\mathrm{7}°}{\mathrm{1}+\mathrm{tan}\:\mathrm{7}°}…
Question Number 194821 by sniper237 last updated on 16/Jul/23 $${M}\:{a}\:{inside}\:{poin}\:{in}\:\:\Delta{ABC}. \\ $$$${M}\:=\:{bar}\:\left\{\left({A},\:{area}\left({MBC}\right)\right),\:\left({B},\:{area}\left({MAC}\right)\right),\left({C},{area}\left({MAB}\right)\right)\right\} \\ $$ Commented by mr W last updated on 16/Jul/23 $${what}\:{do}\:{mean}\:{with}\:\left({A},\:{area}\left({MBC}\right)\right)? \\ $$$${what}\:{do}\:{mean}\:{with}\:{bar}\:\left\{{X},\:{Y},\:{Z}\right\}?…
Question Number 194819 by sonukgindia last updated on 16/Jul/23 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 194818 by sonukgindia last updated on 16/Jul/23 Answered by sniper237 last updated on 16/Jul/23 $$\overset{{x}={u}^{\mathrm{2}} } {=}\int_{\mathrm{0}} ^{\mathrm{1}} \:\sqrt{\mathrm{1}−{u}}\:×\left(\mathrm{2}{lnu}\right)×\left(\mathrm{2}{udu}\right) \\ $$$$=\:\mathrm{4}\:\int_{\mathrm{0}} ^{\mathrm{1}} \:{u}^{\mathrm{2}−\mathrm{1}}…
Question Number 194781 by MM42 last updated on 15/Jul/23 $${f}_{{n}\:} \:\:{the}\:{general}\:{sentence}\:{is}\:{seqiencee} \\ $$$${fibonacci}.\: \\ $$$${prove}\:{that}\::\:\:{f}_{\mathrm{2}{n}−\mathrm{1}} ={f}_{{n}} ^{\mathrm{2}} +{f}_{{n}−\mathrm{1}} ^{\mathrm{2}} \\ $$$$ \\ $$ Terms of…
Question Number 194808 by York12 last updated on 15/Jul/23 $$ \\ $$$${suppose}\:{a},{b},{c}\:{are}\:{positive}\:{real}\:{numbers} \\ $$$${prove}\:{the}\:{inequality} \\ $$$$\left(\frac{{a}+{b}}{\mathrm{2}}\right)\left(\frac{{b}+{c}}{\mathrm{2}}\right)\left(\frac{{c}+{a}}{\mathrm{2}}\right)\geqslant\left(\frac{{a}+{b}+{c}}{\mathrm{3}}\right)\sqrt[{\mathrm{3}}]{\left({abc}\right)^{\mathrm{2}} } \\ $$ Commented by York12 last updated on…
Question Number 194779 by sniper237 last updated on 15/Jul/23 $${If}\:\:{a}\:\:{divided}\:{by}\:{b}\:{gives}\:{q}\:\:{remaining}\:{r} \\ $$$${Then}\:\:\frac{{a}}{{b}}\:=\:{q},{rrr}…\:\:{in}\:{base}\:{b}+\mathrm{1} \\ $$ Commented by Frix last updated on 15/Jul/23 No problem �� Commented by Frix…
Question Number 194796 by sniper237 last updated on 15/Jul/23 $${A}\:\mathrm{1}{m}^{\mathrm{2}} \:{rectangle}\:{which}\:{length}\:{is}\: \\ $$$${less}\:{than}\:\mathrm{1}\:{is}\:\:{a}\:{square}.\:{Why}? \\ $$ Answered by Frix last updated on 15/Jul/23 $$\mathrm{It}'\mathrm{s}\:\mathrm{obviously}\:\mathrm{false} \\ $$$${l}×{w}=\mathrm{1}…
Question Number 194767 by horsebrand11 last updated on 15/Jul/23 $$\:\:\:\:\:\mathrm{tan}\:\theta\:=\:\mathrm{2}\: \\ $$$$\:\:\:\frac{\mathrm{8sin}\:\theta+\mathrm{5cos}\:\theta}{\mathrm{sin}\:^{\mathrm{3}} \theta+\mathrm{cos}\:^{\mathrm{3}} \theta+\mathrm{cos}\:\theta}\:=? \\ $$ Answered by dimentri last updated on 15/Jul/23 $$\:\:\:\mathrm{sec}\:^{\mathrm{2}} {x}=\mathrm{5}\:,\:\mathrm{tan}\:^{\mathrm{2}}…
Question Number 194766 by dimentri last updated on 15/Jul/23 $$\:\:\:\mathrm{1}+\mathrm{2cot}\:\mathrm{2}{x}\:\mathrm{cot}\:{x}\:=\:\mathrm{3}\: \\ $$$$\:\:\:{x}=? \\ $$ Answered by Frix last updated on 15/Jul/23 $$\mathrm{1}+\mathrm{2cor}\:\mathrm{2}{x}\:\mathrm{cot}\:{x}\:=\mathrm{3} \\ $$$$\mathrm{cot}^{\mathrm{2}} \:{x}\:=\mathrm{3}…