Question Number 131283 by SEKRET last updated on 03/Feb/21 $$\:\int_{\mathrm{0}} ^{+\infty} \:\frac{\mathrm{1}}{\boldsymbol{\mathrm{e}}^{\boldsymbol{\mathrm{x}}} \centerdot\boldsymbol{\mathrm{ln}}\left(\boldsymbol{\mathrm{x}}\right)}\:\boldsymbol{\mathrm{dx}}=? \\ $$$$ \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 209 by 02@>@0 last updated on 25/Jan/15 $${y}={sin}\left({x}\right)+{cos}\left({x}\right) \\ $$ Answered by 123456 last updated on 15/Dec/14 $${y}=\frac{\sqrt{\mathrm{2}}}{\:\sqrt{\mathrm{2}}}\mathrm{sin}\:{x}+\frac{\sqrt{\mathrm{2}}}{\:\sqrt{\mathrm{2}}}\mathrm{cos}\:{x} \\ $$$${y}=\sqrt{\mathrm{2}}\left(\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\mathrm{sin}\:{x}+\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\mathrm{cos}\:{x}\right) \\ $$$${y}=\sqrt{\mathrm{2}}\left(\mathrm{cos}\:\frac{\pi}{\mathrm{4}}\mathrm{sin}\:{x}+\mathrm{sin}\:\frac{\pi}{\mathrm{4}}\mathrm{cos}\:{x}\right) \\…
Question Number 65745 by KanhAshish last updated on 03/Aug/19 Commented by KanhAshish last updated on 03/Aug/19 $$\mathrm{15}\:\mathrm{and}\:\mathrm{16}\:\mathrm{both}\:\mathrm{solution}?? \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 208 by 02@>@0 last updated on 25/Jan/15 $$ \\ $$ Answered by 123456 last updated on 16/Dec/14 $$\boldsymbol{\mathrm{R}}\mathrm{andom}\:\boldsymbol{\mathrm{things}}\:\mathbb{L}\mathscr{O}\mathfrak{l}\:\mathcal{I} \\ $$$$\mathrm{lets}\:\mathrm{f}:\left[\mathrm{0}\mid\mathrm{1}\right]\rightarrow\mathbb{R}\:\mathrm{be}\:\mathrm{a}\:\mathrm{integable}\:\mathrm{and}\:\mathrm{continuos}\:\mathrm{function} \\ $$$$\mathrm{define}\:\parallel{f}\parallel\:\mathrm{be}\:\left[\mathrm{0}\mid\mathrm{1}\right]\rightarrow\mathbb{R}^{+} \:\mathrm{where}…
Question Number 65743 by aliesam last updated on 03/Aug/19 Commented by ~ À ® @ 237 ~ last updated on 04/Aug/19 $$\:\: \\ $$$${On}\:{a} \\…
Question Number 65740 by rajesh4661kumar@gmail.com last updated on 03/Aug/19 Commented by mathmax by abdo last updated on 03/Aug/19 $${let}\:{A}\:=\:\int\:\:\:\frac{{dx}}{\frac{\mathrm{1}}{{cosx}}\:+{sinx}}\:\Rightarrow\:{A}\:=\int\:\frac{{cosx}}{\mathrm{1}+{cosx}\:{sinx}}{dx}\:{changement} \\ $$$${tan}\left(\frac{{x}}{\mathrm{2}\:}\right)\:={t}\:{give}\:{A}\:=\int\:\:\:\frac{\frac{\mathrm{1}−{t}^{\mathrm{2}} }{\mathrm{1}+{t}^{\mathrm{2}} }}{\mathrm{1}+\frac{\mathrm{2}{t}\left(\mathrm{1}−{t}^{\mathrm{2}} \right)}{\left(\mathrm{1}+{t}^{\mathrm{2}} \right)^{\mathrm{2}}…
Question Number 204 by 02@>@0 last updated on 25/Jan/15 $${x}^{\mathrm{2}} +\left({y}−\sqrt[{\mathrm{3}}]{{x}^{\mathrm{2}} }\right)^{\mathrm{2}} =\mathrm{1} \\ $$ Commented by 02@>@0 last updated on 15/Dec/14 $$ \\ $$…
Question Number 203 by 02@>@0 last updated on 25/Jan/15 $$\frac{\mathrm{7}}{\mathrm{20}}+\frac{\mathrm{9}}{\mathrm{20}} \\ $$ Answered by 123456 last updated on 15/Dec/14 $$\frac{\mathrm{16}}{\mathrm{20}}=\frac{\mathrm{8}}{\mathrm{10}}=\frac{\mathrm{4}}{\mathrm{5}} \\ $$ Terms of Service…
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Question Number 202 by 02@>@0 last updated on 25/Jan/15 $${x}^{\mathrm{2}} −\mathrm{8}{xy}+\mathrm{17}{y}^{\mathrm{2}} \geqslant\mathrm{0} \\ $$ Answered by prakash jain last updated on 16/Dec/14 $${x}^{\mathrm{2}} −\mathrm{8}{xy}+\mathrm{17}{y}^{\mathrm{2}} \\…