Question Number 65664 by mathmax by abdo last updated on 01/Aug/19 $${solve}\:\frac{\sqrt{\mathrm{1}−{x}}−\sqrt{\mathrm{2}{x}+\mathrm{1}}}{\:\sqrt{\mathrm{1}−{x}}+\sqrt{\mathrm{2}{x}+\mathrm{1}}}\:=\frac{{x}+\mathrm{1}}{\mathrm{3}} \\ $$ Answered by MJS last updated on 01/Aug/19 $$\frac{\sqrt{\mathrm{1}−{x}}−\sqrt{\mathrm{2}{x}+\mathrm{1}}}{\:\sqrt{\mathrm{1}−{x}}+\sqrt{\mathrm{2}{x}+\mathrm{1}}}=\frac{\left(\sqrt{\mathrm{1}−{x}}−\sqrt{\mathrm{2}{x}+\mathrm{1}}\right)^{\mathrm{2}} }{\left(\sqrt{\mathrm{1}−{x}}+\sqrt{\mathrm{2}{x}+\mathrm{1}}\right)\left(\sqrt{\mathrm{1}−{x}}−\sqrt{\mathrm{2}{x}+\mathrm{1}}\right)}= \\ $$$$=\frac{{x}+\mathrm{2}−\mathrm{2}\sqrt{\mathrm{1}−{x}}\sqrt{\mathrm{2}{x}+\mathrm{1}}}{−\mathrm{3}{x}}=−\frac{{x}+\mathrm{2}}{\mathrm{3}{x}}+\frac{\mathrm{2}\sqrt{\mathrm{1}−{x}}\sqrt{\mathrm{2}{x}+\mathrm{1}}}{\mathrm{3}{x}}…
Question Number 129 by anoopsingh7374@gmail.com last updated on 25/Jan/15 $$\mathrm{3}{x}.\mathrm{6}{x}.\mathrm{7}{x}= \\ $$ Answered by rajabhay last updated on 07/Dec/14 $$\mathrm{3}{x}\centerdot\mathrm{6}{x}\centerdot\mathrm{7}{x}=\mathrm{126}{x}^{\mathrm{3}} \\ $$ Terms of Service…
Question Number 131202 by abdurehime last updated on 02/Feb/21 $$\mathrm{1}\:\:\:\:\:\:\:\:\mathrm{lim}_{\mathrm{n}\rightarrow\infty} \left(\frac{\mathrm{3}^{\mathrm{n}} +\mathrm{2}^{\mathrm{n}} }{\mathrm{6}^{\mathrm{n}} }\right)\:\mathrm{and} \\ $$$$\:\:\:\overset{\:\mathrm{lim}\:\underset{\mathrm{n}\rightarrow\infty} {\:}\left(\frac{\mathrm{1}+\mathrm{2}^{\mathrm{2}} +\mathrm{32}+\mathrm{4}^{\mathrm{2}} +…….+\mathrm{n}^{\mathrm{2}} }{\mathrm{n}^{\mathrm{3}} }\right)} {\:} \\ $$$$\mathrm{help}\:\mathrm{me} \\…
Question Number 65665 by mathmax by abdo last updated on 01/Aug/19 $${calculate}\:\int_{−\mathrm{2}} ^{+\infty} \:\:\frac{{e}^{−{x}} }{\:\sqrt{{x}+\mathrm{2}}}\:{dx} \\ $$$$ \\ $$ Commented by mathmax by abdo last…
Question Number 131196 by john_santu last updated on 02/Feb/21 $$\:{The}\:{minimum}\:{value}\:{of}\:{the}\: \\ $$$${expression}\:{B}\:=\:\mid{z}\mid^{\mathrm{2}} +\mid{z}−\mathrm{3}\mid^{\mathrm{2}} +\mid{z}−\mathrm{6}{i}\mid^{\mathrm{2}} \\ $$$${is}\:{p}.\:{What}\:{the}\:{value}\:{of}\:\frac{{p}}{\mathrm{10}}\:.? \\ $$ Answered by liberty last updated on 02/Feb/21…
Question Number 131199 by aurpeyz last updated on 02/Feb/21 Answered by physicstutes last updated on 02/Feb/21 $$\boldsymbol{\mathrm{Example}}\:\mathrm{4} \\ $$$${Q}_{\mathrm{1}} \:=\:\mathrm{2}.\mathrm{0}\:\mu\mathrm{C}\:\mathrm{and}\:{Q}_{\mathrm{2}} \:=\:−\mathrm{4}.\mathrm{0}\:\mu\mathrm{C},\:{R}\:=\:\mathrm{50}\:\mathrm{cm} \\ $$$$\mathrm{the}\:\mathrm{neutral}\:\mathrm{point}\:\mathrm{lies}\:\mathrm{a}\:\mathrm{distance}\:\mathrm{of}\:{x}\:\mathrm{from}\:{Q}_{\mathrm{1}} \:\mathrm{and}\:\left(\mathrm{0}.\mathrm{5}−{x}\right)\:\mathrm{m}\:\mathrm{from}\:{Q}_{\mathrm{2}} \\…
Question Number 125 by novrya last updated on 25/Jan/15 $${If}\:{y}\:=\:{ln}\left(\frac{{cos}\:{x}\:+\:{sin}\:{x}}{{cos}\:{x}\:−\:{sin}\:{x}}\right)\:{then}\:\frac{{dy}}{{dx}}=…. \\ $$ Answered by sushmitak last updated on 07/Dec/14 $$\mathrm{Applying}\:\mathrm{chain}\:\mathrm{rule}\:\mathrm{and}\:\mathrm{quotient}\:\mathrm{rule}\: \\ $$$$\mathrm{for}\:\mathrm{the}\:\mathrm{cases}\:\mathrm{when}\:\mathrm{cos}\:{x}−\mathrm{sin}\:{x}\:\neq\mathrm{0}\:\mathrm{and} \\ $$$$\frac{\mathrm{cos}\:{x}+\mathrm{sin}\:{x}}{\mathrm{cos}\:{x}−\mathrm{sin}\:{x}}>\mathrm{0}. \\…
Question Number 124 by novrya last updated on 25/Jan/15 $${If}\:{C}\:{is}\:{circle}\:\mid{z}\mid=\mathrm{1}.\:{Then}\:{the}\:{value}\:{of} \\ $$$$\underset{{C}} {\int}\:\frac{{cos}\:{z}}{{sin}\:{z}}\:{dz}\:=…. \\ $$ Commented by 123456 last updated on 13/Dec/14 $$\mathrm{o}\:\mathrm{teorema}\:\mathrm{dos}\:\mathrm{residuos}\:\mathrm{seria}\:\mathrm{bem}\:\mathrm{util}\:\mathrm{aqui}. \\ $$$$\mathrm{note}\:\mathrm{que}\:\mathrm{no}\:\mathrm{interior}\:\mathrm{do}\:\mathrm{contorno}\:\mathrm{C}\:\mathrm{so}\:\mathrm{a}\:\mathrm{um}\:\mathrm{polo}\:\mathrm{simples}\left(\mathrm{z}=\mathrm{0}\right)…
Question Number 123 by novrya last updated on 25/Jan/15 $${Solve}\:{the}\:{differential}\:{equation}: \\ $$$$\frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }−\mathrm{2}\frac{{dy}}{{dx}}+{y}={e}^{\mathrm{4}{x}} \\ $$ Answered by sudhanshur last updated on 07/Dec/14 $$\mathrm{Let}\:{y}={Ae}^{\mathrm{4}{x}} \:…
Question Number 131194 by john_santu last updated on 02/Feb/21 $$\:\mathrm{6}{y}^{\mathrm{3}} \:{dx}\:+\:\mathrm{2}{x}\:{dy}\:=\:\left({x}+\mathrm{1}\right)\:{dx}\: \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com