Menu Close

Author: Tinku Tara

b-

Question Number 194756 by horsebrand11 last updated on 15/Jul/23 $$\:\:\:\:\:\:\underbrace{\boldsymbol{{b}}} \\ $$ Answered by cortano12 last updated on 15/Jul/23 $$\:\:\frac{\mathrm{x}−\mathrm{a}}{\:\sqrt{\mathrm{x}}+\sqrt{\mathrm{a}}}\:=\:\frac{\mathrm{x}−\mathrm{a}}{\mathrm{3}\left(\sqrt{\mathrm{x}}+\sqrt{\mathrm{a}}\right)}\:+\mathrm{2}\sqrt{\mathrm{a}} \\ $$$$\:\frac{\mathrm{3}\left(\mathrm{x}−\mathrm{a}\right)}{\mathrm{3}\left(\sqrt{\mathrm{x}}+\sqrt{\mathrm{a}}\right)}−\frac{\left(\mathrm{x}−\mathrm{a}\right)}{\mathrm{3}\left(\sqrt{\mathrm{x}}+\sqrt{\mathrm{a}}\right)}\:=\:\mathrm{2}\sqrt{\mathrm{a}} \\ $$$$\:\:\frac{\mathrm{2}\left(\mathrm{x}−\mathrm{a}\right)}{\mathrm{3}\left(\sqrt{\mathrm{x}}+\sqrt{\mathrm{a}}\right)}\:=\:\mathrm{2}\sqrt{\mathrm{a}} \\…

x-

Question Number 194791 by dimentri last updated on 15/Jul/23 $$\:\:\:\underline{\underbrace{\boldsymbol{{x}}}} \\ $$ Answered by Frix last updated on 15/Jul/23 $$\mathrm{If}\:\sqrt[{\mathrm{7}}]{−{r}}=−\sqrt[{\mathrm{7}}]{{r}} \\ $$$$\frac{{x}^{\mathrm{2}} −\mathrm{2}}{\mathrm{2}{x}^{\mathrm{2}} }\sqrt[{\mathrm{7}}]{{x}−\sqrt{\mathrm{2}}}=\frac{{x}^{\frac{\mathrm{9}}{\mathrm{7}}} }{\mathrm{2}\sqrt[{\mathrm{7}}]{{x}+\sqrt{\mathrm{2}}}}…

Question-194790

Question Number 194790 by BagusSetyoWibowo last updated on 15/Jul/23 Answered by Frix last updated on 15/Jul/23 $$\mathrm{Where}'\mathrm{s}\:\mathrm{the}\:\mathrm{problem}? \\ $$$${ab}^{{x}+{c}} ={d}\:\Rightarrow\:{x}=\frac{\mathrm{ln}\:\frac{{d}}{{a}}}{\mathrm{ln}\:{b}}−{c} \\ $$$${x}=\frac{\mathrm{ln}\:\frac{\mathrm{cos}\:\mathrm{54}\:\left(\mathrm{log}_{\mathrm{5}} \:\mathrm{60}\:+\frac{\tau}{\mathrm{60}}+\mathrm{sin}\:\left(\mathrm{8}+\mathrm{cot}\:\mathrm{67}\right)\:+\mathrm{4}^{\mathrm{2}} \right)}{\mathrm{2}}}{\mathrm{ln}\:\mathrm{50}}−\pi \\…

let-p-be-a-prime-number-amp-let-a-1-a-2-a-3-a-p-be-integers-show-that-there-exists-an-integer-k-such-that-the-numbers-a-1-k-a-2-k-a-3-k-a-p-k-produce-at-least-1-2-p-distinct-

Question Number 194710 by York12 last updated on 14/Jul/23 $${let}\:{p}\:{be}\:{a}\:{prime}\:{number} \\ $$$$\&\:{let}\:{a}_{\mathrm{1}} \:,{a}_{\mathrm{2}} ,{a}_{\mathrm{3}} ,…,{a}_{{p}\:} {be}\:{integers} \\ $$$${show}\:{that}\:,\:{there}\:{exists}\:{an}\:{integer}\:{k}\:{such}\:{that}\:{the}\:{numbers} \\ $$$${a}_{\mathrm{1}} +{k},\:{a}_{\mathrm{2}} +{k},{a}_{\mathrm{3}} +{k},….,{a}_{{p}} +{k} \\…