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Author: Tinku Tara

Evaluate-tan-d-

Question Number 120 by novrya last updated on 25/Jan/15 $${Evaluate}\:\int{tan}\:\theta\:{d}\theta \\ $$ Answered by ssahoo last updated on 06/Dec/14 $$\int\mathrm{tan}\:\theta\:\:{d}\theta \\ $$$$=\int\frac{\mathrm{sin}\:\theta}{\mathrm{cos}\:\theta}{d}\theta \\ $$$$\mathrm{substituting}\:\mathrm{cos}\:\theta={y} \\…

Evaluate-tan-d-

Question Number 119 by novrya last updated on 25/Jan/15 $${Evaluate}\:\int\sqrt{{tan}\:\theta}\:{d}\theta \\ $$ Answered by rajabhay last updated on 06/Dec/14 $$\mathrm{tan}\:\theta={t}^{\mathrm{2}} \\ $$$$\mathrm{sec}^{\mathrm{2}} \theta\:{d}\theta=\mathrm{2}{t}\:{dt},\:\mathrm{sec}^{\mathrm{2}} \theta=\mathrm{1}+{t}^{\mathrm{4}} \\…

find-the-point-on-the-graph-of-f-x-1-x-2-that-are-closest-to-O-0-0-

Question Number 131188 by abdurehime last updated on 02/Feb/21 $$\mathrm{find}\:\mathrm{the}\:\mathrm{point}\:\mathrm{on}\:\mathrm{the}\:\mathrm{graph}\:\mathrm{of}\:\mathrm{f}\left(\mathrm{x}\right)=\mathrm{1}−\mathrm{x}^{\mathrm{2}} \\ $$$$\mathrm{that}\:\mathrm{are}\:\mathrm{closest}\:\mathrm{to}\:\mathrm{O}\left(\mathrm{0},\mathrm{0}\right) \\ $$ Answered by john_santu last updated on 02/Feb/21 $${let}\:{P}\left({x},{y}\right)\:{is}\:{the}\:{point}\:{on}\:{the} \\ $$$${curve}.\: \\…

Question-65651

Question Number 65651 by Masumsiddiqui399@gmail.com last updated on 01/Aug/19 Commented by Prithwish sen last updated on 01/Aug/19 $$\left(\mathrm{x}−\mathrm{1}\right)^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} =\mathrm{0}\:\Rightarrow\mathrm{x}−\mathrm{1}=\mathrm{0}\:\mathrm{and}\:\mathrm{y}=\mathrm{0} \\ $$$$\therefore\mathrm{x}^{\mathrm{3}} +\mathrm{y}^{\mathrm{3}} =\mathrm{1} \\…

lim-x-0-1-x-tan-pi-2-x-

Question Number 131181 by john_santu last updated on 02/Feb/21 $$\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left(\frac{\mathrm{1}}{{x}}\:−\:\mathrm{tan}\:\left(\frac{\pi}{\mathrm{2}}−{x}\right)\right)=? \\ $$ Answered by Ar Brandon last updated on 02/Feb/21 $$\mathscr{L}=\underset{\mathrm{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left(\frac{\mathrm{1}}{{x}}\:−\:\mathrm{tan}\:\left(\frac{\pi}{\mathrm{2}}−{x}\right)\right)=\underset{\mathrm{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left(\frac{\mathrm{1}}{\mathrm{x}}−\mathrm{cotx}\right) \\…

Question-131183

Question Number 131183 by john_santu last updated on 02/Feb/21 Answered by liberty last updated on 02/Feb/21 $$\:\frac{\mathrm{dP}}{\left(\mathrm{32}−\mathrm{P}\right)\mathrm{P}}\:=\:\mathrm{0}.\mathrm{0015}\:\mathrm{dt}\: \\ $$$$\frac{\mathrm{1}}{\mathrm{32}}\:\int\:\left[\:\frac{\mathrm{1}}{\mathrm{32}−\mathrm{P}}\:+\frac{\mathrm{1}}{\mathrm{P}}\:\right]\mathrm{dP}\:=\:\int\mathrm{0}.\mathrm{0015}\:\mathrm{dt} \\ $$$$\frac{\mathrm{1}}{\mathrm{32}}\:\mathrm{ln}\:\mid\frac{\mathrm{P}}{\mathrm{32}−\mathrm{P}}\:\mid\:=\:\mathrm{0}.\mathrm{0015t}\:+\:\mathrm{c}\: \\ $$$$\mathrm{ln}\:\mid\frac{\mathrm{P}}{\mathrm{32}−\mathrm{P}}\mid\:=\:\mathrm{0}.\mathrm{48t}+\mathrm{C}\:;\:\frac{\mathrm{P}\left(\mathrm{t}\right)}{\mathrm{32}−\mathrm{P}\left(\mathrm{t}\right)}\:=\:\lambda\mathrm{e}^{\mathrm{0}.\mathrm{048t}} \\ $$$$\Leftrightarrow\:\frac{\mathrm{32}−\mathrm{P}\left(\mathrm{t}\right)}{\mathrm{P}\left(\mathrm{t}\right)}\:=\:\frac{\mathrm{1}}{\lambda}\mathrm{e}^{−\mathrm{0}.\mathrm{048t}}…