Question Number 13012 by tawa tawa last updated on 10/May/17 $${Sir}.\:{MRV}\:\:{please}\:\mathrm{i}\:\mathrm{need}\:{the}\:\mathrm{cubic}\:\mathrm{equation}\:\mathrm{formular}.\:\:\mathrm{my}\:\mathrm{phone}\:\mathrm{has}\:\mathrm{fault} \\ $$$$\mathrm{and}\:\mathrm{i}\:\mathrm{just}\:\mathrm{restore}\:\mathrm{it}.\:\mathrm{please}\:\mathrm{help}\:\mathrm{me}\:\mathrm{re}\:\mathrm{send}\:\mathrm{it}.\:\mathrm{i}\:\mathrm{really}\:\mathrm{appreciate}\:\mathrm{your}\:\mathrm{effort} \\ $$$$\mathrm{sir}.\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$ Commented by mrW1 last updated on 10/May/17 Commented…
Question Number 13011 by sandy_suhendra last updated on 10/May/17 $$\mathrm{li}\underset{\mathrm{x}\rightarrow\infty} {\mathrm{m}}\left[\mathrm{5}^{\mathrm{x}} \:+\:\mathrm{5}^{\mathrm{3x}} \right]^{\frac{\mathrm{1}}{\mathrm{x}}} \:=\:? \\ $$$$\mathrm{please}\:\mathrm{help} \\ $$ Answered by sma3l2996 last updated on 10/May/17…
Question Number 13010 by tawa tawa last updated on 10/May/17 Answered by sandy_suhendra last updated on 10/May/17 $$\mathrm{BC}\:=\:\sqrt{\mathrm{5}^{\mathrm{2}} −\left(\mathrm{7}−\mathrm{4}\right)^{\mathrm{2}} }\:=\:\mathrm{4}\:\mathrm{cm} \\ $$$$\mathrm{let}\:\mathrm{A}_{\mathrm{ABCD}} \:=\:\mathrm{area}\:\mathrm{of}\:\mathrm{ABCD} \\ $$$$\mathrm{and}\:\mathrm{P}_{\mathrm{ABCD}}…
Question Number 144083 by mathdanisur last updated on 21/Jun/21 $${if}\:\:{a};{b};{c}>\mathrm{0}\:\:{then}: \\ $$$$\frac{\mathrm{9}{abc}}{{a}^{\mathrm{3}} \:+\:{b}^{\mathrm{3}} \:+\:{c}^{\mathrm{3}} }\:+\:\frac{{a}^{\mathrm{2}} }{{bc}}\:+\:\frac{{b}^{\mathrm{2}} }{{ca}}\:+\:\frac{{c}^{\mathrm{2}} }{{ab}}\:\geqslant\:\mathrm{6} \\ $$ Answered by mitica last updated…
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Question Number 13005 by 1630321995 last updated on 10/May/17 $${using}\:{De}\:{Moivre}\:{theorem}\:{solve}\:{the}\:{equation}\:\left({x}+\mathrm{1}\right)^{\mathrm{5}} +\left({x}−\mathrm{1}\right)^{\mathrm{5}} =\mathrm{0} \\ $$ Answered by mrW1 last updated on 10/May/17 $$\left({x}+\mathrm{1}\right)^{\mathrm{5}} −\left(\mathrm{1}−{x}\right)^{\mathrm{5}} =\mathrm{0} \\…
Question Number 13004 by Nayon last updated on 10/May/17 $${If}\:\int{f}\left({x}\right){dx}={g}\left({x}\right)\:,{then}\:{why} \\ $$$$\int_{{b}} ^{{a}} {f}\left({x}\right){dx}={g}\left({a}\right)−{g}\left({b}\right)??? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 144072 by bobhans last updated on 21/Jun/21 $$\mathrm{Use}\:\mathrm{the}\:\mathrm{reduction}\:\mathrm{formula}\:\mathrm{to} \\ $$$$\mathrm{rewrite}\:−\mathrm{3}\:\mathrm{sin}\:\mathrm{x}\:−\mathrm{3}\:\mathrm{cos}\:\mathrm{x}\:\mathrm{in}\:\mathrm{the} \\ $$$$\mathrm{form}\:\mathrm{K}\:\mathrm{sin}\:\left(\mathrm{x}+\alpha\right)\:. \\ $$ Answered by liberty last updated on 21/Jun/21 $$\mathrm{because}\:\begin{cases}{\mathrm{a}=−\mathrm{3}}\\{\mathrm{b}=−\mathrm{3}}\end{cases}\:\mathrm{we}\:\mathrm{have}\:\mathrm{K}=\sqrt{\mathrm{a}^{\mathrm{2}} +\mathrm{b}^{\mathrm{2}}…
Question Number 13002 by Joel577 last updated on 10/May/17 $$\mathrm{3}^{\left({x}\:−\:\mathrm{3}\right)\left({x}\:−\:{y}\:−\:\mathrm{2}\right)} \:=\:\mathrm{1} \\ $$$$\mathrm{5}^{\left({x}^{\mathrm{2}} \:−\:\mathrm{2}{xy}\:+\:{y}^{\mathrm{2}} \:+\:{x}\:−\:{y}\:−\:\mathrm{3}/\mathrm{2}\right)} \:=\:\sqrt{\mathrm{5}} \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:{x}\:\mathrm{and}\:{y} \\ $$ Answered by 433 last updated…
Question Number 144074 by bobhans last updated on 21/Jun/21 $$\:\mathrm{The}\:\mathrm{parallelogram}\:\mathrm{ABCD}\:\mathrm{has} \\ $$$$\mid\mid\mathrm{AB}\mid\mid\:=\mathrm{6},\:\mid\mid\mathrm{AC}\mid\mid=\mathrm{7}\:\&\:\mathrm{d}\left(\mathrm{D},\mathrm{AC}\right)=\mathrm{2} \\ $$$$\mathrm{Find}\:\mathrm{d}\left(\mathrm{D},\mathrm{AB}\right). \\ $$ Answered by liberty last updated on 21/Jun/21 $$\mathrm{Area}_{\Delta\mathrm{ADC}} \:=\:\frac{\mathrm{2}×\mathrm{7}}{\mathrm{2}}=\mathrm{7}…