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Question Number 12946 by 433 last updated on 07/May/17 $${a}_{{n}} =\sqrt{\mathrm{3}{a}_{{n}−\mathrm{1}} +\mathrm{2}}\:\:\:{a}_{\mathrm{1}} =\mathrm{1} \\ $$$$\underset{{n}\rightarrow\infty} {\mathrm{lim}}{a}_{{n}} =? \\ $$ Answered by ajfour last updated on…
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Question Number 144007 by gsk2684 last updated on 20/Jun/21 $$\mathrm{find}\:\mathrm{maximum}\:\mathrm{of}\:\mathrm{x}\:\mathrm{cosec}\:\mathrm{x} \\ $$$$\mathrm{if}\:\mathrm{0}<\mathrm{x}<\frac{\Pi}{\mathrm{6}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 78468 by Dah Solu Tion last updated on 17/Jan/20 $${If}\:{F}\left({x}\right)\:=\:\int_{\mathrm{0}} ^{{arctanx}} \sqrt{\frac{{t}^{\mathrm{4}} −\mathrm{1}}{{t}^{\mathrm{4}} +\mathrm{1}}{dt},}\:{find}\:{F}'\left({x}\right). \\ $$ Commented by mathmax by abdo last updated…
Question Number 12933 by chux last updated on 07/May/17 Commented by ajfour last updated on 08/May/17 $${Touch}\:{and}\:{Draw} \\ $$ Commented by chux last updated on…
Question Number 144006 by gsk2684 last updated on 20/Jun/21 $$\mathrm{find}\:\mathrm{minimum}\:\mathrm{value}\:\mathrm{of}\:\mathrm{sec}\:\mathrm{2A}+\mathrm{sec}\:\mathrm{2B} \\ $$$$\mathrm{where}\:\mathrm{A}+\mathrm{B}\:\mathrm{is}\:\mathrm{constant}\:\mathrm{and} \\ $$$$\mathrm{A},\mathrm{B}\in\left(\mathrm{o}\:\frac{\Pi}{\mathrm{4}}\right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 144001 by mnjuly1970 last updated on 20/Jun/21 Answered by Dwaipayan Shikari last updated on 20/Jun/21 $$\left(\mathrm{1}+\frac{\mathrm{1}}{{n}}\right)^{\frac{\mathrm{1}}{\mathrm{1}}} \left(\mathrm{1}+\frac{\mathrm{2}}{{n}}\right)^{\frac{\mathrm{1}}{\mathrm{2}}} \left(\mathrm{1}+\frac{\mathrm{3}}{{n}}\right)^{\frac{\mathrm{1}}{\mathrm{3}}} …={y} \\ $$$$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\frac{\mathrm{1}}{{n}}\underset{{k}=\mathrm{1}} {\overset{{n}}…
Question Number 144000 by bluberry508 last updated on 20/Jun/21 $$\mathrm{prove}\:\mathrm{that}\: \\ $$$$ \\ $$$$\forall_{{m}} \in\mathbb{N}\:,\:{a}_{{k}} ,{b}_{{k}} \in\mathbb{R} \\ $$$$\mathrm{cos}\:^{\mathrm{2}{m}} {x}\:=\underset{{k}=\mathrm{1}} {\overset{{m}} {\sum}}{a}_{{k}} \mathrm{cos}\:\mathrm{2}{kx} \\ $$$$\mathrm{cos}\:^{\mathrm{2}{m}−\mathrm{1}}…