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Author: Tinku Tara

Question-78465

Question Number 78465 by TawaTawa last updated on 17/Jan/20 Answered by mind is power last updated on 17/Jan/20 $$\zeta\left(\mathrm{z}\right)=\underset{\mathrm{n}\geqslant\mathrm{1}} {\sum}\frac{\mathrm{1}}{\mathrm{n}^{\mathrm{z}} } \\ $$$$\mathrm{Re}\left(\zeta\left(\mathrm{z}\right)\right)=\mathrm{Re}\left\{\underset{\mathrm{n}\geqslant\mathrm{1}} {\sum}\frac{\mathrm{1}}{\mathrm{n}^{\mathrm{Re}\left(\mathrm{z}\right)+\mathrm{iIm}\left(\mathrm{z}\right)} }\right\}…

Question-12928

Question Number 12928 by tawa last updated on 07/May/17 Answered by sandy_suhendra last updated on 09/May/17 $$\mathrm{cosine}\:\mathrm{rule}\:\mathrm{in}\:\Delta\mathrm{ABC}\:: \\ $$$$\mathrm{x}^{\mathrm{2}} =\mathrm{d}^{\mathrm{2}} +\mathrm{d}^{\mathrm{2}} −\mathrm{2d}.\mathrm{d}.\mathrm{cos}\left(\mathrm{180}−\mathrm{2}\theta\right) \\ $$$$\mathrm{x}^{\mathrm{2}} =\mathrm{2d}^{\mathrm{2}}…

The-maximum-value-of-y-x-3-2-x-2-2-2-x-2-x-2-1-2-is-A-10-C-4-B-2-5-D-10-

Question Number 143997 by liberty last updated on 20/Jun/21 $$\:{The}\:{maximum}\:{value}\:{of}\: \\ $$$${y}\:=\:\sqrt{\left({x}−\mathrm{3}\right)^{\mathrm{2}} +\left({x}^{\mathrm{2}} −\mathrm{2}\right)^{\mathrm{2}} }−\sqrt{{x}^{\mathrm{2}} +\left({x}^{\mathrm{2}} −\mathrm{1}\right)^{\mathrm{2}} } \\ $$$${is}\:\left({A}\right)\:\sqrt{\mathrm{10}}\:\:\:\:\:\:\:\left({C}\right)\:\mathrm{4}\: \\ $$$$\:\:\:\:\:\:\left({B}\right)\:\mathrm{2}\sqrt{\mathrm{5}}\:\:\:\:\:\left({D}\right)\:\mathrm{10}\: \\ $$ Answered…

cos-1-n-

Question Number 12927 by satish1992.mishra@gmail.com last updated on 07/May/17 $$\Sigma\mathrm{cos}\:\left(\frac{\mathrm{1}}{{n}}\right) \\ $$ Commented by prakash jain last updated on 07/May/17 $${n}\:{from}\:\mathrm{0}\:{to}\:\infty? \\ $$$$\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\mathrm{cos}\:\left(\frac{\mathrm{1}}{{n}}\right)?…

lim-x-pi-4-pi-4x-1-sin-2x-

Question Number 143995 by liberty last updated on 20/Jun/21 $$\:\:\underset{{x}\rightarrow\pi/\mathrm{4}} {\mathrm{lim}}\frac{\pi−\mathrm{4}{x}}{\:\sqrt{\mathrm{1}−\sqrt{\mathrm{sin}\:\mathrm{2}{x}}}}\:=? \\ $$ Answered by mathmax by abdo last updated on 20/Jun/21 $$\mathrm{f}\left(\mathrm{x}\right)=\frac{\pi−\mathrm{4x}}{\:\sqrt{\mathrm{1}−\sqrt{\mathrm{sin2x}}}}\:\Rightarrow\mathrm{f}\left(\mathrm{x}\right)=_{\frac{\pi}{\mathrm{4}}−\mathrm{x}=\mathrm{t}} \:\:\:\frac{\pi−\mathrm{4}\left(\frac{\pi}{\mathrm{4}}−\mathrm{t}\right)}{\:\sqrt{\mathrm{1}−\sqrt{\mathrm{sin}\left(\mathrm{2}\left(\frac{\pi}{\mathrm{4}}−\mathrm{t}\right)\right.}}} \\…