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Author: Tinku Tara

prove-by-contradiction-9-13-3-is-irrational-

Question Number 12822 by fawadalamawan@gmail.com last updated on 02/May/17 $${prove}\:{by}\:{contradiction}\:\mathrm{9}+\mathrm{13}\sqrt{\mathrm{3}\:} \\ $$$${is}\:{irrational} \\ $$ Answered by mrW1 last updated on 03/May/17 $${let}\:{us}\:{assume}\:\mathrm{9}+\mathrm{13}\sqrt{\mathrm{3}}\:{is}\:{rational},.{i}.{e}. \\ $$$${there}\:{exist}\:{integer}\:{numbers}\:{a}\:{and}\:{b},\:{b}\neq\mathrm{0}, \\…

Show-that-1-6x-1-1-6x-1-3x-1-1-3x-4-6x-Ignoring-higher-power-of-x-in-the-expansion-

Question Number 78357 by TawaTawa last updated on 16/Jan/20 $$\mathrm{Show}\:\mathrm{that}:\:\:\:\frac{\sqrt{\mathrm{1}\:+\:\mathrm{6x}}\:\:−\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{1}\:−\:\mathrm{6x}}}}{\:\sqrt{\mathrm{1}\:+\:\mathrm{3x}}\:\:−\:\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{1}\:−\:\mathrm{3x}}}}\:\:\:\:\:=\:\:\:\mathrm{4}\:+\:\mathrm{6x} \\ $$$$\mathrm{Ignoring}\:\mathrm{higher}\:\mathrm{power}\:\mathrm{of}\:\:\mathrm{x}\:\:\mathrm{in}\:\mathrm{the}\:\mathrm{expansion} \\ $$ Commented by MJS last updated on 16/Jan/20 $$\mathrm{I}\:\mathrm{don}'\mathrm{t}\:\mathrm{understand}\:\mathrm{this}\:\mathrm{question} \\ $$$$\mathrm{the}\:\mathrm{left}\:\mathrm{handed}\:\mathrm{side}\:\mathrm{is}\:\mathrm{defined}\:\mathrm{for} \\…

Find-1-cos-2-x-1-tanx-2-dx-

Question Number 78352 by Khyati last updated on 16/Jan/20 $${Find}\:\int\frac{\mathrm{1}}{{cos}^{\mathrm{2}} {x}\left(\mathrm{1}−{tanx}\right)^{\mathrm{2}} }\:{dx} \\ $$ Commented by jagoll last updated on 17/Jan/20 $$\int\:\frac{\mathrm{sec}\:^{\mathrm{2}} {x}\:{dx}}{\left(\mathrm{1}−\mathrm{tan}\:{x}\right)^{\mathrm{2}} }\:=\:−\int\:\frac{{d}\left(\mathrm{1}−\mathrm{tan}\:{x}\right)}{\left(\mathrm{1}−\mathrm{tan}\:{x}\right)^{\mathrm{2}} }…

Let-a-b-c-R-and-a-b-b-c-1-where-0-lt-b-1-Prove-that-a-b-b-c-a-b-b-c-2-

Question Number 78351 by loveineq. last updated on 16/Jan/20 $$\mathrm{Let}\:\:{a},{b},{c}\:\in\:\mathrm{R}^{+} \:\:\mathrm{and}\:\:\left({a}+{b}\right)\left({b}+{c}\right)\:=\:\mathrm{1}\:,\:\mathrm{where}\:\:\mathrm{0}\:<{b}\leqslant\:\mathrm{1}\:. \\ $$$$\mathrm{Prove}\:\mathrm{that}\:\:\mid{a}−{b}\mid\mid{b}−{c}\mid\:\geqslant\:\frac{\mid\sqrt{{a}}−\sqrt{{b}}\mid\mid\sqrt{{b}}−\sqrt{{c}}\mid}{\mathrm{2}}\:. \\ $$ Commented by loveineq. last updated on 19/Jan/20 $$\mathrm{More}\:\mathrm{stronger}\:\mathrm{is}\:\:\mid{a}−{b}\mid\mid{b}−{c}\mid\:\geqslant\:\mid\sqrt{{a}}−\sqrt{{b}}\mid\mid\sqrt{{b}}−\sqrt{{c}}\mid\:. \\ $$…