Question Number 12814 by syambabu087@gmail.com last updated on 02/May/17 Commented by FilupS last updated on 02/May/17 $${x}\left({y}^{{n}} −{y}\right)+\frac{{dy}}{{dx}}=\mathrm{0} \\ $$$$\frac{{dy}}{{dx}}=−{x}\left({y}^{{n}} −{y}\right) \\ $$$$\frac{\mathrm{1}}{{y}^{{n}} −{y}}\:\frac{{dy}}{{dx}}=−{x} \\…
Question Number 12812 by tawa last updated on 01/May/17 Answered by sandy_suhendra last updated on 02/May/17 $$\left.\mathrm{1}\right)\:\mathrm{V}=\pi\mathrm{r}^{\mathrm{2}} \mathrm{t} \\ $$$$\:\:\:\:\:\mathrm{350}=\mathrm{3}.\mathrm{14}×\mathrm{r}^{\mathrm{2}} ×\mathrm{8}.\mathrm{5} \\ $$$$\:\:\:\:\:\mathrm{r}^{\mathrm{2}} =\mathrm{13}.\mathrm{11} \\…
Question Number 78342 by mhmd last updated on 16/Jan/20 $${sppose}\:{that}\:\left({R},+,.\right){be}\:{aring}\:{and}\:{we}\:{have}\:{the}\:{ring}\:\left({R}×{Z},+^{'\:} ,.^{'} \right)\:{prove}\:{that}\:\left({R}×\mathrm{0},+^{'} ,.'\right)\:{it}\:{was}\:{ideal}\:{in}\:\left({R}×{Z},+^{'} ,.^{'} \right) \\ $$$${and}\:{prove}\:\left(\mathrm{0}×{Z},+,.\right){be}\:{isomorphic}\:{in}\:\left({Z},+,.\right) \\ $$$${and}\:{if}\:{a}\in{R}\:{identity}\:{element}\:\left({a}^{\mathrm{2}} ={a}\right){prove}\:{that}\:\left(−{a},\mathrm{1}\right){be}\:{identity}\:{element}\:{in}\:{the}\:{ring}\:\left({R}×{Z},+^{'} ,.^{'} \right) \\ $$$${pleas}\:{sir}\:{help}\:{me}\:{am}\:{neding}\:{this}\:{pleas}? \\…
Question Number 78343 by balbayrak last updated on 16/Jan/20 Commented by MJS last updated on 16/Jan/20 $$\mathrm{syntax}\:\mathrm{error}.\:\mathrm{type}\:\mathrm{it}\:\mathrm{correctly}\:\mathrm{please} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 78340 by loveineq. last updated on 16/Jan/20 $$\mathrm{Let}\:\:{a},{b},{c}\:>\:\mathrm{0}\:\:\mathrm{and}\:\:{c}^{\mathrm{2}} \:=\:\frac{{ab}+{bc}+{ca}}{\mathrm{3}}\:.\:\mathrm{Prove}\:\mathrm{that} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\frac{{a}^{\mathrm{3}} +{b}^{\mathrm{3}} −\mathrm{2}{c}^{\mathrm{3}} }{{a}^{\mathrm{3}} +{b}^{\mathrm{3}} +{c}^{\mathrm{3}} }\:\leqslant\:\mathrm{3}\left(\frac{{a}^{\mathrm{2}} +{b}^{\mathrm{2}} −\mathrm{2}{c}^{\mathrm{2}} }{{a}^{\mathrm{2}} +{b}^{\mathrm{2}} +{c}^{\mathrm{2}} }\right)…
Question Number 143878 by akmalovna05 last updated on 19/Jun/21 $$\mathrm{y}'''=\mathrm{2xy}'' \\ $$ Answered by Ar Brandon last updated on 19/Jun/21 $$\mathrm{y}'''=\mathrm{2xy}''\Rightarrow\frac{\mathrm{y}'''}{\mathrm{y}''}=\mathrm{2x}\Rightarrow\mathrm{ln}\left(\mathrm{y}''\right)=\mathrm{x}^{\mathrm{2}} \Rightarrow\mathrm{y}''=\mathrm{e}^{\mathrm{x}^{\mathrm{2}} } \\ $$…
Question Number 12804 by b.e.h.i.8.3.4.1.7@gmail.com last updated on 01/May/17 Commented by tawa last updated on 01/May/17 Commented by tawa last updated on 01/May/17 Commented by…
Question Number 143875 by ajfour last updated on 19/Jun/21 Commented by ajfour last updated on 19/Jun/21 $${solve}\:{for}\:{m}\:{in}\:{terms}\:{of} \\ $$$${a},{b},{c},{d}. \\ $$ Terms of Service Privacy…
Question Number 12801 by tawa last updated on 01/May/17 Answered by sandy_suhendra last updated on 01/May/17 $$\left.\mathrm{1}\right)\:\mathrm{molar}\:\mathrm{gas}\:=\:\frac{\mathrm{2}.\mathrm{8}}{\mathrm{22}.\mathrm{4}}\:=\:\mathrm{0}.\mathrm{125}\:\mathrm{mol} \\ $$$$\mathrm{molar}\:\mathrm{mass}\:\mathrm{of}\:\mathrm{gas}\:=\:\frac{\mathrm{8}}{\mathrm{0}.\mathrm{125}}\:=\:\mathrm{64}\:\mathrm{gram}/\mathrm{mol} \\ $$$$\mathrm{vapour}\:\mathrm{density}\:=\:\frac{\mathrm{molar}\:\mathrm{mass}\:\mathrm{of}\:\mathrm{gas}}{\mathrm{molar}\:\mathrm{mass}\:\mathrm{of}\:\mathrm{H}_{\mathrm{2}} }\:=\:\frac{\mathrm{64}}{\mathrm{2}}\:=\mathrm{32}\:\:\:\:\: \\ $$$$\left.\mathrm{2}\right)\:\mathrm{Mg}\:+\:\mathrm{2HCl}\:\rightarrow\:\mathrm{MgCl}_{\mathrm{2}} \:+\:\mathrm{H}_{\mathrm{2}}…
Question Number 143874 by akmalovna05 last updated on 19/Jun/21 $$\mathrm{y}''−\mathrm{x}×\mathrm{y}'''+\mathrm{y}'''^{\mathrm{3}} =\mathrm{0} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com