Question Number 143863 by Khalmohmmad last updated on 19/Jun/21 Commented by justtry last updated on 19/Jun/21 $${log}\:\mathrm{10}=\mathrm{1} \\ $$$$….. \\ $$ Terms of Service Privacy…
Question Number 78324 by jagoll last updated on 16/Jan/20 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{1}+\mathrm{sin}\:\mathrm{4}{x}−\mathrm{cos}\:\mathrm{2}{x}}{\:\sqrt{{x}+\mathrm{1}}−\sqrt{\mathrm{1}−{x}}}= \\ $$ Commented by john santu last updated on 16/Jan/20 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\left(\sqrt{{x}+\mathrm{1}}+\sqrt{\mathrm{1}−{x}}\right)×\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{2sin}\:^{\mathrm{2}} {x}+\mathrm{2sin}\:\mathrm{2}{x}\mathrm{cos}\:\mathrm{2}{x}}{\mathrm{2}{x}}…
Question Number 78325 by jagoll last updated on 16/Jan/20 $$ \\ $$$$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\left(\frac{\mathrm{5}{x}^{\mathrm{2}} +\mathrm{3}{x}}{\mathrm{5}{x}^{\mathrm{2}} −\mathrm{2}{x}}\right)^{\mathrm{3}{x}−\mathrm{1}} \\ $$ Commented by john santu last updated on 16/Jan/20…
Question Number 143857 by gsk2684 last updated on 19/Jun/21 $$\mathrm{if}\:\mathrm{cos}^{\mathrm{4}} \theta\mathrm{sec}\:^{\mathrm{2}} \alpha,\:\frac{\mathrm{1}}{\mathrm{2}},\:\mathrm{sin}^{\mathrm{4}} \theta\mathrm{cosec}^{\mathrm{2}} \alpha\: \\ $$$$\mathrm{are}\:\mathrm{in}\:\mathrm{A}.\mathrm{P}.\:\mathrm{then} \\ $$$$\:\mathrm{cos}^{\mathrm{8}} \theta\mathrm{sec}^{\mathrm{6}} \alpha,\:\frac{\mathrm{1}}{\mathrm{2}},\:\mathrm{sin}^{\mathrm{8}} \theta\mathrm{cosec}^{\mathrm{6}} \alpha \\ $$$$\mathrm{are}\:\mathrm{in}\:\mathrm{which}\:\mathrm{progression}? \\…
Question Number 143856 by gsk2684 last updated on 19/Jun/21 $$\mathrm{if}\:\frac{\mathrm{cos}^{\mathrm{4}} \mathrm{x}}{\mathrm{cos}^{\mathrm{2}} \mathrm{y}}+\frac{\mathrm{sin}^{\mathrm{4}} \mathrm{x}}{\mathrm{sin}^{\mathrm{2}} \mathrm{y}}=\mathrm{1then}\:\mathrm{find}\: \\ $$$$\:\frac{\mathrm{cos}^{\mathrm{4}} \mathrm{y}}{\mathrm{cos}^{\mathrm{2}} \mathrm{x}}+\frac{\mathrm{sin}^{\mathrm{4}} \mathrm{y}}{\mathrm{sin}^{\mathrm{2}} \mathrm{x}} \\ $$ Commented by justtry…
Question Number 143858 by gsk2684 last updated on 19/Jun/21 $$\mathrm{if}\:\mathrm{A}\geqslant\mathrm{0},\:\mathrm{B}\geqslant\mathrm{0},\:\mathrm{A}+\mathrm{B}=\frac{\Pi}{\mathrm{3}}\:\mathrm{then} \\ $$$$\mathrm{find}\:\mathrm{minimum}\:\mathrm{and}\:\mathrm{maximum}\: \\ $$$$\mathrm{of}\:\mathrm{tan}\:\mathrm{A}.\mathrm{tan}\:\mathrm{B}\: \\ $$ Answered by ajfour last updated on 19/Jun/21 $$\sqrt{\mathrm{3}}=\frac{{p}+{q}}{\mathrm{1}−{pq}} \\…
Question Number 78319 by clarissagirl last updated on 16/Jan/20 $$\mathrm{57}+\mathrm{6}{h}=\mathrm{16}{h}−\mathrm{33} \\ $$ Commented by jagoll last updated on 16/Jan/20 $$\mathrm{10}{h}=\mathrm{90}\:\Rightarrow\:{h}=\mathrm{9} \\ $$ Terms of Service…
Question Number 78316 by mathocean1 last updated on 15/Jan/20 $$\mathrm{the}\:\mathrm{circle}\:\mathrm{represents}\:\mathrm{a}\:\mathrm{farm}\:\mathrm{where} \\ $$$$\left(\mathrm{LK}\right)\:\mathrm{is}\:\mathrm{symetric}\:\mathrm{axe}\:\mathrm{of}\:\mathrm{circle}\:\mathrm{such} \\ $$$$\mathrm{as}\:\forall\:\mathrm{M}\:\mathrm{of}\:\mathrm{this}\:\mathrm{circle}\:\mathrm{verifying} \\ $$$$\mathrm{ML}^{\mathrm{2}} −\mathrm{4MK}^{\mathrm{2}} =\mathrm{0}\:\:\mathrm{with}\:\mathrm{LK}=\mathrm{150m}. \\ $$$$\mathrm{calculate}\:\mathrm{the}\:\mathrm{radius}\:\mathrm{of}\:\mathrm{circle}. \\ $$$$\mathrm{please}\:\mathrm{help}\:\mathrm{me}… \\ $$ Commented…
Question Number 78314 by mfwajoel1 last updated on 15/Jan/20 $${resolve} \\ $$$$\left\{_{{logx}_{{y}} ={logy}_{{x}} } ^{{x}^{{y}} ={y}^{{x}} } \right. \\ $$ Commented by john santu last…
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